
There are three Newton’s laws of motion namely first, second and third laws. We can derive
A. Second and third laws from the first law
B. First and second laws from the third law
C. Third and first laws from the second law
D. All the three laws are independent of each other.
Answer
136.5k+ views
Hint Newton's first law states that the object at rest or in other words it is in motion will remain unless the object relates a net external force But the newton's Second Law of Motion relates force, mass, and acceleration.
Complete step by step solution
Newton’s second law of motions states that the net force applied on a body is equal to the rate of change in its Momentum.
We know that, $F = ma$
$a = v - \dfrac{u}{t}$
Substitute, $F = m\left( {v - \dfrac{u}{t}} \right)$
Simplify, $Ft = mv - mu.$
Now, when $F = 0$then $v = u.$ This shows the absence of the force. So, the object continues with the same velocity.
Now, when $F = 0$ and $u = 0$,then $v = 0.$That is, an object at rest if no force is acting on it.
Therefore, first law is derived from the second law.
Now, let us consider a system of two bodies, one and two bodies, there is no force acting on it.
Now ${F_{12}}$ be the force acting on 2 by 1 and ${F_{21}}$ be the force acting on 1 by 2.
The rate of change of the momentum of $1 = \dfrac{{d{p_1}}}{{dt}}$ and the rate of change of the momentum of $2 = \dfrac{{d{p_2}}}{{dt}}$.
Adding both, we get
$\dfrac{{d\left( {{p_2} + {p_1}} \right)}}{{dt}}$
Therefore, the momentum change will also be 0 change in velocity occurs.
Therefore, ${F_{12}} + {F_{21}} = 0.$
Thus, Newton’s third law is proved with Newton’s second law.
Therefore, Newton’s first and second laws with second law.
Hence, from the above options, option C is correct.
Note Newton’s first law states that the body states at rest, if it is at rest and moves with a constant velocity if already moving, until a net force is applied to it. In other words, the state of motion of the body changes only on application of a net non-Zero force.
Complete step by step solution
Newton’s second law of motions states that the net force applied on a body is equal to the rate of change in its Momentum.
We know that, $F = ma$
$a = v - \dfrac{u}{t}$
Substitute, $F = m\left( {v - \dfrac{u}{t}} \right)$
Simplify, $Ft = mv - mu.$
Now, when $F = 0$then $v = u.$ This shows the absence of the force. So, the object continues with the same velocity.
Now, when $F = 0$ and $u = 0$,then $v = 0.$That is, an object at rest if no force is acting on it.
Therefore, first law is derived from the second law.
Now, let us consider a system of two bodies, one and two bodies, there is no force acting on it.
Now ${F_{12}}$ be the force acting on 2 by 1 and ${F_{21}}$ be the force acting on 1 by 2.
The rate of change of the momentum of $1 = \dfrac{{d{p_1}}}{{dt}}$ and the rate of change of the momentum of $2 = \dfrac{{d{p_2}}}{{dt}}$.
Adding both, we get
$\dfrac{{d\left( {{p_2} + {p_1}} \right)}}{{dt}}$
Therefore, the momentum change will also be 0 change in velocity occurs.
Therefore, ${F_{12}} + {F_{21}} = 0.$
Thus, Newton’s third law is proved with Newton’s second law.
Therefore, Newton’s first and second laws with second law.
Hence, from the above options, option C is correct.
Note Newton’s first law states that the body states at rest, if it is at rest and moves with a constant velocity if already moving, until a net force is applied to it. In other words, the state of motion of the body changes only on application of a net non-Zero force.
Recently Updated Pages
Uniform Acceleration - Definition, Equation, Examples, and FAQs

JEE Main 2021 July 25 Shift 2 Question Paper with Answer Key

JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 20 Shift 2 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

How to find Oxidation Number - Important Concepts for JEE

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

A body crosses the topmost point of a vertical circle class 11 physics JEE_Main

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Degree of Dissociation and Its Formula With Solved Example for JEE

At which height is gravity zero class 11 physics JEE_Main

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Motion in a Straight Line Class 11 Notes: CBSE Physics Chapter 2

Units and Measurements Class 11 Notes: CBSE Physics Chapter 1

Important Questions for CBSE Class 11 Physics Chapter 1 - Units and Measurement

NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements

NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line
