
There are three Newton’s laws of motion namely first, second and third laws. We can derive
A. Second and third laws from the first law
B. First and second laws from the third law
C. Third and first laws from the second law
D. All the three laws are independent of each other.
Answer
217.5k+ views
Hint Newton's first law states that the object at rest or in other words it is in motion will remain unless the object relates a net external force But the newton's Second Law of Motion relates force, mass, and acceleration.
Complete step by step solution
Newton’s second law of motions states that the net force applied on a body is equal to the rate of change in its Momentum.
We know that, $F = ma$
$a = v - \dfrac{u}{t}$
Substitute, $F = m\left( {v - \dfrac{u}{t}} \right)$
Simplify, $Ft = mv - mu.$
Now, when $F = 0$then $v = u.$ This shows the absence of the force. So, the object continues with the same velocity.
Now, when $F = 0$ and $u = 0$,then $v = 0.$That is, an object at rest if no force is acting on it.
Therefore, first law is derived from the second law.
Now, let us consider a system of two bodies, one and two bodies, there is no force acting on it.
Now ${F_{12}}$ be the force acting on 2 by 1 and ${F_{21}}$ be the force acting on 1 by 2.
The rate of change of the momentum of $1 = \dfrac{{d{p_1}}}{{dt}}$ and the rate of change of the momentum of $2 = \dfrac{{d{p_2}}}{{dt}}$.
Adding both, we get
$\dfrac{{d\left( {{p_2} + {p_1}} \right)}}{{dt}}$
Therefore, the momentum change will also be 0 change in velocity occurs.
Therefore, ${F_{12}} + {F_{21}} = 0.$
Thus, Newton’s third law is proved with Newton’s second law.
Therefore, Newton’s first and second laws with second law.
Hence, from the above options, option C is correct.
Note Newton’s first law states that the body states at rest, if it is at rest and moves with a constant velocity if already moving, until a net force is applied to it. In other words, the state of motion of the body changes only on application of a net non-Zero force.
Complete step by step solution
Newton’s second law of motions states that the net force applied on a body is equal to the rate of change in its Momentum.
We know that, $F = ma$
$a = v - \dfrac{u}{t}$
Substitute, $F = m\left( {v - \dfrac{u}{t}} \right)$
Simplify, $Ft = mv - mu.$
Now, when $F = 0$then $v = u.$ This shows the absence of the force. So, the object continues with the same velocity.
Now, when $F = 0$ and $u = 0$,then $v = 0.$That is, an object at rest if no force is acting on it.
Therefore, first law is derived from the second law.
Now, let us consider a system of two bodies, one and two bodies, there is no force acting on it.
Now ${F_{12}}$ be the force acting on 2 by 1 and ${F_{21}}$ be the force acting on 1 by 2.
The rate of change of the momentum of $1 = \dfrac{{d{p_1}}}{{dt}}$ and the rate of change of the momentum of $2 = \dfrac{{d{p_2}}}{{dt}}$.
Adding both, we get
$\dfrac{{d\left( {{p_2} + {p_1}} \right)}}{{dt}}$
Therefore, the momentum change will also be 0 change in velocity occurs.
Therefore, ${F_{12}} + {F_{21}} = 0.$
Thus, Newton’s third law is proved with Newton’s second law.
Therefore, Newton’s first and second laws with second law.
Hence, from the above options, option C is correct.
Note Newton’s first law states that the body states at rest, if it is at rest and moves with a constant velocity if already moving, until a net force is applied to it. In other words, the state of motion of the body changes only on application of a net non-Zero force.
Recently Updated Pages
Elastic Collision in Two Dimensions Explained Simply

Elastic Collisions in One Dimension Explained

Electric Field Due to a Uniformly Charged Ring Explained

Electric Field of Infinite Line Charge and Cylinders Explained

Electric Flux and Area Vector Explained Simply

Electric Field of a Charged Spherical Shell Explained

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 11 Physics Chapter 8 Mechanical Properties Of Solids

Motion in a Straight Line Class 11 Physics Chapter 2 CBSE Notes - 2025-26

NCERT Solutions for Class 11 Physics Chapter 7 Gravitation 2025-26

Understanding Atomic Structure for Beginners

