Answer
64.8k+ views
Hint We are given the situation of three blocks of equal masses put up in a certain configuration and are asked to find the tension of the string connecting two of the three blocks. Thus, we will just apply the basics of force and mass configuration.
Complete Step By Step Solution
Here,
For the tension and gravitational force on the block$I$, we get
$T - mg = ma$
Putting the values of mass, we get
$T - 3g = 3a$
Thus, we get
$T = 3a + 3g \cdot \cdot \cdot \cdot \cdot \cdot \left( 1 \right)$
Now,
For the blocks$II$ and$III$, we get
$2mg - T = 2ma$
Putting in the values of mass, we get
$6g - T = 6a$
Further, using equation$(1)$, we get
$6g - 3a - 3g = 6a$
After further evaluation, we get
$3g = 9a$
Then, we get
$a = \dfrac{g}{3}$
Now,
The $T$we considered till now is the net tension of the string.
Now,
We will take $T'$ as the tension between the blocks$II$ and$III$.
Thus, the equation will be
$mg - T' = ma$
Further, putting in the values, we get
$3g - T' = 3a$
Further, we get
$T' = 3g - 3a$
Thus, putting the evaluated value of$a$, we get
$T' = 3g - 3\left( {\dfrac{g}{3}} \right)$
Then we get
$T' = 2g$
Putting the value of$g$, we get
$T' = 2 \times 10 = 20N$
Hence, the correct option is (D).
Additional Information The diagram we are considering is called the free body diagram which shows us the bodies and the forces acting on it. The equations we are forming are on the basis of the fundamental idea that all the external forces are in balance for an isolated body.
Note The tension of the string will hold the blocks in equilibrium and will determine the motion of the blocks as the string moves on the pulley. But the tension of the string between the two blocks will make sure that while the motion of the block, the block remains in equilibrium.
Complete Step By Step Solution
Here,
For the tension and gravitational force on the block$I$, we get
$T - mg = ma$
Putting the values of mass, we get
$T - 3g = 3a$
Thus, we get
$T = 3a + 3g \cdot \cdot \cdot \cdot \cdot \cdot \left( 1 \right)$
Now,
For the blocks$II$ and$III$, we get
$2mg - T = 2ma$
Putting in the values of mass, we get
$6g - T = 6a$
Further, using equation$(1)$, we get
$6g - 3a - 3g = 6a$
After further evaluation, we get
$3g = 9a$
Then, we get
$a = \dfrac{g}{3}$
Now,
The $T$we considered till now is the net tension of the string.
Now,
We will take $T'$ as the tension between the blocks$II$ and$III$.
Thus, the equation will be
$mg - T' = ma$
Further, putting in the values, we get
$3g - T' = 3a$
Further, we get
$T' = 3g - 3a$
Thus, putting the evaluated value of$a$, we get
$T' = 3g - 3\left( {\dfrac{g}{3}} \right)$
Then we get
$T' = 2g$
Putting the value of$g$, we get
$T' = 2 \times 10 = 20N$
Hence, the correct option is (D).
Additional Information The diagram we are considering is called the free body diagram which shows us the bodies and the forces acting on it. The equations we are forming are on the basis of the fundamental idea that all the external forces are in balance for an isolated body.
Note The tension of the string will hold the blocks in equilibrium and will determine the motion of the blocks as the string moves on the pulley. But the tension of the string between the two blocks will make sure that while the motion of the block, the block remains in equilibrium.
Recently Updated Pages
Write a composition in approximately 450 500 words class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Arrange the sentences P Q R between S1 and S5 such class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What is the common property of the oxides CONO and class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
If four points A63B 35C4 2 and Dx3x are given in such class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The area of square inscribed in a circle of diameter class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Other Pages
Excluding stoppages the speed of a bus is 54 kmph and class 11 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
In the ground state an element has 13 electrons in class 11 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Electric field due to uniformly charged sphere class 12 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
A boat takes 2 hours to go 8 km and come back to a class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
According to classical free electron theory A There class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)