Answer
64.8k+ views
Hint: Le Chatelier’s principle states that when a system in equilibrium is disturbed by changing the concentrations, changing pressure, changing the temperature, the system shifts its equilibrium, to balance the change of variables.
Complete step by step answer:
The given chemical reaction is
${{\text{N}}_{\text{2}}}{\text{ + 3}}{{\text{H}}_{\text{2}}}{\text{ }} \rightleftharpoons {\text{ 2N}}{{\text{H}}_{\text{3}}};{\text{ }}\Delta H{\text{ = - 22}}{\text{.08kcal }}$
According to Le Chatelier’s principle, there are various factors like a concentration of reactant and product, pressure and temperature affects the position of equilibrium and thus the yield of the product.
The effect of change in concentration of ${{\text{N}}_{\text{2}}}$ on yield of ${\text{N}}{{\text{H}}_{\text{3}}}$ is as follows:
An increase in the concentration of the reactant shifts the equilibrium to the product side while a decrease in the concentration of the reactant shifts the equilibrium to the reactant side.
Similarly, an increase in the concentration of products shifts the equilibrium to the reactant side while a decrease in the concentration of products shifts the equilibrium to the product side.
In the reaction given to us, ${{\text{N}}_{\text{2}}}$ is a reactant, so a change in concentration of ${{\text{N}}_{\text{2}}}$ affects the yield of ${\text{N}}{{\text{H}}_{\text{3}}}$. It will increase or decrease due to an increase or decrease in the concentration of ${{\text{N}}_{\text{2}}}$.
The effect of change in temperature on the yield of ${\text{N}}{{\text{H}}_{\text{3}}}$ is as follows:
The negative value of enthalpy of reaction ($\Delta H{\text{ = - 22}}{\text{.08kcal }}$$\Delta H$) indicates that this is an exothermic reaction. Reactions that evolve heat energy are known as exothermic reactions.
In the case of an exothermic reaction, an increase in temperature shifts the equilibrium to the reactant side while a decrease in temperature shifts the equilibrium to the product side. Thus, an increase in temperature will decrease the yield of ${\text{N}}{{\text{H}}_{\text{3}}}$ while a decrease in temperature will increase the yield of${\text{N}}{{\text{H}}_{\text{3}}}$.
Thus, a change in temperature affects the yield of${\text{N}}{{\text{H}}_{\text{3}}}$.
Effect of change in pressure on yield of ${\text{N}}{{\text{H}}_{\text{3}}}$ is as follows:
According to Le Chatelier’s principle, an increase in pressure by decreasing volume, shifts the equilibrium to the side of fewer numbers of moles of gas. While a decrease in pressure by increasing volume shifts the equilibrium to the side of greater numbers of moles of gas.
${{\text{N}}_{\text{2}}}{\text{ + 3}}{{\text{H}}_{\text{2}}}{\text{ }} \rightleftharpoons {\text{ 2N}}{{\text{H}}_{\text{3}}};{\text{ }}\Delta H{\text{ = - 22}}{\text{.08kcal }}$
$4{\text{ moles 2 moles}}$
Here, moles of gaseous reactants are greater than moles of a gaseous product. So an increase in the pressure by decreasing volume will increase the yield of ${\text{N}}{{\text{H}}_{\text{3}}}$ while a decrease in the pressure by increasing volume will decrease the yield of ${\text{N}}{{\text{H}}_{\text{3}}}$.
Thus, a change in pressure affects the yield of ${\text{N}}{{\text{H}}_{\text{3}}}$.
Hence, the correct answer is option (D) .
Note:
The system where the rate of forward reaction and the backward reaction is equal is said to be at a state of equilibrium. Change in reaction condition that changes in temperature, pressure and concentration changes the position of equilibrium and affects the yield of the product.
