The time taken by a photoelectron to come out after the photon strikes is approximately.
(A) ${10^{ - 1}}\,s$
(B) ${10^{ - 2}}\,s$
(C) ${10^{ - 10}}\,s$
(D) ${10^{ - 16}}\,s$
Answer
292.8k+ views
Hint To find the correct option, you first of all need to know that even though the kinetic energy does depend upon the energy of the incident light beam, but the time taken by a photoelectron to come out after the photon of the incident light beam strikes is not dependent
Complete step by step answer
As it is apparent from the given options as well as explained in the hint section of the solution to the asked question, the time taken by a photoelectron to come out after the photon strikes is almost constant no matter what incident light rays of any intensity you use. Even though the maximum kinetic energy achieved by the photoelectrons will differ as the intensity and frequency of the incident light rays vary, the time by the photoelectron to come out would not vary since it is independent of the intensity and frequency of the incident light beams. The only necessary condition for photoelectrons to come out is that the frequency of the incident light rays is higher than the threshold frequency of the material of the plate being used. Note that this also gives us an insight that the time taken by the photoelectrons to come out does not depend on the material of the plate being used either and is independent of literally every factor that could have affected it.
As we can see it being cited in many study material and published articles and science pages, the time taken by a photoelectron to come out after the photon strikes is almost constant and is equal to ${10^{ - 10}}\,s$ approximately. This has been witnessed in multiple experiments and has been proven to be a fact and a stepping stone in the study of photoelectric effect, giving us a major stand on the fact that light rays and the material of the plate cannot change the time taken by the photoelectron to come out once the sufficient energy is given to it by the incident photons of the incident light rays.
Hence, the correct option is option (C).
Note The only major confusion would have been if there was another option saying that the time depends on the intensity of the incident light rays as many students will believe that more energized light ray will cause the electrons to come out faster. Which is a wrong notion as more energized light rays or photons only affect the maximum kinetic energy but not the time taken to come out.
Complete step by step answer
As it is apparent from the given options as well as explained in the hint section of the solution to the asked question, the time taken by a photoelectron to come out after the photon strikes is almost constant no matter what incident light rays of any intensity you use. Even though the maximum kinetic energy achieved by the photoelectrons will differ as the intensity and frequency of the incident light rays vary, the time by the photoelectron to come out would not vary since it is independent of the intensity and frequency of the incident light beams. The only necessary condition for photoelectrons to come out is that the frequency of the incident light rays is higher than the threshold frequency of the material of the plate being used. Note that this also gives us an insight that the time taken by the photoelectrons to come out does not depend on the material of the plate being used either and is independent of literally every factor that could have affected it.
As we can see it being cited in many study material and published articles and science pages, the time taken by a photoelectron to come out after the photon strikes is almost constant and is equal to ${10^{ - 10}}\,s$ approximately. This has been witnessed in multiple experiments and has been proven to be a fact and a stepping stone in the study of photoelectric effect, giving us a major stand on the fact that light rays and the material of the plate cannot change the time taken by the photoelectron to come out once the sufficient energy is given to it by the incident photons of the incident light rays.
Hence, the correct option is option (C).
Note The only major confusion would have been if there was another option saying that the time depends on the intensity of the incident light rays as many students will believe that more energized light ray will cause the electrons to come out faster. Which is a wrong notion as more energized light rays or photons only affect the maximum kinetic energy but not the time taken to come out.
Recently Updated Pages
The average and RMS value of voltage for square waves class 12 physics JEE_Main

The force between two short electric dipoles placed class 12 physics JEE_Main

The force of interaction of two dipoles if the two class 12 physics JEE_Main

The value of current through 2Omega resistor is A 10A class 12 physics JEE_MAin

when an object Is placed at a distance of 60 cm from class 12 physics JEE_Main

Formula for number of images formed by two plane mirrors class 12 physics JEE_Main

Trending doubts
Electron Gain Enthalpy and Electron Affinity Explained

What Are Current and Potential Difference in Electricity?

Understanding the Angle of Deviation in a Prism

Isoelectronic Species: Definition, Examples & Importance

Understanding Average and RMS Value in Electrical Circuits

Units and Measurements Mock Test for JEE Main 2026-27 Preparation

Other Pages
JEE Advanced 2026 Notification Out with Exam Date, Registration (Extended), Syllabus and More

Understanding Collisions: Types and Examples for Students

Class 12 Physics Formulas: Complete Chapter-wise PDF Guide

Understanding Inertial and Non-Inertial Frames of Reference

What Are Elastic Collisions in One Dimension?

Electric field due to uniformly charged sphere class 12 physics JEE_Main

