Answer
64.8k+ views
Hint: We are given with four unit conversion of the dipole moment and are asked to find out the correct one out of them. In other words, we are asked to evaluate the standard unit conversion of dipole moment. Thus, we will take into consideration the standard setup for a dipole and then calculate its dipole moment.
Complete Step By Step Solution:
In the standard setup,
The standard unit Debye is expressed in the electrostatic unit of charge.
That means,
$1D = {10^{ - 18}}esu.cm$
Now,
We know,
$1esu = 3.3356 \times {10^{ - 10}}C$
And
$1cm = {10^{ - 2}}m$
Putting in these values, we get
$1D = {10^{ - 18}} \times 3.356 \times {10^{ - 10}} \times {10^{ - 2}}Cm$
Further, we get
$1D = 3.3356 \times {10^{ - 30}}Cm$
Hence, the correct answer is (B).
Additional Information: In this question, we discussed the dipole moment. But what is the dipole moment and what is the dipole? We will discuss these two points in this briefing. Now, Dipole is nothing but a setup of two opposite charges of equal magnitudes placed at a fixed distance from each other. This setup is done to study the effect on a separate particle placed at the equatorial plane or the axial plane or at any random position in space. The dipole moment is a value assigned to a dipole setup so as to get an idea of the effectiveness of the dipole setup. The value of a dipole is calculated by the product of the magnitude of the either charge with the distance of separation of the charges. The distance of separation of the charges is also called the length or the size of the dipole.
Note: Here we have used the standard setup as the unit conversion is asked for a general case. If some other situation was asked, then the conversion would have been different.
Complete Step By Step Solution:
In the standard setup,
The standard unit Debye is expressed in the electrostatic unit of charge.
That means,
$1D = {10^{ - 18}}esu.cm$
Now,
We know,
$1esu = 3.3356 \times {10^{ - 10}}C$
And
$1cm = {10^{ - 2}}m$
Putting in these values, we get
$1D = {10^{ - 18}} \times 3.356 \times {10^{ - 10}} \times {10^{ - 2}}Cm$
Further, we get
$1D = 3.3356 \times {10^{ - 30}}Cm$
Hence, the correct answer is (B).
Additional Information: In this question, we discussed the dipole moment. But what is the dipole moment and what is the dipole? We will discuss these two points in this briefing. Now, Dipole is nothing but a setup of two opposite charges of equal magnitudes placed at a fixed distance from each other. This setup is done to study the effect on a separate particle placed at the equatorial plane or the axial plane or at any random position in space. The dipole moment is a value assigned to a dipole setup so as to get an idea of the effectiveness of the dipole setup. The value of a dipole is calculated by the product of the magnitude of the either charge with the distance of separation of the charges. The distance of separation of the charges is also called the length or the size of the dipole.
Note: Here we have used the standard setup as the unit conversion is asked for a general case. If some other situation was asked, then the conversion would have been different.
Recently Updated Pages
Write a composition in approximately 450 500 words class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Arrange the sentences P Q R between S1 and S5 such class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What is the common property of the oxides CONO and class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
If four points A63B 35C4 2 and Dx3x are given in such class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The area of square inscribed in a circle of diameter class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Other Pages
A boat takes 2 hours to go 8 km and come back to a class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Electric field due to uniformly charged sphere class 12 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
In the ground state an element has 13 electrons in class 11 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
According to classical free electron theory A There class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Excluding stoppages the speed of a bus is 54 kmph and class 11 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)