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Equivalence Relation Explained with Examples

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How to Identify and Apply Equivalence Relations in Maths

We all have learned about fractions in our childhood and if we have then it is not unknown to us that every fraction has many equivalent forms. Let us take an example, 1/2, 2/4, 3/6, -1/-2, -3/-6, 15/30


The fractions given above may all look different from each other or maybe referred to by different names but actually they are all equal and the same number.

  

This unique idea of classifying them together that “look different but are actually the same” is the fundamental idea of equivalence relation. Distribution of a set S is either a finite or infinite collection of a nonempty and mutually disjoint subset whose union is S.

 

A relation R on a set A can be considered as an equivalence relation only if the relation R will be reflexive, along with being symmetric, and transitive. But what does reflexive, symmetric, and transitive mean?


Reflexive: A relation is supposed to be reflexive, if (a, a) ∈ R, for every a ∈ A.

Symmetric: A relation is supposed to be symmetric, if (a, b) ∈ R, then (b, a) ∈ R.

Transitive: A relation is supposed to be transitive if (a, b) ∈ R and (b, c) ∈ R, then (a, c) ∈ R.


Solved Examples of Equivalence Relation 

1. Let us consider that F is a relation on the set R real numbers that are defined by xFy on a condition if x-y is an integer. Prove F as an equivalence relation on R.

Reflexive property: Assume that x belongs to R, and, x – x = 0 which is an integer. Thus, xFx.

Symmetric Property: Assume that x and y belongs to R and xFy. And x – y is an integer. Therefore, y – x = – ( x – y), y – x is too an integer. Thus, yFx.

Transitive Property: Assume that x and y belongs to R, xFy, and yFz. And both x-y and y-z are integers. So, according to the transitive property, ( x – y ) + ( y – z ) = x – z is also an integer. Therefore, xFz.

Hence, R is an equivalence relation on R.


2. How do we know that the relation R is an equivalence relation in the set A = { 1, 2, 3, 4, 5 } given by the relation R = { (a, b):|a-b| is even }.

Here, R = { (a, b):|a-b| is even }. And a, b belongs to A

Reflexive Property : From the given relation,

|a – a| = | 0 |=0

And 0 is always even.

Thus, |a-a| is even

Therefore, (a, a) belongs to R

Hence R is Reflexive

Symmetric Property : From the given relation,

|a – b| = |b – a|

We know that |a – b| = |-(b – a)|= |b – a|

Hence |a – b| is even,

Then |b – a| is also even.

Therefore, if (a, b) ∈ R, then (b, a) belongs to R

Hence R is symmetric

Transitive Property : If |a-b| is even, then (a-b) is even.

In the same way, if |b-c| is even, then (b-c) is also even.

Sum of even number is also even

So, we can write it as a-b+ b-c is even

Then, a – c is also even

So,

|a – b| and |b – c| is even , then |a-c| is even.

Therefore, if (a, b) ∈ R and (b, c) ∈ R, then (a, c) also belongs to R

Hence R is transitive. 


Connection of Equivalence Relation to other relations

  • An incomplete order is a reciprocal, system can be classified, and linear relation. 

  • Equality is a complete order as well as an equivalence relation.

  • Equality is also the only inductive, symmetric, and antisymmetric relation on a set. 

  • Equal variables in algebraic expressions can be replaced for one another, a feature not accessible for equivalence-related variables. 

  • Persons inside an equivalence relation's equivalence classes can replace each other, but not people within a class.

  • A rigorous incomplete order is asymmetric, irreflexive, and bidirectional. 

  • A complete equivalence connection is equal and linear. Such a relationship is bidirectional if and only if it is serial, that is, if for every display style, there occurs some display style text such that asim b. As a result, an equivalence relation can be defined in a variety of ways, including symmetric, transitive, and serial.

  • The ternary equivalent of the normal equivalence relation is the ternary comparability relation.

  • A reliance relation or a tolerance relation is a reciprocal and symmetrical relation.

  • A sequence is both bidirectional and inductive.

  • An equivalence relation whose domain X is also the bottom set for an algebraic form and which satisfies the extra form is known as a congruence relation. In general, congruence relations serve as homomorphism kernels, and a structure's quotient can be created using a congruence relation. Congruence relations have an alternate representation as structural components of the form on which they are established in many crucial circumstances.

  • Although the opposite assertion holds exclusively in classical mathematics because it is identical to the law of excluded middle, any equivalence connection is the negative of an apartness relationship.

  • Every recursive and left or right Riemann connection is also an interval estimate.


A Few key points to remember

i) Equations with similar solutions or bases are known as equivalent equations.

ii) An analogous equation is created by adding or subtracting the identical number or phrase to both sides of an equation.

iii) An analogous equation is created by multiplying or dividing both sides of an equation by the same non-zero value.


Conclusion

The primary focus lies in conceptual understanding and one who has mastered that art is sure to succeed. Practice sums after going through the concept for a better understanding of the topic. Equivalence relations can be a tricky affair if not practiced again and again.

