The time taken by a photoelectron to come out after the photon strikes is approximately.
(A) ${10^{ - 1}}\,s$
(B) ${10^{ - 2}}\,s$
(C) ${10^{ - 10}}\,s$
(D) ${10^{ - 16}}\,s$
Answer
288.6k+ views
Hint To find the correct option, you first of all need to know that even though the kinetic energy does depend upon the energy of the incident light beam, but the time taken by a photoelectron to come out after the photon of the incident light beam strikes is not dependent
Complete step by step answer
As it is apparent from the given options as well as explained in the hint section of the solution to the asked question, the time taken by a photoelectron to come out after the photon strikes is almost constant no matter what incident light rays of any intensity you use. Even though the maximum kinetic energy achieved by the photoelectrons will differ as the intensity and frequency of the incident light rays vary, the time by the photoelectron to come out would not vary since it is independent of the intensity and frequency of the incident light beams. The only necessary condition for photoelectrons to come out is that the frequency of the incident light rays is higher than the threshold frequency of the material of the plate being used. Note that this also gives us an insight that the time taken by the photoelectrons to come out does not depend on the material of the plate being used either and is independent of literally every factor that could have affected it.
As we can see it being cited in many study material and published articles and science pages, the time taken by a photoelectron to come out after the photon strikes is almost constant and is equal to ${10^{ - 10}}\,s$ approximately. This has been witnessed in multiple experiments and has been proven to be a fact and a stepping stone in the study of photoelectric effect, giving us a major stand on the fact that light rays and the material of the plate cannot change the time taken by the photoelectron to come out once the sufficient energy is given to it by the incident photons of the incident light rays.
Hence, the correct option is option (C).
Note The only major confusion would have been if there was another option saying that the time depends on the intensity of the incident light rays as many students will believe that more energized light ray will cause the electrons to come out faster. Which is a wrong notion as more energized light rays or photons only affect the maximum kinetic energy but not the time taken to come out.
Complete step by step answer
As it is apparent from the given options as well as explained in the hint section of the solution to the asked question, the time taken by a photoelectron to come out after the photon strikes is almost constant no matter what incident light rays of any intensity you use. Even though the maximum kinetic energy achieved by the photoelectrons will differ as the intensity and frequency of the incident light rays vary, the time by the photoelectron to come out would not vary since it is independent of the intensity and frequency of the incident light beams. The only necessary condition for photoelectrons to come out is that the frequency of the incident light rays is higher than the threshold frequency of the material of the plate being used. Note that this also gives us an insight that the time taken by the photoelectrons to come out does not depend on the material of the plate being used either and is independent of literally every factor that could have affected it.
As we can see it being cited in many study material and published articles and science pages, the time taken by a photoelectron to come out after the photon strikes is almost constant and is equal to ${10^{ - 10}}\,s$ approximately. This has been witnessed in multiple experiments and has been proven to be a fact and a stepping stone in the study of photoelectric effect, giving us a major stand on the fact that light rays and the material of the plate cannot change the time taken by the photoelectron to come out once the sufficient energy is given to it by the incident photons of the incident light rays.
Hence, the correct option is option (C).
Note The only major confusion would have been if there was another option saying that the time depends on the intensity of the incident light rays as many students will believe that more energized light ray will cause the electrons to come out faster. Which is a wrong notion as more energized light rays or photons only affect the maximum kinetic energy but not the time taken to come out.
Recently Updated Pages
JEE Main 2025-26 Mock Test: Properties of Solids and Liquids

JEE Main Mock Test 2025-26: Thermodynamics Practice & Tips

JEE Main 2025-26 Mock Test: Properties of Solids & Liquids

JEE Main 2025-26 Electromagnetic Waves Mock Test with Solutions

JEE Main 2025-26: Electromagnetic Induction & Alternating Currents Mock Test

Kinetic Theory Of Gases JEE Main Mock Test 2025-26

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Understanding the Electric Field of a Uniformly Charged Ring

Electron Gain Enthalpy and Electron Affinity Explained

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
CBSE Class 12 Physics Question Paper 2026: Download SET-wise PDF with Answer Key & Analysis

JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

JEE Advanced 2026 Notification Out with Exam Date, Registration (Extended), Syllabus and More

JEE Advanced Weightage Chapter Wise 2026 for Physics, Chemistry, and Mathematics

Dual Nature of Radiation and Matter Class 12 Physics Chapter 11 CBSE Notes - 2026-27 PDF Download (Login Required)

Hybridisation in Chemistry – Concept, Types & Applications

