Which of the following statements is/are correct regarding the electric field produced by changing magnetic field due to motion of charge q?
A) It is non-conservative in nature
B) It is non-electrostatic in nature
C) Potential can be defined corresponding to this field.
D) The lines of this field are closed curves.
Answer
274.2k+ views
Hint: This question can be answered by analysing each option carefully and then arriving at the correct option by eliminating the improbable option. Compare this electric field with the electric field produced by normal static charges to reach to the conclusion.
Complete step by step answer:
We know that the induced electromotive force or emf in any closed circular loop is equal to the rate of change of the magnetic flux in the same current carrying coil. This means that the induced electromotive force or emf in the current carrying loop is non-zero. Thus the electric field in the current carrying coil due to the induced magnetic field will be non-conservative. Thus we can clearly see that option (A) is correct.
We also know that the electric field which is produced by a changing magnetic field is not a result of the static electric charges and is thus, non-conservative in nature. This means that the electric field produced by a changing magnetic field due to motion of an electric charge is non-electrostatic in nature. Thus we see that the option (B) is also correct.
As we have come to the conclusion that the electric field produced by a changing magnetic field due to motion of an electric charge is non-electrostatic in nature, we can say that the potential cannot be defined for a point for a non-electrostatic field. This is because the work done in moving an electric charge in an induced electric field is path dependent. Thus, we find that the option (C) is incorrect.
The induced electric field lines produced due to changing magnetic field because of the motion of an electric charge form closed curves. Thus option (D) is also correct.
$\therefore$ The correct options are A,B and D
Note: The electric field which is conservative in nature, only for them we can define a potential and consider the work done by that field in a round trip/closed path to be zero. For non-conservative fields the energy is not conserved.
Complete step by step answer:
We know that the induced electromotive force or emf in any closed circular loop is equal to the rate of change of the magnetic flux in the same current carrying coil. This means that the induced electromotive force or emf in the current carrying loop is non-zero. Thus the electric field in the current carrying coil due to the induced magnetic field will be non-conservative. Thus we can clearly see that option (A) is correct.
We also know that the electric field which is produced by a changing magnetic field is not a result of the static electric charges and is thus, non-conservative in nature. This means that the electric field produced by a changing magnetic field due to motion of an electric charge is non-electrostatic in nature. Thus we see that the option (B) is also correct.
As we have come to the conclusion that the electric field produced by a changing magnetic field due to motion of an electric charge is non-electrostatic in nature, we can say that the potential cannot be defined for a point for a non-electrostatic field. This is because the work done in moving an electric charge in an induced electric field is path dependent. Thus, we find that the option (C) is incorrect.
The induced electric field lines produced due to changing magnetic field because of the motion of an electric charge form closed curves. Thus option (D) is also correct.
$\therefore$ The correct options are A,B and D
Note: The electric field which is conservative in nature, only for them we can define a potential and consider the work done by that field in a round trip/closed path to be zero. For non-conservative fields the energy is not conserved.
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