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**Hint**Compare the given voltage of the alternating current with the trigonometric formula, the change in the voltage provides the answer for the maximum voltage of the alternating current. Use the formula of the angular velocity of the wave to find the maximum frequency of the alternating current.

Useful formula:

(1) The trigonometric formula is given by

$\sin 2\theta = 2\sin \theta \cos \theta $

(2) The formula of the angular velocity is given by

$\omega = 2\pi f$

Where $\omega $ is the angular velocity and $f$ is the frequency of the alternating current.

**Complete step by step answer**

It is given that the

Voltage of the alternating current supply, $V = 60\sin 50\pi t.\cos 50\pi t$

Let us apply the formula of the $\sin 2\theta $ in the above voltage,

$\sin 2\left( {50\pi t} \right) = 2\sin 50\pi t.\cos 50\pi t$ ---------(1)

But the given voltage is $V = 60\sin 50\pi t.\cos 50\pi t$ ------(2)

Comparing (1) and (2), all are the same except the constant before the trigonometric parameters. Hence the maximum voltage is obtained by dividing them as $\dfrac{{60}}{2} = 30\,V$ .

Hence the maximum voltage of the given voltage of the alternating current is obtained as $30\,V$ .

Let us use the formula of the angular velocity,

$\omega = 2\pi f$

Rearranging the above formula in order to find the frequency.

$f = \dfrac{\omega }{{2\pi }}$

Substituting the $\omega = 100\pi $ in the above formula, we get

$f = \dfrac{{100\pi }}{{2\pi }}$

By simplifying the above step, we get

$f = 50\pi $

Hence the maximum frequency of the alternating current of the given voltage is $50\pi $ .

**Thus the option (D) is correct.**

**Note:**The frequency will be maximum only when the angular velocity of the given wave will be maximum. The angular velocity will be maximum at twice the theta of the voltage. Hence the angular velocity is obtained by $2 \times 50\pi $ , which is equal to $100\pi $ .

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