
Which of the following aqueous solutions produces the same osmotic pressure? This question has multiple correct options
(A) $0.1M$ $NaCl$solution
(B) $0.1M$glucose solution
(C) $0.6g$ urea in $100ml$ solution
(D) $1.0g$ of a non-electrolyte solute (X) in $50ml$ solution (Molar mass of X = 200)
Answer
233.1k+ views
Hint: The minimum pressure which is required to be applied to the solution to prevent the inward flow of the solvent across a semipermeable membrane is known as osmotic pressure. This process is known as osmosis.
Formula Used: The formula used to calculate the osmotic pressure of a solution is:
$\pi = icRT$; where $i$ = van’t hoff index
$c$ = Concentration of solute, $R$ = Gas constant, $T$ = Temperature (Kelvin), $\pi $= Osmotic pressure.
Complete Step by Step Answer:
For two solutions to be isotonic, they should have the same osmotic pressure. So, we will calculate the osmotic pressure of each of the solutions given in the options, and the two solutions that will have the same osmotic pressure will be our answer.
(A) $0.1M$ $NaCl$solution
As $NaCl$ dissociates and gives 2 ions, so $i=2$
Thus, osmotic pressure will be
$\pi =2\times 0.1\times R\times T$
$\pi =0.2RT$
(B) $0.1M$glucose solution
As glucose does not dissociates, that is, it does not give any ions, so $i=1$
Thus, osmotic pressure will be
$\pi =1\times 0.1\times R\times T$
$\pi =0.1RT$
(C) $0.6g$ urea in $100ml$ solution
Urea does not dissociate, so $i=1$
Also, the concentration is calculated as
$c=\frac{0.6\times 1000}{60\times 100}$
$c=0.1$
Thus, osmotic pressure will be
$\pi =1\times 0.1\times R\times T$
$\pi =0.1RT$
(D) $1.0g$ of a non-electrolyte solute (X) in $50ml$ solution (Molar mass of X = 200)
As a non-electrolyte does not dissociate, so $i=1$
Also, the concentration is calculated as
$c=\frac{1.0\times 1000}{200\times 50}$
$c=0.1$
Thus, osmotic pressure will be
$\pi =1\times 0.1\times R\times T$
$\pi =0.1RT$
Hence, 0.1M glucose solution, 0.6g urea in 100ml solution, and 1.0g of a non-electrolyte solute (X) in 50 ml solution are isotonic solutions.
Correct Options: (B), (C) and (D).
Note: The process of osmosis is important for the human body. In the human body, osmosis occurs in the small and large intestines. It plays an important role in the gastro-intestinal system and kidneys. It helps in getting all the essential nutrients from our food and also removes the waste products from the blood.
Formula Used: The formula used to calculate the osmotic pressure of a solution is:
$\pi = icRT$; where $i$ = van’t hoff index
$c$ = Concentration of solute, $R$ = Gas constant, $T$ = Temperature (Kelvin), $\pi $= Osmotic pressure.
Complete Step by Step Answer:
For two solutions to be isotonic, they should have the same osmotic pressure. So, we will calculate the osmotic pressure of each of the solutions given in the options, and the two solutions that will have the same osmotic pressure will be our answer.
(A) $0.1M$ $NaCl$solution
As $NaCl$ dissociates and gives 2 ions, so $i=2$
Thus, osmotic pressure will be
$\pi =2\times 0.1\times R\times T$
$\pi =0.2RT$
(B) $0.1M$glucose solution
As glucose does not dissociates, that is, it does not give any ions, so $i=1$
Thus, osmotic pressure will be
$\pi =1\times 0.1\times R\times T$
$\pi =0.1RT$
(C) $0.6g$ urea in $100ml$ solution
Urea does not dissociate, so $i=1$
Also, the concentration is calculated as
$c=\frac{0.6\times 1000}{60\times 100}$
$c=0.1$
Thus, osmotic pressure will be
$\pi =1\times 0.1\times R\times T$
$\pi =0.1RT$
(D) $1.0g$ of a non-electrolyte solute (X) in $50ml$ solution (Molar mass of X = 200)
As a non-electrolyte does not dissociate, so $i=1$
Also, the concentration is calculated as
$c=\frac{1.0\times 1000}{200\times 50}$
$c=0.1$
Thus, osmotic pressure will be
$\pi =1\times 0.1\times R\times T$
$\pi =0.1RT$
Hence, 0.1M glucose solution, 0.6g urea in 100ml solution, and 1.0g of a non-electrolyte solute (X) in 50 ml solution are isotonic solutions.
Correct Options: (B), (C) and (D).
Note: The process of osmosis is important for the human body. In the human body, osmosis occurs in the small and large intestines. It plays an important role in the gastro-intestinal system and kidneys. It helps in getting all the essential nutrients from our food and also removes the waste products from the blood.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding the Electric Field of a Uniformly Charged Ring

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Hydrocarbons Class 11 Chemistry Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Chemistry Chapter 5 CBSE Notes - 2025-26

Equilibrium Class 11 Chemistry Chapter 6 CBSE Notes - 2025-26

Organic Chemistry Some Basic Principles And Techniques Class 11 Chemistry Chapter 8 CBSE Notes - 2025-26

NCERT Solutions For Class 11 Chemistry Chapter 7 Redox Reactions (2025-26)

