The relation between volume V, pressure P and absolute temperature T of an ideal gas is PV=XT, where X is a constant. The value of X depends upon
A. the mass of gas molecule
B. the average kinetic energy of the gas molecules
C. p, V and T
D. The number of gas molecules in V
Answer
256.2k+ views
Hint First, we will derive the ideal gas equation using the different laws such as Boyle’s law, Charles’s law and Avogadro’s law. Then we will equate the both equations and find the value of x.
Complete step-by-step solution The ideal gas law is the equation of state of ideal gas.
Derivation of ideal gas equation
Let pressure exerted by the gas=P, Temperature=T, Volume of the gas=V, moles=n, universal gas constant=R
Acc. To Boyle’s law,
It states that volume is inversely proportional to pressure given temperature remains the same.
\[V \propto \dfrac{1}{P}\]
Acc. To Charle’s law,
It states that volume of the gas occupied is directly proportional to temperature given pressure is constant.
\[V \propto T\]
Acc. To Avogadro’s law ,
\[V \propto n\]
Combining all three equations
\[V \propto \dfrac{{nT}}{P}\]
Ideal gas equation,
\[PV = nRT\] , R= Universal Gas Constant=8.314J/mol-K ……(1)
We are given that
\[PV = xT\] …….(2)
Comparing the two equations
\[x = nR\]
\[n = \dfrac{N}{{{N_a}}}\] , N= number of molecules of the gas
\[{N_a}\] = Avogadro’s number
So \[{N_a}\] and R are constant
x depends upon N= number of molecules of gas
option(d) the number of gas molecules in V
Note
1. No gas is the ideal gas, it is a good approximation of the behaviour of many gases under various conditions but these are under several limitations.
2. The ideal gas model depends on some assumptions such as molecules of gas are small spheres, indistinguishable. All collisions are elastic.
Complete step-by-step solution The ideal gas law is the equation of state of ideal gas.
Derivation of ideal gas equation
Let pressure exerted by the gas=P, Temperature=T, Volume of the gas=V, moles=n, universal gas constant=R
Acc. To Boyle’s law,
It states that volume is inversely proportional to pressure given temperature remains the same.
\[V \propto \dfrac{1}{P}\]
Acc. To Charle’s law,
It states that volume of the gas occupied is directly proportional to temperature given pressure is constant.
\[V \propto T\]
Acc. To Avogadro’s law ,
\[V \propto n\]
Combining all three equations
\[V \propto \dfrac{{nT}}{P}\]
Ideal gas equation,
\[PV = nRT\] , R= Universal Gas Constant=8.314J/mol-K ……(1)
We are given that
\[PV = xT\] …….(2)
Comparing the two equations
\[x = nR\]
\[n = \dfrac{N}{{{N_a}}}\] , N= number of molecules of the gas
\[{N_a}\] = Avogadro’s number
So \[{N_a}\] and R are constant
x depends upon N= number of molecules of gas
option(d) the number of gas molecules in V
Note
1. No gas is the ideal gas, it is a good approximation of the behaviour of many gases under various conditions but these are under several limitations.
2. The ideal gas model depends on some assumptions such as molecules of gas are small spheres, indistinguishable. All collisions are elastic.
Recently Updated Pages
Electricity and Magnetism Explained: Key Concepts & Applications

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

JEE Main 2023 (February 1st Shift 1) Maths Question Paper with Answer Key

JEE Main 2023 (February 1st Shift 2) Maths Question Paper with Answer Key

JEE Main 2023 (February 1st Shift 2) Chemistry Question Paper with Answer Key

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Colleges 2026: Complete List of Participating Institutes

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Hybridisation in Chemistry – Concept, Types & Applications

Other Pages
JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

CBSE Notes Class 11 Physics Chapter 1 - Units And Measurements - 2025-26

NCERT Solutions For Class 11 Physics Chapter 1 Units And Measurements - 2025-26

Important Questions For Class 11 Physics Chapter 1 Units and Measurement - 2025-26

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

