Wolframite ore is separated from tin stone ore by the process of
(a) Roasting
(b) Electromagnetic
(c) Smelting
(d) Calcination
Answer
Verified
119.1k+ views
Hint: Wolframite is an ore of iron and tungsten. It has magnetic properties. It is a series of tungsten ore minerals.
Complete step by step solution:
-Wolframite ore can be represented as\[[FeW{{O}_{4}}]\]. It is present in tin stone as impurities. It has the same mass per unit volume as that of a tinstone. Because wolframite has a magnetic nature, it can be separated from tinstone using an electromagnetic separator. Tinstone is non magnetic.
-Electromagnetic separation is a process of removing magnetic materials from non magnetic materials, using electromagnets in which the materials travel along a conveyor, over a drum or into a revolving screen. It is a method to purify certain metals, ores, isolate metals and oils.
-Roasting is a process of heating of a sulphide ore at a high temperature in the presence of air. It is a metallurgical process involving gas-solid reaction at high temperatures and used to purify metal components. Roasting consists of oxidation, reduction, chlorination, sulfation and pyrohydrolysis reactions.
-Smelting is a process where metal is extracted from an ore by applying heat. Many metals are extracted from their ores using this method like silver, iron, copper and other base metals. This process uses heat and chemical reducing agents to decompose the ore, and driving off other elements and leaving only the metal base behind.
-Calcination is the process of heating ores at high temperature in the presence of air or oxygen. It is basically thermal decomposition of ores and other materials.
Thus, Wolframite ore is separated from tin stone ore by the process of electromagnetic separation and the correct answer to the question is option (b).
Note: The main difference between tinstone ore and wolframite ore is that tinstone ore is not magnetic while the latter is magnetic. Other process is the heating process.
Complete step by step solution:
-Wolframite ore can be represented as\[[FeW{{O}_{4}}]\]. It is present in tin stone as impurities. It has the same mass per unit volume as that of a tinstone. Because wolframite has a magnetic nature, it can be separated from tinstone using an electromagnetic separator. Tinstone is non magnetic.
-Electromagnetic separation is a process of removing magnetic materials from non magnetic materials, using electromagnets in which the materials travel along a conveyor, over a drum or into a revolving screen. It is a method to purify certain metals, ores, isolate metals and oils.
-Roasting is a process of heating of a sulphide ore at a high temperature in the presence of air. It is a metallurgical process involving gas-solid reaction at high temperatures and used to purify metal components. Roasting consists of oxidation, reduction, chlorination, sulfation and pyrohydrolysis reactions.
-Smelting is a process where metal is extracted from an ore by applying heat. Many metals are extracted from their ores using this method like silver, iron, copper and other base metals. This process uses heat and chemical reducing agents to decompose the ore, and driving off other elements and leaving only the metal base behind.
-Calcination is the process of heating ores at high temperature in the presence of air or oxygen. It is basically thermal decomposition of ores and other materials.
Thus, Wolframite ore is separated from tin stone ore by the process of electromagnetic separation and the correct answer to the question is option (b).
Note: The main difference between tinstone ore and wolframite ore is that tinstone ore is not magnetic while the latter is magnetic. Other process is the heating process.
Recently Updated Pages
The hybridization and shape of NH2 ion are a sp2 and class 11 chemistry JEE_Main
Total number of orbitals associated with the 3rd shell class 11 chemistry JEE_Main
Which of the following has the lowest boiling point class 11 chemistry JEE_Main
Which of the following compounds has zero dipole moment class 11 chemistry JEE_Main
Number of g of oxygen in 322 g Na2SO410H2O is Molwt class 11 chemistry JEE_Main
In the neutralization process of H3PO4 and NaOH the class 11 chemistry JEE_Main
Trending doubts
JEE Main 2025: Application Form (Out), Exam Dates (Released), Eligibility & More
JEE Main Login 2045: Step-by-Step Instructions and Details
JEE Main Chemistry Question Paper with Answer Keys and Solutions
Learn About Angle Of Deviation In Prism: JEE Main Physics 2025
JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics
JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking
Other Pages
NCERT Solutions for Class 11 Chemistry Chapter 7 Redox Reaction
NCERT Solutions for Class 11 Chemistry Chapter 5 Thermodynamics
NCERT Solutions for Class 11 Chemistry Chapter 8 Organic Chemistry
NCERT Solutions for Class 11 Chemistry Chapter 6 Equilibrium
NCERT Solutions for Class 11 Chemistry Chapter 9 Hydrocarbons
Equilibrium Class 11 Notes: CBSE Chemistry Chapter 6