Answer
64.8k+ views
Hint: We know that the fringe width is the distance between the two dark fringes or bright fringes or two dark fringes successfully.
It is independent of order of all the fringes. Double slit experiment shows both energy and matter show both wave and particle characteristics.
Apply this logic to find the width with central maximum.
Formula used:
$\beta = \dfrac{{\lambda D}}{d}$
Here $d,D,\lambda $ is the distance between the slits, distance between the slit and screen and wavelength.
Complete step by step answer:
Two coherent sources of lights placed at a small distance apart are used in Young’s double slit experiment. Usually only magnitudes greater than wavelength of light is used.
Young’s double slit experiment helps in understanding the wave theory of light. A commonly used coherent source in the modern-day experiments is Laser.
Young’s double slit experiment firmly establishes that light behaves as a particle and wave.
The distance between the two bright fringes or two dark fringes successfully is said to fringe width. It is independent of order of all the fringes.
The brightest central fringe from a diffraction pattern on the screen is considered to be the central maxima. It has the maximum intensity than all other diffraction fringes.
Fringe separation is given by $\beta = \dfrac{{\lambda D}}{d}$
Here d is ${10^{ - 3}}m$
And $D = 1m$
Then the width of central maxima in a single slit experiment=$\dfrac{{2\lambda D}}{a}$
Fringe width in double slit experiment $\beta = \dfrac{{\lambda D}}{d}$
Hence, we have to obtain for 10 maxima of double slit
$\Rightarrow 10\beta = \dfrac{{2\lambda D}}{a}$
On putting the values and we get
$\Rightarrow 10\dfrac{{\lambda D}}{d} = \dfrac{{2\lambda D}}{a}$
Then, we can write it as
$\Rightarrow a = \dfrac{d}{5}mm = \dfrac{1}{5}mm = 0.2mm$
Hence Option C is the correct option.
Note: Later they conducted Young’s double slit experiment using electrons and the pattern generated a similar result as light. It behaves both as a particle and wave. Young’s double slit experiment shows both these characteristics prominently.
It is independent of order of all the fringes. Double slit experiment shows both energy and matter show both wave and particle characteristics.
Apply this logic to find the width with central maximum.
Formula used:
$\beta = \dfrac{{\lambda D}}{d}$
Here $d,D,\lambda $ is the distance between the slits, distance between the slit and screen and wavelength.
Complete step by step answer:
Two coherent sources of lights placed at a small distance apart are used in Young’s double slit experiment. Usually only magnitudes greater than wavelength of light is used.
Young’s double slit experiment helps in understanding the wave theory of light. A commonly used coherent source in the modern-day experiments is Laser.
Young’s double slit experiment firmly establishes that light behaves as a particle and wave.
The distance between the two bright fringes or two dark fringes successfully is said to fringe width. It is independent of order of all the fringes.
The brightest central fringe from a diffraction pattern on the screen is considered to be the central maxima. It has the maximum intensity than all other diffraction fringes.
Fringe separation is given by $\beta = \dfrac{{\lambda D}}{d}$
Here d is ${10^{ - 3}}m$
And $D = 1m$
Then the width of central maxima in a single slit experiment=$\dfrac{{2\lambda D}}{a}$
Fringe width in double slit experiment $\beta = \dfrac{{\lambda D}}{d}$
Hence, we have to obtain for 10 maxima of double slit
$\Rightarrow 10\beta = \dfrac{{2\lambda D}}{a}$
On putting the values and we get
$\Rightarrow 10\dfrac{{\lambda D}}{d} = \dfrac{{2\lambda D}}{a}$
Then, we can write it as
$\Rightarrow a = \dfrac{d}{5}mm = \dfrac{1}{5}mm = 0.2mm$
Hence Option C is the correct option.
Note: Later they conducted Young’s double slit experiment using electrons and the pattern generated a similar result as light. It behaves both as a particle and wave. Young’s double slit experiment shows both these characteristics prominently.
Recently Updated Pages
Write a composition in approximately 450 500 words class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Arrange the sentences P Q R between S1 and S5 such class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What is the common property of the oxides CONO and class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
If four points A63B 35C4 2 and Dx3x are given in such class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The area of square inscribed in a circle of diameter class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Other Pages
A boat takes 2 hours to go 8 km and come back to a class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Electric field due to uniformly charged sphere class 12 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
In the ground state an element has 13 electrons in class 11 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
According to classical free electron theory A There class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Excluding stoppages the speed of a bus is 54 kmph and class 11 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)