Playing with Numbers

An Introduction To Playing With Numbers Class 6

Mathematics is a subject that helps to increase one’s reasoning ability and challenges their problem-solving skills to a certain extent. It is a medium that helps to route our critical thoughts accurately.

However, many of us find specific chapters tricky and confusing, such as permutation and combination, geometry and playing with numbers, etc. It happens because we lack in-depth knowledge about these concepts.

However, if you are dealing with problematic mathematical topics seek playing with numbers class 6 NCERT solutions! We hope the solved answers will be beneficial for the exam guidance.

Let’s start gathering knowledge!

Solved Problem On Playing With Numbers Class 6 - Exercise 3.7

If you are studying class 8 playing with numbers, we would advise you to go through the following solutions. Ace your studies with these exercises!

  1. Mohanty purchases two bags of mangoes, weighing 45 kg and 25 kg. Point out the maximum amount of weight for measuring the number of mangoes (number of times).

Answer: Since the weight of mangoes in two bags are present = 45 kg and 25 kg. 

                The maximum amount of weight will be = H.C.F. of the two bags (45, 25)

                45 = 3 * 3 * 5

                25 = 5 * 5

                H.C.F. = 5

Therefore, 5 kg is the maximum amount of weight for two bags of mangoes (the exact number of times).

  1. Two boys start stepping off from an identical place. The steps amount to 63 cm, 70 cm and 77 respectively. What will be the minimum distance that each of them should cover so that all of them can complete the entire distance? (Problem: Playing with numbers)

Answer: 1st boy’s step is = 63 cm,

              2nd boy’s step is = 70 cm,

              3rd boy’s steps measures = 77 cm.

              L.C.M. of 63, 70 and 77 using the division method

               (Image to be added soon)

              ∴ L.C.M. = 2*3*3*5*7*11 = 6,930 cm

Therefore, the minimum required distance will be 6,930 cm to cover the entire distance.

  1. Suppose there are 3 tankers, containing 50 litres, 45 litres and 60 litres of oil, respectively. Find out the highest capacity that measures the oil of all three tankers (number of times).

Answer: Maximum amount of capacity measures through = H.C.F. of (50, 45, 60)

  50 = 2*5*5

               45 = 3*3*5

  60 = 3*2*2*5

∴ H.C.F. = 5 (because it is the common factor)

So, the maximum capacity of the tanker will be 5 litres.

Tips To Tackle Mathematics Problems Regarding Playing With Number Class 8

You may find yourself in a lot of stress when you face complex math problems. However, you can reduce these problems through the following tips:

  • Try to finish your chapters along with the class. Leaving things for the last-minute can worsen your condition. Solving problems related to numbers daily can help you gain confidence. You can also learn from NCERT solutions for class 8 maths chapter playing with numbers to score better!

  • Also, you should try to memorise all the vital formulas before you finish your studies. Keeping the formulas in mind will help you solve the problems quickly. Try recalling the techniques every day apart from learning class 6 maths playing with numbers before you call it a day to score well in maths.

Students often assume mathematics as a difficult subject. However, you can score better grades in maths, if you understand all the conceptions clearly.

If you are facing any problem with difficult topics, try going through NCERT solutions for class 8 maths chapter 16 exercise 16.2. You can also visit and learn from our live classes and get detailed solutions for playing with numbers class 6 CBSE.

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FAQ (Frequently Asked Questions)

1. What Is The Dual-step Addition And Subtraction Method In Playing With Numbers?

You can use double-step addition and subtraction method to tackle complex mathematical problem related to playing with numbers. In this method, you need to first attempt which is easy and go for the difficult ones later on. The subtraction method works similarly, removing at first what’s easy and so on. 

It helps you when you struggle to add numbers while counting or reducing more than three digits together. For instance, if you need to find the sum of 392 and 88, let’s learn how to find it using this method.

= (392 + 8) + (88 - 8)

= 400 + 80

= 480

2. How To Use Reduction From 1000 Method To Solve Mathematical Equations Quickly?

A quick and easy way to solve problematic mathematical questions is through reducing a number from 1000. The technique will help you to solve four-digit numbers with ease, its ideal for people learning playing with numbers class 8. 

Take a number 1000; subtract the first two numbers from 9, and the last digit from 10. You can use this method with integers of 10,000, 1,00,000 and other going through this pattern.

For instance, suppose you need to solve 1000 – 453, then the steps will be:

= 9 – 4 = 5

= 9 – 5 = 4

= 10 - 3 = 7

= 547

3. What Is L.C.M. And H.C.F. In A Mathematical Problem Dealing With Playing With Numbers Class 8 CBSE?

L.C.M. stands for the least possible number, whereas H.C.F. stands for the highest common factor in the chapter playing with numbers. The least expected digit which completely divides a number is known as L.C.M., whereas the maximum times a number gets divided completely is known as H.C.F.

For example, suppose there are three numbers 3, 11, 66 (11*6) present. Therefore, the L.C.M. of these numbers will be 11*3*6 = 198. Similarly, assume that there are three numbers, 10, 25, and 30, present. Hence, the highest common factor (H.C.F.) will be:

10 = 2*5

25 = 5*5

30 = 2*3*5

∴ H.C.F. = 5

4. How Can You Use Doubling And Halving Method For Multiplication To Solve Problems Quickly?

A method that you can use to solve problems faster is applying doubling and halving method in multiplication. If you are studying playing with numbers, this method will be beneficial. 

You need to half the even number at first and double the other one later on. Students can use this method when the equation becomes challenging to solve.

For instance, you need to multiply 10*48; the steps will be:

= 20 * 24 (here the first number gets doubled, and the second one gets halved)

= 40 * 12

= 80 * 6

= 160 * 3

= 480 will be the solution.