Question

Which of the following represents clear electropositive properties ?
A. F
B. I
C. $Br$
D. $Cl$

Answer 1

Hint: As we move down a group in halogen the electropositivity of halogen elements increases. Thus fluorine is least electropositive.

Complete Step by Step Answer:
Electropositivity of an element is defined as its electron releasing power. As we move from fluorine to iodine in the halogen group the size of the halogen increases so, the attracting power of the nucleus towards the electron decreases. Thus the electron releasing tendency increases and electropositivity also increases. Thus we can write that I or iodine represent clear electropositive properties.
Thus the correct option is B.

Additional Information: Iodine generally exists as a gas at room temperature. It is a violet colored gas and has the atomic number of $56$. In the presence of starch it gives blue coloration. It has the symbol of I.

Note: Halogens are generally electronegative elements. The electronegativity of an element is defined as the attraction of the nucleus of an atom towards the electrons. As we move from fluorine to iodine in the halogen group the size of the halogen increases so, the attracting power of the nucleus towards the electron decreases. Thus the electron releasing tendency increases and electronegativity decreases. Thus fluorine is the most electronegative element among halogens.