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The work done on an object does not depend on the:
(A) displacement
(B) angle between force and displacement
(C) force applied
(D) initial velocity of the object

Last updated date: 21st Apr 2024
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Hint We should know that work, in physics, measure of energy transfer that occurs when an object is moved over a distance by an external force at least part of which is applied in the direction of the displacement. Work is done when a force that is applied to an object moves that object. The work is calculated by multiplying the force by the amount of movement of an object. if there is no motion in the direction of the force, then no work is done by that force. If the displacement of the object is zero, then one can calculate the work done by each individual force, the work done by each force is zero. Work is not defined in terms of what would have happened to the object in the absence of other forces; it is defined in terms of the motion that actually occurred.

Complete step by step answer We know that, $W=F\cdot d\cos 0$.
Here, $\mathrm{F}=$ force applied on the object,
$\mathrm{d}=$ displacement and 0 is angle between force and displacement.
So, the work done on an object does not depend upon the initial velocity of the object.

Therefore, the correct answer is Option D.

Note We can conclude that when the force and displacement are in the same direction, we call the work positive. In the opposite direction, we call the work negative. An isobaric expansion of a gas requires heat transfer to keep the pressure constant. An isochoric process is one in which the volume is held constant, meaning that the work done by the system will be zero. Work done is maximum in an adiabatic process.