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# The shielding constant for ${}_{30}Zn$ is:A) 25.65B) 15.65C)25.35D) 10.35

Last updated date: 19th Apr 2024
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Hint: Slater's rule is used to calculate shielding constant.

Formula used- $= (0.35 \times n) + (0.85 \times m) + (1.00 \times p)$ where n is number of electrons in n shell, m is number of electrons in n-1 shell, p is number of electrons in the remaining inner shells.

Complete step by step answer:
Write the electronic configuration of Zinc
Atomic number of Zinc is 30
Hence its electronic configuration is$1{s^2},2{s^2}2{p^6},3{s^2}3{p^6},3{d^{10}},4{s^2}$
Find the number of electrons in n shell.
In the given case, n=4 and the number of electrons is 2. But we will take only 1 electron.
Find number of electrons in n-1 shell.
There are 18 electrons in the third shell.
Find the number of electrons in the remaining inner shells
The remaining inner shells include the first and second shell. There are 10 electrons in the first and second shell.
Calculate the shielding constant using slater’s rule
Shielding effect =$(0.35 \times 1) + (0.85 \times 18) + (1.00 \times 10) = 25.65$

Option A is correct.