FAQs on Equivalence Relation Explained with Examples

1. What is an equivalence relation in Maths as per the CBSE Class 12 syllabus?

An equivalence relation is a specific type of binary relation on a set that groups together elements that are considered 'equivalent' in some way. For a relation R on a set A to be an equivalence relation, it must satisfy three specific conditions: it must be reflexive, symmetric, and transitive. If even one of these properties does not hold, the relation is not an equivalence relation.

2. What are the three properties a relation must satisfy to be an equivalence relation?

A relation R on a set A is defined as an equivalence relation if it satisfies the following three properties for all elements a, b, and c in set A:

  • Reflexive Property: Every element is related to itself. For every a ∈ A, (a, a) ∈ R.

  • Symmetric Property: If the first element is related to the second, then the second must be related to the first. If (a, b) ∈ R, then (b, a) ∈ R.

  • Transitive Property: If a first element is related to a second, and that second element is related to a third, then the first must be related to the third. If (a, b) ∈ R and (b, c) ∈ R, then (a, c) ∈ R.

3. What are some common examples of equivalence relations?

Some common mathematical examples that help explain the concept of equivalence relations include:

  • The relation 'is equal to' (=) on the set of all numbers.

  • The relation 'is similar to' on the set of all triangles.

  • The relation 'is congruent to' on the set of all polygons.

  • For lines in a plane, the relation 'is parallel to' (L1 || L2).

  • The relation 'has the same birthday' on a set of people.

4. How do you prove that a given relation is an equivalence relation?

To prove that a relation R on a set A is an equivalence relation, you must demonstrate methodically that it satisfies all three required properties:

  1. Prove Reflexivity: Show that for any arbitrary element 'a' from set A, the pair (a, a) is in R.

  2. Prove Symmetry: Assume that for arbitrary elements 'a' and 'b' from set A, the pair (a, b) is in R. Then, use the definition of the relation to show that (b, a) must also be in R.

  3. Prove Transitivity: Assume that for arbitrary elements a, b, and c from set A, the pairs (a, b) and (b, c) are both in R. Then, use the definition of the relation to show that (a, c) must also be in R.

If all three properties are successfully proven, you can conclude that R is an equivalence relation.

5. What is an equivalence class?

An equivalence class is a fundamental concept directly linked to an equivalence relation. For any element 'a' in a set A, its equivalence class, denoted as [a], is the subset of A containing all elements 'x' that are related to 'a' under the equivalence relation R. In simple terms, [a] = {x ∈ A | (x, a) ∈ R}. An equivalence relation effectively divides, or partitions, the entire set A into a collection of these equivalence classes, where each class is disjoint (non-overlapping) and their union is the entire set A.

6. Why is the concept of partitioning a set so important for understanding equivalence relations?

The concept of partitioning is crucial because it reveals the true purpose of an equivalence relation: to categorise or group elements. An equivalence relation on a set A fundamentally carves the set into non-overlapping subsets, known as equivalence classes. Every element in the original set belongs to one and only one of these classes. This means the relation provides a structured way to classify all elements based on a shared property, which is the essence of 'equivalence'. The relation and the partition are two sides of the same coin.

7. How is an equivalence relation different from a partial order relation?

The primary difference lies in the second property they must satisfy. An equivalence relation requires symmetry, while a partial order relation requires anti-symmetry.

  • Symmetry (Equivalence): If a is related to b, then b must be related to a. This property creates groups of equals.

  • Anti-symmetry (Partial Order): If a is related to b and b is related to a, then a and b must be the same element. This property establishes a hierarchy or an order (like 'less than or equal to').

Both relations must be reflexive and transitive, but this key difference in the second property means they describe entirely different kinds of structures.

8. Can a relation be symmetric and transitive but not reflexive? Give an example.

Yes, a relation can be symmetric and transitive without being reflexive. This happens when an element in the set is not related to anything, including itself. Consider the set A = {1, 2, 3} and the relation R = {(1, 1), (1, 2), (2, 1), (2, 2)}.

  • It is not reflexive because the element 3 is in set A, but the pair (3, 3) is not in R.

  • It is symmetric because for (1, 2) in R, (2, 1) is also in R.

  • It is transitive as it satisfies all conditions (e.g., (2,1) and (1,2) are in R, and (2,2) is also in R).

Since it fails the reflexive property, it is not an equivalence relation. This shows why all three conditions are essential.

9. What is a common mistake students make when checking for transitivity?

A common mistake is misunderstanding what it means for the transitive property to hold. The property states: IF (a, b) ∈ R and (b, c) ∈ R, THEN (a, c) must be in R. Students often mistakenly think the property fails if they cannot find a chain of (a, b) and (b, c). However, the property is only violated if the 'IF' condition is true, but the 'THEN' condition is false. If you cannot find a link from b to c, the condition is considered vacuously true for that specific 'a' and 'b' pair and is not a violation.