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The peak voltage in a 220 V, 50 Hz AC source is:
(A) 220 V
(B) About 160 V
(C) About 310 V
(D) 440 V

Last updated date: 23rd Apr 2024
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Hint: To answer this question we need to know the formula to find the peak voltage. This formula develops in a relationship with the rated voltage. Once we find the formula we can put the values mentioned in the question to get the desired answer. The answer should be the closest to one among the mentioned options.

Complete step by step answer:
We know that voltage rating is the most rms also known as root mean square value of the voltage.
So we can write the formula of peak voltage as:
${V_{peak}} = \sqrt 2 {V_{rated}}$
Now we have to put the value in the above formula to get that:
$\sqrt 2 {V_{rated}} = \sqrt 2 \times 220 = 311V$
So we can say that the peak voltage in a 220 V, 50 Hz Ac source is 311 V.

Hence option C is the answer.

Note: For a better understanding we need to define the term peak voltage. By peak voltage, we mean the highest point or we can also say numerically the highest value of the voltage in case of any voltage waveform.
We have also seen the mentioning of the term rms value. By rms value we mean the value which is the most efficient value of the total waveform. The rms value also known as the Root Mean Square signifies the level of the DC signal which would provide the same amount of mean power as that of the periodic signal.