
Two balls are thrown simultaneously in the air. The acceleration of the centre of mass of the two balls when in air,
A. Is equal to g (Acceleration due to gravity)
B. Depends on the masses of the two balls
C. Depends on the direction off motion of the two balls
D. Depends on the speeds of the two balls
Answer
232.8k+ views
Hint: Define centre of mass. Obtain the mathematical expression for acceleration of centre of mass. The acceleration on each ball thrown upward will be the acceleration due to gravity. Using these values on the equation for acceleration of centre of mass, we will get the required answer.
Complete step by step answer:
Centre of mass can be defined as a position of a system of masses where the weighted relative position of masses sums to zero.
Acceleration of the centre of mass of a system of mass can be expressed mathematically as,
$\begin{align}
& {{a}_{cm}}=\dfrac{{{a}_{1}}{{m}_{1}}+{{a}_{2}}{{m}_{2}}+{{a}_{3}}{{m}_{3}}+......+{{a}_{n}}{{m}_{n}}}{{{m}_{1}}+{{m}_{2}}+.....+{{m}_{n}}} \\
& {{a}_{cm}}M={{a}_{1}}{{m}_{1}}+{{a}_{2}}{{m}_{2}}+{{a}_{3}}{{m}_{3}}+......+{{a}_{n}}{{m}_{n}} \\
\end{align}$
Where, ${{a}_{cm}}$ is the acceleration of the centre of mass of the system.
Here, ${{a}_{1}}{{m}_{1}}$ is the net force on particle 1 and so on and ${{a}_{cm}}M$ is the force on the centre of mass of the system if all the mass is located at the COM of the system.
Now, in the above question, we have two balls thrown upward.
Let the mass of the balls are ${{m}_{1}}$ and ${{m}_{2}}$ .
Now, when we throw an object upward, gravity acts on it and the acceleration acts on it will be negative of acceleration due to gravity i.e. deceleration.
So, the acceleration on each ball will be g.
Applying these to the equation for acceleration of centre of mass,
$\begin{align}
& {{a}_{cm}}=\dfrac{{{m}_{1}}g+{{m}_{2}}g}{{{m}_{1}}+{{m}_{2}}} \\
& {{a}_{cm}}=\dfrac{\left( {{m}_{1}}+{{m}_{2}} \right)g}{{{m}_{1}}+{{m}_{2}}} \\
& {{a}_{cm}}=g \\
\end{align}$
So, the acceleration of the centre of mass of the two balls thrown upward will be g.
The correct option is (A).
Note: If we consider any number of balls or particles thrown upward, then also the acceleration for centre of mass will be g. This is because the acceleration acting on each ball will be equal to acceleration due to gravity and the acceleration on the centre of mass will be also equal to g.
Complete step by step answer:
Centre of mass can be defined as a position of a system of masses where the weighted relative position of masses sums to zero.
Acceleration of the centre of mass of a system of mass can be expressed mathematically as,
$\begin{align}
& {{a}_{cm}}=\dfrac{{{a}_{1}}{{m}_{1}}+{{a}_{2}}{{m}_{2}}+{{a}_{3}}{{m}_{3}}+......+{{a}_{n}}{{m}_{n}}}{{{m}_{1}}+{{m}_{2}}+.....+{{m}_{n}}} \\
& {{a}_{cm}}M={{a}_{1}}{{m}_{1}}+{{a}_{2}}{{m}_{2}}+{{a}_{3}}{{m}_{3}}+......+{{a}_{n}}{{m}_{n}} \\
\end{align}$
Where, ${{a}_{cm}}$ is the acceleration of the centre of mass of the system.
Here, ${{a}_{1}}{{m}_{1}}$ is the net force on particle 1 and so on and ${{a}_{cm}}M$ is the force on the centre of mass of the system if all the mass is located at the COM of the system.
Now, in the above question, we have two balls thrown upward.
Let the mass of the balls are ${{m}_{1}}$ and ${{m}_{2}}$ .
Now, when we throw an object upward, gravity acts on it and the acceleration acts on it will be negative of acceleration due to gravity i.e. deceleration.
So, the acceleration on each ball will be g.
Applying these to the equation for acceleration of centre of mass,
$\begin{align}
& {{a}_{cm}}=\dfrac{{{m}_{1}}g+{{m}_{2}}g}{{{m}_{1}}+{{m}_{2}}} \\
& {{a}_{cm}}=\dfrac{\left( {{m}_{1}}+{{m}_{2}} \right)g}{{{m}_{1}}+{{m}_{2}}} \\
& {{a}_{cm}}=g \\
\end{align}$
So, the acceleration of the centre of mass of the two balls thrown upward will be g.
The correct option is (A).
Note: If we consider any number of balls or particles thrown upward, then also the acceleration for centre of mass will be g. This is because the acceleration acting on each ball will be equal to acceleration due to gravity and the acceleration on the centre of mass will be also equal to g.
Recently Updated Pages
JEE Main 2023 April 6 Shift 1 Question Paper with Answer Key

JEE Main 2023 April 6 Shift 2 Question Paper with Answer Key

JEE Main 2023 (January 31 Evening Shift) Question Paper with Solutions [PDF]

JEE Main 2023 January 30 Shift 2 Question Paper with Answer Key

JEE Main 2023 January 25 Shift 1 Question Paper with Answer Key

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Key

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Laws of Motion Class 11 Physics Chapter 4 CBSE Notes - 2025-26

Waves Class 11 Physics Chapter 14 CBSE Notes - 2025-26

Mechanical Properties of Fluids Class 11 Physics Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Physics Chapter 11 CBSE Notes - 2025-26

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

