The preparation of alkyl fluoride from alkyl chloride, in presence of metallic fluoride is known as:
(A) Williamson’s synthesis
(B) Finkelstein reaction
(C) Swarts reaction
(D) Wurtz reaction
Answer
267.3k+ views
Hint:Here metallic fluoride means ‘MF’ where M is the metal. Preparation of alkyl fluoride from alkyl chloride reaction is a nucleophilic substitution reaction.
Complete step by step solution:
> Williamson synthesis: It is an organic reaction, forming ether from an organohalide and a de-protonated alcohol (alkoxide). An example:
\[~{{\left[ Na \right]}^{+}}{{[{{C}_{2}}{{H}_{5}}O]}^{-}}~+\text{ }{{C}_{2}}{{H}_{5}}Cl\text{ }\to \text{ }{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}~+\text{ }{{\left[ Na \right]}^{+}}\left[ Cl \right]\]
> Finkelstein reaction: A\[{{S}_{N}}2\] reaction in which one halogen atom (the leaving group) is replaced by another halogen atom (the nucleophile). In this example of the Finkelstein reaction, 1-chloro-2-phenylethane is treated with sodium iodide to produce 1-iodo-2-phenylethane.
> Swarts Reaction: It is generally used to get alkyl fluorides from alkyl chlorides or alkyl bromides. This is done by heating of the alkyl chloride/bromide in the presence of the fluoride of some heavy metals (\[AgF\], \[H{{g}_{2}}{{F}_{2}}\]).
\[R-X+AgF\to R-F+AgX\]
> Wurtz reaction: It is an organic chemical coupling reaction wherein sodium metal (Na) is reacted with two alkyl halides in the environment provided by a solution of dry ether in order to form a higher alkane along with a compound containing sodium and the halogen.
The main difference between Finkelstein reaction and Swarts reaction is that the end product of Finkelstein reaction is alkyl iodide whereas the end product of Swarts reaction is alkyl fluoride.
So, from the above explanation we can say that the correct option is “C”.
Note: And here the Wurtz reaction is limited to the synthesis of symmetric alkanes. If two dissimilar alkyl halides are taken as reactants, then the product is a mixture of alkanes. Don’t get confused between Finkelstein reaction and Swarts Reactions because they have different products.
Complete step by step solution:
> Williamson synthesis: It is an organic reaction, forming ether from an organohalide and a de-protonated alcohol (alkoxide). An example:
\[~{{\left[ Na \right]}^{+}}{{[{{C}_{2}}{{H}_{5}}O]}^{-}}~+\text{ }{{C}_{2}}{{H}_{5}}Cl\text{ }\to \text{ }{{C}_{2}}{{H}_{5}}O{{C}_{2}}{{H}_{5}}~+\text{ }{{\left[ Na \right]}^{+}}\left[ Cl \right]\]
> Finkelstein reaction: A\[{{S}_{N}}2\] reaction in which one halogen atom (the leaving group) is replaced by another halogen atom (the nucleophile). In this example of the Finkelstein reaction, 1-chloro-2-phenylethane is treated with sodium iodide to produce 1-iodo-2-phenylethane.
> Swarts Reaction: It is generally used to get alkyl fluorides from alkyl chlorides or alkyl bromides. This is done by heating of the alkyl chloride/bromide in the presence of the fluoride of some heavy metals (\[AgF\], \[H{{g}_{2}}{{F}_{2}}\]).
\[R-X+AgF\to R-F+AgX\]
> Wurtz reaction: It is an organic chemical coupling reaction wherein sodium metal (Na) is reacted with two alkyl halides in the environment provided by a solution of dry ether in order to form a higher alkane along with a compound containing sodium and the halogen.
The main difference between Finkelstein reaction and Swarts reaction is that the end product of Finkelstein reaction is alkyl iodide whereas the end product of Swarts reaction is alkyl fluoride.
So, from the above explanation we can say that the correct option is “C”.
Note: And here the Wurtz reaction is limited to the synthesis of symmetric alkanes. If two dissimilar alkyl halides are taken as reactants, then the product is a mixture of alkanes. Don’t get confused between Finkelstein reaction and Swarts Reactions because they have different products.
Recently Updated Pages
States of Matter Chapter For JEE Main Chemistry

Types of Solutions in Chemistry: Explained Simply

Difference Between Crystalline and Amorphous Solid: Table & Examples

Know The Difference Between Fluid And Liquid

[Awaiting the three content sources: Ask AI Response, Competitor 1 Content, and Competitor 2 Content. Please provide those to continue with the analysis and optimization.]

Sign up for JEE Main 2026 Live Classes - Vedantu

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

Understanding Atomic Structure for Beginners

Other Pages
JEE Advanced 2026 Notification Out with Exam Date, Registration (Extended), Syllabus and More

JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

JEE Advanced 2026 Marks vs Rank: Estimate IIT Rank from Your Score

JEE Advanced Weightage Chapter Wise 2026 for Physics, Chemistry, and Mathematics

NCERT Solutions For Class 11 Chemistry In Hindi Chapter 1 Some Basic Concepts Of Chemistry - 2025-26

How to Convert a Galvanometer into an Ammeter or Voltmeter

