
Which compound can exist in a dipolar (zwitterion) structure?
(A) \[{C_6}{H_5}C{H_2}CH(N = C{H_2})COOH\]
(B) \[{(C{H_3})_2}CHCH(N{H_2})COOH\]
(C) \[{C_6}{H_5}CONHC{H_2}COOH\]
(D) \[HOOCC{H_2}C{H_2}COCOOH\]
Answer
151.8k+ views
Hint: Zwitterions are basically molecules with two sets of functional groups. The condition to be followed is that one of these functional groups needs to be positively charged, while the other functional group needs to be negatively charged. Also, the net charge on the molecule must be zero.
Complete Step-by-Step Solution:
To determine which of the given molecules is a zwitterion, we need to understand the molecular structures of these molecules and also understand the type of functional groups present on these molecules. Another condition to be followed is that both these functional groups must be present on the same carbon atom.
\[{C_6}{H_5}C{H_2}CH(N = C{H_2})COOH\]

The functional groups present in this compound are secondary amine and carboxylic acids. Amine is a positive functional group and carboxylic acid is a negative functional group. But both these functional groups are not present on the same carbon atom.
\[{(C{H_3})_2}CHCH(N{H_2})COOH\]

The functional groups present in this compound are amine and carboxylic acid. Amine is a positive functional group and carboxylic acid is a negative functional group. And both these functional groups are present on the same carbon atom.
\[{C_6}{H_5}CONHC{H_2}COOH\]

The functional groups present in this compound are amide and carboxylic acid. Amide is a negative functional group and carboxylic acid is also a negative functional group.
\[HOOCC{H_2}C{H_2}COCOOH\]

The functional groups present in this compound are carbonyl and carboxylic acid. Carbonyl is a negative functional group and carboxylic acid is also a negative functional group.
Hence, Option C is the correct option.
Note: Amino Acids have both the amine functional group and carboxylic acid functional group. Both of these are present on the same carbon atom. Hence all amino acids are by default zwitterions.
Complete Step-by-Step Solution:
To determine which of the given molecules is a zwitterion, we need to understand the molecular structures of these molecules and also understand the type of functional groups present on these molecules. Another condition to be followed is that both these functional groups must be present on the same carbon atom.
\[{C_6}{H_5}C{H_2}CH(N = C{H_2})COOH\]

The functional groups present in this compound are secondary amine and carboxylic acids. Amine is a positive functional group and carboxylic acid is a negative functional group. But both these functional groups are not present on the same carbon atom.
\[{(C{H_3})_2}CHCH(N{H_2})COOH\]

The functional groups present in this compound are amine and carboxylic acid. Amine is a positive functional group and carboxylic acid is a negative functional group. And both these functional groups are present on the same carbon atom.
\[{C_6}{H_5}CONHC{H_2}COOH\]

The functional groups present in this compound are amide and carboxylic acid. Amide is a negative functional group and carboxylic acid is also a negative functional group.
\[HOOCC{H_2}C{H_2}COCOOH\]

The functional groups present in this compound are carbonyl and carboxylic acid. Carbonyl is a negative functional group and carboxylic acid is also a negative functional group.
Hence, Option C is the correct option.
Note: Amino Acids have both the amine functional group and carboxylic acid functional group. Both of these are present on the same carbon atom. Hence all amino acids are by default zwitterions.
Recently Updated Pages
Classification of Drugs Based on Pharmacological Effect, Drug Action

Types of Solutions - Solution in Chemistry

Difference Between Alcohol and Phenol

JEE Main Participating Colleges 2024 - A Complete List of Top Colleges

JEE Main Maths Paper Pattern 2025 – Marking, Sections & Tips

Sign up for JEE Main 2025 Live Classes - Vedantu

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Degree of Dissociation and Its Formula With Solved Example for JEE

JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics

Electrical Field of Charged Spherical Shell - JEE

Other Pages
NCERT Solutions for Class 12 Chemistry Chapter 1 Solutions

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 12 Chemistry Chapter 2 Electrochemistry

NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

Solutions Class 12 Notes: CBSE Chemistry Chapter 1
