
The number of significant figures in \[6.02 \times {10^{23}}\] is :
A. 23
B. 3
C. 4
D. 26
Answer
220.5k+ views
Hint: Significant figures in any expression or numeral or decimal are just the number of significant digits from 0-9. When a number is expressed in scientific notation, the expressions in which all the zeros to the right-hand side of the decimal point are significant.
Complete Step by Step Solution:
Whether a number is significant or not is governed by some rules. One of the rules states that non-zero numbers are significant.
If we consider the number 55.78, there is a count of four significant figures.
Another rule states that if zeroes are there between any no.of significant numbers then the zeroes have significance.
So, for the given question, 6.02 has a total of four significant digits as the zero between six and two is also considered a significant number.
When numbers are expressed in scientific notation, these expressions of all the zeros to the right-hand side of the decimal point are significant.
For instance, \[6.5 \times {10^3}\] has two significant figures.
\[6.50 \times {10^3}\] has three significant figures.
Lastly, \[6.500 \times {10^3}\] has four significant figures.
So, the no.of significant numbers in \[6.02 \times {10^{23}}\] is 3.
So, option B is correct.
Note: Exact numbers have or demonstrate an infinite number of significant figures. For instance, in 60 pencils or 100 copies, there are unlimited significant figures present as these are exact numbers and can be indicated or represented by documenting an unlimited no.of zeros after positioning a decimal i.e. 50 = 50.000000 or 100 = 100.000000.
Complete Step by Step Solution:
Whether a number is significant or not is governed by some rules. One of the rules states that non-zero numbers are significant.
If we consider the number 55.78, there is a count of four significant figures.
Another rule states that if zeroes are there between any no.of significant numbers then the zeroes have significance.
So, for the given question, 6.02 has a total of four significant digits as the zero between six and two is also considered a significant number.
When numbers are expressed in scientific notation, these expressions of all the zeros to the right-hand side of the decimal point are significant.
For instance, \[6.5 \times {10^3}\] has two significant figures.
\[6.50 \times {10^3}\] has three significant figures.
Lastly, \[6.500 \times {10^3}\] has four significant figures.
So, the no.of significant numbers in \[6.02 \times {10^{23}}\] is 3.
So, option B is correct.
Note: Exact numbers have or demonstrate an infinite number of significant figures. For instance, in 60 pencils or 100 copies, there are unlimited significant figures present as these are exact numbers and can be indicated or represented by documenting an unlimited no.of zeros after positioning a decimal i.e. 50 = 50.000000 or 100 = 100.000000.
Recently Updated Pages
The hybridization and shape of NH2 ion are a sp2 and class 11 chemistry JEE_Main

What is the pH of 001 M solution of HCl a 1 b 10 c class 11 chemistry JEE_Main

Aromatization of nhexane gives A Benzene B Toluene class 11 chemistry JEE_Main

Show how you will synthesise i 1Phenylethanol from class 11 chemistry JEE_Main

The enolic form of acetone contains a 10sigma bonds class 11 chemistry JEE_Main

Which of the following Compounds does not exhibit tautomerism class 11 chemistry JEE_Main

Trending doubts
JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Understanding Electromagnetic Waves and Their Importance

Understanding Collisions: Types and Examples for Students

Understanding Entropy Changes in Different Processes

Common Ion Effect: Concept, Applications, and Problem-Solving

Other Pages
NCERT Solutions For Class 11 Chemistry Chapter 9 Hydrocarbons

What Are Elastic Collisions in One Dimension?

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Free Radical Substitution and Its Stepwise Mechanism

Understanding Geostationary and Geosynchronous Satellites

NCERT Solutions For Class 11 Chemistry Chapter 7 Equilibrium in Hindi - 2025-26

