Vinegar obtained from cane sugar contains [CPMT $1980$; DPMT $1982$; KCET $1992$; MP PMT $1994$;AIIMS $1999$]
A.Citric acid
B.Lactic acid
C.Acetic acid
D.Palmitic acid
Answer
249.6k+ views
Hint: In the industrial field cane sugar is one of the most widely used perennial grasses. Along with fiber tissue, it contains a high amount of sugar. Historically Vinegar was made with natural sugar such as cane sugar, grasps, honey, etc. Vinegar is a weak acid produced by a two-step fermentation process.
Complete answer:Vinegar is a dilute solution of an acid named acetic acid. Generally, it is made with $5%-8%$acetic acid by volume and used as a flavoring for foods or directly used as an ingredient of mustard, ketchup, pickle, etc. Natural vinegar can be prepared from a wide range of fruits like apples, grasps, cane sugar, dates, and from plants.
In the fermentation process at first, yeast feeds on the sugar or stretches any liquid from a plant like fruits, grains, rice, etc. then the liquid ferments into alcohol. Now, this fresh alcohol is exposed to air and a bacteria named acetobacter ferments this alcohol again over a very long time either weeks or months and finally forms vinegar. The overall reaction of acetic acid preparation is given by the following reaction:
$\begin{align}
& {{C}_{2}}{{H}_{5}}OH\,\,\,\,+\,\,\,{{O}_{2}}\to \,\,\,C{{H}_{3}}COOH\,\,\,\,+\,\,\,{{H}_{2}}O \\
& (Ethanol)\,\,\,\,\,\,(Air)\,\,\,\,\,\,(Acetic\,\,acid)\, \\
\end{align}$
Acetic acid is the major component of vinegar and it smelt like pungent vinegar.
Therefore vinegar obtained from cane sugar contains $5%-8%$acetic acid.
Thus, option (C) is correct.
Note: Vinegar is most widely used in the culinary, medicinal, and industrial fields. In the culinary industry, it is used as a condiment, preservative, and flavoring agent since ancient times. The anti-infective qualities of vinegar make it an effective disinfectant for infections. It can be used directly on many cooking dishes.
Complete answer:Vinegar is a dilute solution of an acid named acetic acid. Generally, it is made with $5%-8%$acetic acid by volume and used as a flavoring for foods or directly used as an ingredient of mustard, ketchup, pickle, etc. Natural vinegar can be prepared from a wide range of fruits like apples, grasps, cane sugar, dates, and from plants.
In the fermentation process at first, yeast feeds on the sugar or stretches any liquid from a plant like fruits, grains, rice, etc. then the liquid ferments into alcohol. Now, this fresh alcohol is exposed to air and a bacteria named acetobacter ferments this alcohol again over a very long time either weeks or months and finally forms vinegar. The overall reaction of acetic acid preparation is given by the following reaction:
$\begin{align}
& {{C}_{2}}{{H}_{5}}OH\,\,\,\,+\,\,\,{{O}_{2}}\to \,\,\,C{{H}_{3}}COOH\,\,\,\,+\,\,\,{{H}_{2}}O \\
& (Ethanol)\,\,\,\,\,\,(Air)\,\,\,\,\,\,(Acetic\,\,acid)\, \\
\end{align}$
Acetic acid is the major component of vinegar and it smelt like pungent vinegar.
Therefore vinegar obtained from cane sugar contains $5%-8%$acetic acid.
Thus, option (C) is correct.
Note: Vinegar is most widely used in the culinary, medicinal, and industrial fields. In the culinary industry, it is used as a condiment, preservative, and flavoring agent since ancient times. The anti-infective qualities of vinegar make it an effective disinfectant for infections. It can be used directly on many cooking dishes.
Recently Updated Pages
JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Isoelectronic Definition in Chemistry: Meaning, Examples & Trends

Ionisation Energy and Ionisation Potential Explained

Iodoform Reactions - Important Concepts and Tips for JEE

Introduction to Dimensions: Understanding the Basics

Instantaneous Velocity Explained: Formula, Examples & Graphs

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Hybridisation in Chemistry – Concept, Types & Applications

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Other Pages
CBSE Class 12 Chemistry Question Paper 2026 PDF Download (All Sets) with Answer Key

NCERT Solutions For Class 12 Chemistry Chapter 10 Biomolecules - 2025-26

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions For Class 12 Chemistry Chapter 2 Electrochemistry - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 1 Solutions - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 3 Chemical Kinetics - 2025-26

