A plane figure is a closed, two-dimensional flat figure. It has only length and breadth but no thickness at all. Since it has two measurements only, it is two-dimensional. Plain figures only have vertices and sides, and owing to their two-dimensional properties, only their perimeter and area can be measured. You cannot measure their volume, which is reserved for 3-dimensional figures.

The Opposite Sides of a Rhomboid are Parallel.

Let's take a figure, where ABCD as a rhomboid. So hence, AB is parallel to DC, and AD is parallel to DC.

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The Opposite Sides of the Rhombus are Congruent as Well.

In the figure below, quadrilateral DABC is a rhomboid. In the rhomboid, DA = CB and DC = AB. So, opposite sides of the rhomboid are equal.

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The Diagonals of the Rhomboid Divide the Figure Into Two Congruent Triangles.

This is a property true of any parallelogram. In the figure below, ABCD is a rhomboid, with AC and BD as its diagonals meeting at point O. Hence Triangle ABC is congruent to Triangle ADC by SSS congruence test.

To prove it:

AB= DC (opposite sides of a rhomboid)

AD=BC (opposite sides of a rhomboid)

AC=AC (common side)

Hence proved.

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4. The Opposite Angles of a Rhomboid are Equal.

In the figure below, quadrilateral ADCB is a rhomboid. Here ∠ADC= ∠ABC and ∠DAB= ∠DCB. This is because the opposite angles of a rhomboid are always equal.

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5. The Sum of the Angles in a Rhomboid is Equal to 360 Degrees.

Owing to the angle sum property of a quadrilateral, the sum of all the angles in a rhomboid is equal to 360 degrees. In the figure below, ADCB is a rhomboid which is a quadrilateral. Hence the sum of all the angles ∠A+∠D+∠C+∠D= 360 degrees. A quadrilateral is a closed, 2-D shape which has 4 sides.

This can be verified because the Rhomboid consists of two congruent triangles whose interior angles will add up to 180 degrees each (since all interior angles of a triangle must add up to 180 degrees). Hence when you add the sum of the interior angles of both the triangles forming the quadrilateral (180+180), you can prove that the total measure is 360 degrees.

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1) Area of a rhomboid

Being a 2D figure, the area of the Rhomboid stands for the size of an area, i.e., space covered by the Rhomboid. To calculate the area of a Rhomboid, we first find the length of its base side and height(perpendicular).

We know that the diagonal divides the Rhomboid into two congruent triangles.

Hence the area of a rhomboid would be = 2 x [½ x base x height] (area of a triangle is: ½ x base x height)

I.e

Area of Rhomboid= base x height.

The area is expressed in unit square, eg, m2.

1. Calculate the area of a rhomboid ABCD when the base is 7 cm, and the perpendicular height is 5 cm.

Solution:

It is given that:

Base, b=7 cm

Height, h= 5 cm

Area of Rhomboid= base x height.

Hence,

A = b x h

= 7 x 5 cm2

= 35 cm2

Thus, the area of rhomboid ABCD is 35 cm2

2. Find the perpendicular height of a rhomboid ABCD, where the area is 50 cm2, and the measure of the base side is 10 cm.

Solution:

It is given that

Area, A= 50 cm2

Base, b= 10 cm

We know that

A = b x h

To find h

A= b x h

50= 10 x h

50/10 = h

h= 5 cm

Hence, the perpendicular height of the rhomboid ABCD is 5 cm.

2) The perimeter of a Rhomboid

Perimeter is basically the measure of the boundary of a figure. Thus the perimeter of the Rhomboid will be the addition of all the sides.

Let's assume a rhomboid to be ABCD

Hence the perimeter of the Rhomboid would be:

P= AB+BC+CD+DA

P= 2(AB+BC) ............ ( since opposite sides of a rhomboid are congruent)

1. Calculate the perimeter of a rhomboid ABCD where:

AB= 5 cm

BC=4 cm

CD=5 cm

DA= 4 cm

Solution:

It is given that:

AB = CD = 5 cm

Hence, 2AB= 5 x 2 = 10 cm

BC = DA = 4cm

Hence, 2BC=4 x 2 = 8 cm

Perimeter, P = 2AB + 2BC

= 2(AB+BC)

= 2(5+4) cm

= 2(9) cm

= 18 cm.

Thus, the perimeter of the rhomboid ABCD is 18 cm.

2. If the perimeter of the Rhomboid is 60 cm, and the measure of one side is 20 cm, find the other side of the Rhomboid.

Solution:

Let ABCD be a rhomboid.

It is given that

Perimeter, P = 60 cm

Let, the one side be AB.

Hence, AB= 20 cm

We know that the opposite sides of a rhomboid are congruent.

Hence, AB = CD = 20 cm

To find BC and DA.

P= 2AB + 2BC

60= 2(20) + 2 BC

60= 40 + 2BC

20 = 2 BC

Hence, BC = 10 cm

Since BC= DA

DA will also be 10 cm.

So finally the measurements of the sides of the rhomboid ABCD are:

AB= CD = 20 cm

BC = DA = 10 cm

FAQ (Frequently Asked Questions)

1. What is the Difference Between a Rhomboid and a Rhombus?

The answer is very simple. Even though one might confuse both these parallelograms with being the same, they have a demarcating difference. When all the sides of a rhomboid are of equal length, it is a rhombus. Thus all rhombus is a rhomboid, but all rhomboids may not be a rhombus.

2. What is the Difference Between a Rhomboid and a Rectangle?

A parallelogram where all sides are equal becomes a rhombus. Now when this rhombus comes with all right-angled corners, it is a rectangle.

3. What is the Difference Between a Rhomboid Shape and a Parallelogram?

In simple geometry, Rhomboid can be defined as a parallelogram that does not meet the properties of both a rhombus and a rectangle, i.e., no equal sides or no right-angled corners. So, rhomboids are a type of parallelogram.

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