Answer
64.8k+ views
Hint: The force between the two charges depends upon the nature of the two charges, if the two charges are positive ions then there is repulsion between the two the charges and if they are negative charge ions then also there will be repulsion only for positive and negative charge ions there is attraction force.
Formula used:
The formula of the Coulomb's law is given by,
$F = k\dfrac{{{q_1} \times {q_2}}}{{{d^2}}}$
Where force is F, the charges are ${q_1}$ and ${q_2}$ also the distance between the charges is d.
Complete step by step solution:
It is given in the problem two positive ions, each carrying a charge q, are separated by a distance d if F is the force of repulsion between the ions then we need to find the number of electrons missing from each ion will be (e being the charge on an electron).
The formula of the Coulomb's law is given by,
$ \Rightarrow F = k\dfrac{{{q_1} \times {q_2}}}{{{d^2}}}$
Where force is F, the charges are ${q_1}$ and ${q_2}$ also the distance between the charges is d.
$ \Rightarrow F = k\dfrac{{{q_1} \times {q_2}}}{{{d^2}}}$
As both the charge, $q = ne$ and the distance is d. Therefore we get,
$ \Rightarrow {q_1} = {q_2} = ne$
$ \Rightarrow F = k\dfrac{{ne \times ne}}{{{d^2}}}$
$ \Rightarrow F = k\dfrac{{{n^2}{e^2}}}{{{d^2}}}$
$ \Rightarrow {n^2}{e^2} = \dfrac{{F \times {d^2}}}{k}$
$ \Rightarrow {n^2} = \dfrac{{F \times {d^2}}}{{k \times {e^2}}}$
$ \Rightarrow n = \sqrt {\dfrac{{F \times {d^2}}}{{k \times {e^2}}}} $.
Replacing the value of constant, $k = \dfrac{1}{{4\pi {\varepsilon _o}}}$ we get,
$ \Rightarrow n = \sqrt {\dfrac{{4\pi {\varepsilon _o} \times {d^2}}}{{{e^2}}}} $.
The number of electrons missing from each item is equal to $n = \sqrt {\dfrac{{4\pi {\varepsilon _o} \times {d^2}}}{{{e^2}}}} $. The nature of force is repulsion as both of the charges are electrons and therefore both charges will repel each other.
Note: The students should understand and remember the formula of coulomb's law as it is very helpful in solving problems like these. The force between two similar natured charges will always be repulsion and the force between two different natured charges will be attraction.
Formula used:
The formula of the Coulomb's law is given by,
$F = k\dfrac{{{q_1} \times {q_2}}}{{{d^2}}}$
Where force is F, the charges are ${q_1}$ and ${q_2}$ also the distance between the charges is d.
Complete step by step solution:
It is given in the problem two positive ions, each carrying a charge q, are separated by a distance d if F is the force of repulsion between the ions then we need to find the number of electrons missing from each ion will be (e being the charge on an electron).
The formula of the Coulomb's law is given by,
$ \Rightarrow F = k\dfrac{{{q_1} \times {q_2}}}{{{d^2}}}$
Where force is F, the charges are ${q_1}$ and ${q_2}$ also the distance between the charges is d.
$ \Rightarrow F = k\dfrac{{{q_1} \times {q_2}}}{{{d^2}}}$
As both the charge, $q = ne$ and the distance is d. Therefore we get,
$ \Rightarrow {q_1} = {q_2} = ne$
$ \Rightarrow F = k\dfrac{{ne \times ne}}{{{d^2}}}$
$ \Rightarrow F = k\dfrac{{{n^2}{e^2}}}{{{d^2}}}$
$ \Rightarrow {n^2}{e^2} = \dfrac{{F \times {d^2}}}{k}$
$ \Rightarrow {n^2} = \dfrac{{F \times {d^2}}}{{k \times {e^2}}}$
$ \Rightarrow n = \sqrt {\dfrac{{F \times {d^2}}}{{k \times {e^2}}}} $.
Replacing the value of constant, $k = \dfrac{1}{{4\pi {\varepsilon _o}}}$ we get,
$ \Rightarrow n = \sqrt {\dfrac{{4\pi {\varepsilon _o} \times {d^2}}}{{{e^2}}}} $.
The number of electrons missing from each item is equal to $n = \sqrt {\dfrac{{4\pi {\varepsilon _o} \times {d^2}}}{{{e^2}}}} $. The nature of force is repulsion as both of the charges are electrons and therefore both charges will repel each other.
Note: The students should understand and remember the formula of coulomb's law as it is very helpful in solving problems like these. The force between two similar natured charges will always be repulsion and the force between two different natured charges will be attraction.
Recently Updated Pages
Write a composition in approximately 450 500 words class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Arrange the sentences P Q R between S1 and S5 such class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What is the common property of the oxides CONO and class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
If four points A63B 35C4 2 and Dx3x are given in such class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The area of square inscribed in a circle of diameter class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Other Pages
A boat takes 2 hours to go 8 km and come back to a class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Electric field due to uniformly charged sphere class 12 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
In the ground state an element has 13 electrons in class 11 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
According to classical free electron theory A There class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Excluding stoppages the speed of a bus is 54 kmph and class 11 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)