
The primary winding of a transformer has 500 turns whereas its secondary has 5000 turns. The primary is connected to an ac supply of 20V, 50Hz. The secondary will have an output of:
A) $2V, 5Hz$
B) $20V, 5Hz$
C) $200V, 50Hz$
D) $20V, 500Hz$
Answer
123.9k+ views
Hint: Assuming ideal conditions of the Transformer we have a ratio of primary side induced voltage to the secondary side induced voltage (induced voltage is equal to supply voltage) is equal to the ratio of turns of the primary and secondary winding.
$\dfrac{{{V_1}}}{{{V_2}}} = \dfrac{{{N_1}}}{{{N_2}}}$ (Where V1 and V2 are the voltages of primary and secondary side, similarly N1 and N2 are the number of turns of primary and secondary side)
Using the above relation we will find the voltage of the secondary side.
Complete step by step solution:
Let’s discuss a few points about transformers and then we will proceed for the calculation part.
Transformer is a static device which works on the principle of electromagnetic induction. A single phase transformer has two windings primary and secondary winding .Winding having large number of turns have high voltage and the winding having less number of turns have low voltage, because voltage in a winding is directly proportional to the number of turns it has. An ideal transformer has negligible or no losses.
Now we will do the calculation for secondary side voltage:
$\dfrac{{{V_1}}}{{{V_2}}} = \dfrac{{{N_1}}}{{{N_2}}}$.....................(1)
We are being provided with primary side supply voltage, turns and turns of secondary side.
Let’s substitute the value of each in equation 1 and find the value of secondary voltage.
$
\Rightarrow \dfrac{{20}}{{{V_2}}} = \dfrac{{500}}{{5000}} \\
\Rightarrow {V_2} = \dfrac{{20 \times 50}}{5} \\
$(Rearranging the terms for secondary side voltage)
$ \Rightarrow {V_2} = 200$
Secondary side voltage comes out to be 200 Volts
Frequency remains constant in the transformer;
Therefore, option (C) is correct.
Note: Transformer has two types of core named core type and shell type. Transformer core is generally made up of high permeability and low loss material like CRGO silicon steel (cold rolled grain oriented). Shell type transformers are used for low voltage applications while core type transformers are used for high voltage applications.
$\dfrac{{{V_1}}}{{{V_2}}} = \dfrac{{{N_1}}}{{{N_2}}}$ (Where V1 and V2 are the voltages of primary and secondary side, similarly N1 and N2 are the number of turns of primary and secondary side)
Using the above relation we will find the voltage of the secondary side.
Complete step by step solution:
Let’s discuss a few points about transformers and then we will proceed for the calculation part.
Transformer is a static device which works on the principle of electromagnetic induction. A single phase transformer has two windings primary and secondary winding .Winding having large number of turns have high voltage and the winding having less number of turns have low voltage, because voltage in a winding is directly proportional to the number of turns it has. An ideal transformer has negligible or no losses.
Now we will do the calculation for secondary side voltage:
$\dfrac{{{V_1}}}{{{V_2}}} = \dfrac{{{N_1}}}{{{N_2}}}$.....................(1)
We are being provided with primary side supply voltage, turns and turns of secondary side.
Let’s substitute the value of each in equation 1 and find the value of secondary voltage.
$
\Rightarrow \dfrac{{20}}{{{V_2}}} = \dfrac{{500}}{{5000}} \\
\Rightarrow {V_2} = \dfrac{{20 \times 50}}{5} \\
$(Rearranging the terms for secondary side voltage)
$ \Rightarrow {V_2} = 200$
Secondary side voltage comes out to be 200 Volts
Frequency remains constant in the transformer;
Therefore, option (C) is correct.
Note: Transformer has two types of core named core type and shell type. Transformer core is generally made up of high permeability and low loss material like CRGO silicon steel (cold rolled grain oriented). Shell type transformers are used for low voltage applications while core type transformers are used for high voltage applications.
Recently Updated Pages
Young's Double Slit Experiment Step by Step Derivation

Difference Between Circuit Switching and Packet Switching

Difference Between Mass and Weight

JEE Main Participating Colleges 2024 - A Complete List of Top Colleges

JEE Main Maths Paper Pattern 2025 – Marking, Sections & Tips

Sign up for JEE Main 2025 Live Classes - Vedantu

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility & More

JEE Main Exam Marking Scheme: Detailed Breakdown of Marks and Negative Marking

JEE Main 2023 January 24 Shift 2 Question Paper with Answer Keys & Solutions

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

JEE Main 2025: Conversion of Galvanometer Into Ammeter And Voltmeter in Physics

Electric field due to uniformly charged sphere class 12 physics JEE_Main

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

Dual Nature of Radiation and Matter Class 12 Notes: CBSE Physics Chapter 11

Physics Average Value and RMS Value JEE Main 2025

Degree of Dissociation and Its Formula With Solved Example for JEE

JEE Main 2025: Derivation of Equation of Trajectory in Physics
