
Underwater illusion. One clue used by your brain to determine the direction of a source of sound is the time delay Δt between the arrival of the sound at the ear closer to the source and the arrival at the farther ear. Assume that the source is distant so that a wavefront from it is approximately planar when it reaches you, and let D represent the separation between your ears.
(a) If the source is located at angle θ in front of you (Fig. 17-31), what is Δt in terms of D and the speed of sound v in air?
(b) If you are submerged in water and the sound source is directly to your right, what is Δt in terms of D and the speed of sound \[{{v}_{w}}\] in water?
(c) Based on the time-delay clue, your brain interprets the submerged sound to arrive at an angle θ from the forward direction. Evaluate θ for fresh water at 20 \[^{0}C\]

The two angles marked in the figure represent angle, θ
Answer
161.1k+ views
Hint: Wavefront describes the movement of sound from the source and has its origin in Hygen’s principle. According to it, Sound moves equally in all directions and there cannot be a backward flow of energy and hence no backward wavefront. We can make use of formula for speed to find out the answer of part (a)
Complete Step by step solution:
(a) using the relationship between speed, distance and time we get.
\[\Delta t=\dfrac{d}{v}=\dfrac{D\sin \theta }{v}\]
(b) since, the speed of the sound in water is now \[{{v}_{n}}\] with \[\theta ={{90}^{0}}\], we have
\[\Delta {{t}_{w}}=\dfrac{D\sin \theta }{{{v}_{w}}}=\dfrac{d}{{{v}_{w}}}\]
(c) now to find the apparent angle we can do that as, \[\Delta t=\dfrac{D\sin \theta }{v}=\dfrac{d}{{{v}_{w}}}\]
Solving for the angle \[\theta \]with \[{{v}_{w}}=1482m/s\] we get,
$\Rightarrow \theta ={{\sin }^{-1}}(\dfrac{v}{{{v}_{w}}}) \\
\Rightarrow \theta ={{\sin }^{-1}}(\dfrac{343}{1482}) \\$
$343m/s$ being the speed of sound in air,
$\Rightarrow {{\sin }^{-1}}(0.231) \\
\therefore {{13}^{0}} \\$
Note: Trigonometric ratios are unitless but angles can be measured either in degrees or radians. All the units to be taken in standard SI units of system. A wavefront is a surface over which a wave has a constant phase. Wavefront came into existence from Hygen’s theory of wave picture of light. Wavefront determines the nature and propagation of a light emanating from the given source.
One should always keep in mind that frequency is the characteristic of the source of the light
Complete Step by step solution:
(a) using the relationship between speed, distance and time we get.
\[\Delta t=\dfrac{d}{v}=\dfrac{D\sin \theta }{v}\]
(b) since, the speed of the sound in water is now \[{{v}_{n}}\] with \[\theta ={{90}^{0}}\], we have
\[\Delta {{t}_{w}}=\dfrac{D\sin \theta }{{{v}_{w}}}=\dfrac{d}{{{v}_{w}}}\]
(c) now to find the apparent angle we can do that as, \[\Delta t=\dfrac{D\sin \theta }{v}=\dfrac{d}{{{v}_{w}}}\]
Solving for the angle \[\theta \]with \[{{v}_{w}}=1482m/s\] we get,
$\Rightarrow \theta ={{\sin }^{-1}}(\dfrac{v}{{{v}_{w}}}) \\
\Rightarrow \theta ={{\sin }^{-1}}(\dfrac{343}{1482}) \\$
$343m/s$ being the speed of sound in air,
$\Rightarrow {{\sin }^{-1}}(0.231) \\
\therefore {{13}^{0}} \\$
Note: Trigonometric ratios are unitless but angles can be measured either in degrees or radians. All the units to be taken in standard SI units of system. A wavefront is a surface over which a wave has a constant phase. Wavefront came into existence from Hygen’s theory of wave picture of light. Wavefront determines the nature and propagation of a light emanating from the given source.
One should always keep in mind that frequency is the characteristic of the source of the light
Recently Updated Pages
A steel rail of length 5m and area of cross section class 11 physics JEE_Main

At which height is gravity zero class 11 physics JEE_Main

A nucleus of mass m + Delta m is at rest and decays class 11 physics JEE_MAIN

A wave is travelling along a string At an instant the class 11 physics JEE_Main

The length of a conductor is halved its conductivity class 11 physics JEE_Main

Two billiard balls of the same size and mass are in class 11 physics JEE_Main

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Displacement-Time Graph and Velocity-Time Graph for JEE

Class 11 JEE Main Physics Mock Test 2025

Differentiate between audible and inaudible sounds class 11 physics JEE_Main

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

Units and Measurements Class 11 Notes: CBSE Physics Chapter 1

Motion in a Straight Line Class 11 Notes: CBSE Physics Chapter 2

NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements

NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line
