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The oxidation number of the nitrogen atom in the ammonium ion is: A. +3B. +2C. +1D. -2E. -3

Last updated date: 19th Sep 2024
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Hint: Oxidation number of every atom must be known to calculate the oxidation number of an atom. We assume the atom for which the oxidation number is to be calculated as “x”.

Complete step-by-step solution:
We know that the charge of a hydrogen atom is +1 and there are four hydrogen atoms so we will take four +1 charges. Now, we need to calculate the oxidation number of Nitrogen now. So, we take the oxidation number of Nitrogen as “x”.
$\begin{array}{l}\mathop {\rm{N}}\limits^{\rm{x}} {\mathop {\rm{H}}\limits^{ + 1} _{\rm{4}}} = 1\\ \Rightarrow {\rm{x}} + 4 \times (1) = 4\\ \Rightarrow x = - 3\end{array}$
So, we can conclude that the oxidation number of nitrogen is -3. Therefore, out of the given five options, E is the correct option. Options A, B, C and D are incorrect.