Complete step by step answer:
The given chemical reaction is
${{\text{N}}_{\text{2}}}{\text{ + 3}}{{\text{H}}_{\text{2}}}{\text{ }} \rightleftharpoons {\text{ 2N}}{{\text{H}}_{\text{3}}};{\text{ }}\Delta H{\text{ = - 22}}{\text{.08kcal }}$
According to Le Chatelier’s principle, there are various factors like a concentration of reactant and product, pressure and temperature affects the position of equilibrium and thus the yield of the product.
The effect of change in concentration of ${{\text{N}}_{\text{2}}}$ on yield of ${\text{N}}{{\text{H}}_{\text{3}}}$ is as follows:
An increase in the concentration of the reactant shifts the equilibrium to the product side while a decrease in the concentration of the reactant shifts the equilibrium to the reactant side.
Similarly, an increase in the concentration of products shifts the equilibrium to the reactant side while a decrease in the concentration of products shifts the equilibrium to the product side.
In the reaction given to us, ${{\text{N}}_{\text{2}}}$ is a reactant, so a change in concentration of ${{\text{N}}_{\text{2}}}$ affects the yield of ${\text{N}}{{\text{H}}_{\text{3}}}$. It will increase or decrease due to an increase or decrease in the concentration of ${{\text{N}}_{\text{2}}}$.
The effect of change in temperature on the yield of ${\text{N}}{{\text{H}}_{\text{3}}}$ is as follows:
The negative value of enthalpy of reaction ($\Delta H{\text{ = - 22}}{\text{.08kcal }}$$\Delta H$) indicates that this is an exothermic reaction. Reactions that evolve heat energy are known as exothermic reactions.
In the case of an exothermic reaction, an increase in temperature shifts the equilibrium to the reactant side while a decrease in temperature shifts the equilibrium to the product side. Thus, an increase in temperature will decrease the yield of ${\text{N}}{{\text{H}}_{\text{3}}}$ while a decrease in temperature will increase the yield of${\text{N}}{{\text{H}}_{\text{3}}}$.
Thus, a change in temperature affects the yield of${\text{N}}{{\text{H}}_{\text{3}}}$.
Effect of change in pressure on yield of ${\text{N}}{{\text{H}}_{\text{3}}}$ is as follows:
According to Le Chatelier’s principle, an increase in pressure by decreasing volume, shifts the equilibrium to the side of fewer numbers of moles of gas. While a decrease in pressure by increasing volume shifts the equilibrium to the side of greater numbers of moles of gas.
${{\text{N}}_{\text{2}}}{\text{ + 3}}{{\text{H}}_{\text{2}}}{\text{ }} \rightleftharpoons {\text{ 2N}}{{\text{H}}_{\text{3}}};{\text{ }}\Delta H{\text{ = - 22}}{\text{.08kcal }}$
$4{\text{ moles 2 moles}}$
Here, moles of gaseous reactants are greater than moles of a gaseous product. So an increase in the pressure by decreasing volume will increase the yield of ${\text{N}}{{\text{H}}_{\text{3}}}$ while a decrease in the pressure by increasing volume will decrease the yield of ${\text{N}}{{\text{H}}_{\text{3}}}$.
Thus, a change in pressure affects the yield of ${\text{N}}{{\text{H}}_{\text{3}}}$.
Hence, the correct answer is option (D) .
Note:
The system where the rate of forward reaction and the backward reaction is equal is said to be at a state of equilibrium. Change in reaction condition that changes in temperature, pressure and concentration changes the position of equilibrium and affects the yield of the product.
Recently Updated Pages
Write a composition in approximately 450 500 words class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Arrange the sentences P Q R between S1 and S5 such class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What is the common property of the oxides CONO and class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
If four points A63B 35C4 2 and Dx3x are given in such class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The area of square inscribed in a circle of diameter class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Other Pages
A boat takes 2 hours to go 8 km and come back to a class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
In the ground state an element has 13 electrons in class 11 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Electric field due to uniformly charged sphere class 12 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
According to classical free electron theory A There class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Excluding stoppages the speed of a bus is 54 kmph and class 11 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)