
Two solutions of $KN{{O}_{3}}$ and \[CH_{3}^{{}}COOH~\] are prepared separately. Molarity of both is $0.1M$ and osmotic pressures are \[{{P}_{1}}\] and \[{{P}_{2}}\] respectively. The correct relationship between the osmotic pressures is :
(A) \[{{P}_{2}}>{{P}_{1}}\]
(B) \[{{P}_{1}}={{P}_{2}}\]
(C) \[{{P}_{1}}>{{P}_{2}}\]
(D) $\frac{{{P}_{1}}}{{{P}_{1}}+{{P}_{2}}}=\frac{{{P}_{2}}}{{{P}_{1}}+{{P}_{2}}}$
Answer
221.7k+ views
Hint: The minimum pressure which is required to be applied to the solution to prevent the inward flow of the solvent across a semipermeable membrane is known as osmotic pressure. This process is known as osmosis. If there is no osmotic pressure, there will be no movement of solvent. It is a unidirectional process. It tends to make the concentration of solute across the two sides of the membrane equal.
Formula Used: The formula used to calculate the osmotic pressure of a solution is:
$P=icRT$; Where $i$= van’t hoff index
$c$= Concentration of solute
$R$= Gas constant
$T$= Temperature (Kelvin)
$P$= Osmotic pressure
Complete Step by Step Answer:
We will calculate the osmotic pressure for two solutions of $KN{{O}_{3}}$ and \[CH_{3}^{{}}COOH~\] each of concentration$0.1M$.
Osmotic Pressure of $0.1M$ $KN{{O}_{3}}$:
As $KN{{O}_{3}}$ is a strong electrolyte, it dissociates completely and gives 2 ions, so $i=2$
Thus, osmotic pressure will be
${{P}_{1}}=2\times 0.1\times R\times T$
${{P}_{1}}=0.2RT$
Osmotic Pressure of $0.1M$ \[CH_{3}^{{}}COOH~\]:
As \[CH_{3}^{{}}COOH~\] is a weak electrolyte, it does not dissociate completely, so $i=1$
Thus, osmotic pressure will be
${{P}_{2}}=1\times 0.1\times R\times T$
${{P}_{2}}=0.1RT$
We can observe that \[{{P}_{1}}>{{P}_{2}}\]
Correct Option: (C) \[{{P}_{1}}>{{P}_{2}}\].
Note: The process of osmosis is important for the human body. In the human body, osmosis occurs in the small and large intestines. It plays an important role in the gastro-intestinal system and kidneys. It helps in getting all the essential nutrients from our food and also removes the waste products from the blood.
Formula Used: The formula used to calculate the osmotic pressure of a solution is:
$P=icRT$; Where $i$= van’t hoff index
$c$= Concentration of solute
$R$= Gas constant
$T$= Temperature (Kelvin)
$P$= Osmotic pressure
Complete Step by Step Answer:
We will calculate the osmotic pressure for two solutions of $KN{{O}_{3}}$ and \[CH_{3}^{{}}COOH~\] each of concentration$0.1M$.
Osmotic Pressure of $0.1M$ $KN{{O}_{3}}$:
As $KN{{O}_{3}}$ is a strong electrolyte, it dissociates completely and gives 2 ions, so $i=2$
Thus, osmotic pressure will be
${{P}_{1}}=2\times 0.1\times R\times T$
${{P}_{1}}=0.2RT$
Osmotic Pressure of $0.1M$ \[CH_{3}^{{}}COOH~\]:
As \[CH_{3}^{{}}COOH~\] is a weak electrolyte, it does not dissociate completely, so $i=1$
Thus, osmotic pressure will be
${{P}_{2}}=1\times 0.1\times R\times T$
${{P}_{2}}=0.1RT$
We can observe that \[{{P}_{1}}>{{P}_{2}}\]
Correct Option: (C) \[{{P}_{1}}>{{P}_{2}}\].
Note: The process of osmosis is important for the human body. In the human body, osmosis occurs in the small and large intestines. It plays an important role in the gastro-intestinal system and kidneys. It helps in getting all the essential nutrients from our food and also removes the waste products from the blood.
Recently Updated Pages
JEE Main 2022 (July 26th Shift 1) Physics Question Paper with Answer Key

JEE Main 2022 (June 26th Shift 2) Chemistry Question Paper with Answer Key

Apparent Frequency Explained: Formula, Uses & Examples

JEE Main 2023 (January 30th Shift 2) Chemistry Question Paper with Answer Key

Displacement Current and Maxwell’s Equations Explained

JEE Main 2022 (June 29th Shift 1) Maths Question Paper with Answer Key

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

How to Convert a Galvanometer into an Ammeter or Voltmeter

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Other Pages
NCERT Solutions For Class 11 Chemistry Chapter 7 Redox Reaction

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Hydrocarbons Class 11 Chemistry Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Chemistry Chapter 5 CBSE Notes - 2025-26

NCERT Solutions ForClass 11 Chemistry Chapter Chapter 5 Thermodynamics

Equilibrium Class 11 Chemistry Chapter 6 CBSE Notes - 2025-26

