Answer
64.8k+ views
Hint: The electronic configuration of an element describes how electrons are distributed in its atomic orbitals. The electronic configurations of atoms follow a standard notation in which all electron-containing atomic subshells are placed in a sequence.
Complete step by step answer:
The electronic configuration of an atom is written with the help of the subshell labels. Now, these labels contain the shell number (given by the principal quantum number), the subshell name, (given by the azimuthal quantum number) and the total number of electrons in the subshell in superscript.
For example if the two electrons are filled in the' subshell of the first shell, then the resulting notation is $1{s^2}$. The three rules that dictate the manner in which electrons are filled in atomic orbitals are Aufbau principle, Pauli’s exclusion principle and Hund’s rule.
In Aufbau principle, the electrons must completely fill the atomic orbitals of a given energy level before occupying an orbital associated with a higher energy.
In Pauli’s exclusion principle, no two electrons can have equal values for all four quantum numbers and each subshell of an orbital can accommodate a maximum of two electrons and both the electrons must have opposite spins.
In Hund’s rule, all the subshells in an orbital must be singly occupied before any subshell is doubly occupied.
The order in which the electrons are filled in atomic orbitals as per the Aufbau principle is as shown:
![](https://www.vedantu.com/question-sets/326437fa-86ef-4049-b77f-46177a66319e3455216231618656426.png)
Now, among the given options Al is the correct option as, the atomic number of aluminum Is 13 and further, according the given rules, its electronic configuration is $1{s^2}2{s^2}2{p^6}3{s^2}3{p^1}$.
Hence, option B is correct.
Note:
The electronic configuration of copper is $[Ar]3{d^{10}}4{s^1}$. This configuration disobeys the aufbau principle due to the relatively small energy gap between the $3d$ and the $4s$ orbitals and chromium is also one such exception in this case. These exceptions can sometimes be explained by the stability provided by half-filled or completely filled subshells.
Complete step by step answer:
The electronic configuration of an atom is written with the help of the subshell labels. Now, these labels contain the shell number (given by the principal quantum number), the subshell name, (given by the azimuthal quantum number) and the total number of electrons in the subshell in superscript.
For example if the two electrons are filled in the' subshell of the first shell, then the resulting notation is $1{s^2}$. The three rules that dictate the manner in which electrons are filled in atomic orbitals are Aufbau principle, Pauli’s exclusion principle and Hund’s rule.
In Aufbau principle, the electrons must completely fill the atomic orbitals of a given energy level before occupying an orbital associated with a higher energy.
In Pauli’s exclusion principle, no two electrons can have equal values for all four quantum numbers and each subshell of an orbital can accommodate a maximum of two electrons and both the electrons must have opposite spins.
In Hund’s rule, all the subshells in an orbital must be singly occupied before any subshell is doubly occupied.
The order in which the electrons are filled in atomic orbitals as per the Aufbau principle is as shown:
![](https://www.vedantu.com/question-sets/326437fa-86ef-4049-b77f-46177a66319e3455216231618656426.png)
Now, among the given options Al is the correct option as, the atomic number of aluminum Is 13 and further, according the given rules, its electronic configuration is $1{s^2}2{s^2}2{p^6}3{s^2}3{p^1}$.
Hence, option B is correct.
Note:
The electronic configuration of copper is $[Ar]3{d^{10}}4{s^1}$. This configuration disobeys the aufbau principle due to the relatively small energy gap between the $3d$ and the $4s$ orbitals and chromium is also one such exception in this case. These exceptions can sometimes be explained by the stability provided by half-filled or completely filled subshells.
Recently Updated Pages
Write a composition in approximately 450 500 words class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Arrange the sentences P Q R between S1 and S5 such class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What is the common property of the oxides CONO and class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
If four points A63B 35C4 2 and Dx3x are given in such class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The area of square inscribed in a circle of diameter class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Other Pages
A boat takes 2 hours to go 8 km and come back to a class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
In the ground state an element has 13 electrons in class 11 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Electric field due to uniformly charged sphere class 12 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
According to classical free electron theory A There class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Excluding stoppages the speed of a bus is 54 kmph and class 11 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)