
The number of AM broadcasting stations that can be accommodated in a 100 kHz bandwidth if the highest frequency modulating a carrier is 5 kHz are
(A) 5
(B) 7
(C) 20
(D) 10
Answer
232.8k+ views
Hint: Bandwidth is basically the total space which can be allotted with carrier waves. A wave being modulated will produce the same frequency of lower and upper bands. So, we will need double space in the bandwidth to accommodate that wave.
Complete step by step solution
Given: Bandwidth (B.W.) = 100 kHz
\[{f_m}\] = Highest modulation frequency = 5 kHz
We know,
$B.W. = 2n{f_m}$ ……(i)
Where, B.W. = Bandwidth.
n = Number of AM broadcasting stations.
\[{f_m}\] = Highest modulation frequency.
Putting the value of B.W. and \[{f_m}\] in equation (i) we get
$100kHz = 2n \times 5kHz$
Cross multiplying, we get
$n = \dfrac{{100}}{{10}} = 10$ .
(Option D)
Additional information:
The need for modulating a wave are as follows-
(i) In case of direct transmission there is a possibility of signals from different stations getting lost or mixed up.
(ii) Direct transmission requires an antenna of abnormal size.
(iii) It is limited to only a short distance.
Note above formula gives the maximum number amplitude modulated broadcasting stations in a given bandwidth. There are three types of modulation
(i) Amplitude modulation: In this case the amplitude of a high frequency wave is varied in accordance with the instantaneous value of a low frequency signal. The high frequency wave is called a carrier wave and the low frequency wave is called the modulating voltage.
(ii) Frequency modulation: In this case the frequency of the carrier wave is varied in accordance with the instantaneous value of the modulating signal. This is advantageous because all man made and atmospheric disturbances cause variation in the amplitude to the carrier wave which is eliminated in case of frequency modulation.
(iii) Phase modulation: In this case the phase of the carrier wave is varied in accordance with the instantaneous value of the modulating signal.
Complete step by step solution
Given: Bandwidth (B.W.) = 100 kHz
\[{f_m}\] = Highest modulation frequency = 5 kHz
We know,
$B.W. = 2n{f_m}$ ……(i)
Where, B.W. = Bandwidth.
n = Number of AM broadcasting stations.
\[{f_m}\] = Highest modulation frequency.
Putting the value of B.W. and \[{f_m}\] in equation (i) we get
$100kHz = 2n \times 5kHz$
Cross multiplying, we get
$n = \dfrac{{100}}{{10}} = 10$ .
(Option D)
Additional information:
The need for modulating a wave are as follows-
(i) In case of direct transmission there is a possibility of signals from different stations getting lost or mixed up.
(ii) Direct transmission requires an antenna of abnormal size.
(iii) It is limited to only a short distance.
Note above formula gives the maximum number amplitude modulated broadcasting stations in a given bandwidth. There are three types of modulation
(i) Amplitude modulation: In this case the amplitude of a high frequency wave is varied in accordance with the instantaneous value of a low frequency signal. The high frequency wave is called a carrier wave and the low frequency wave is called the modulating voltage.
(ii) Frequency modulation: In this case the frequency of the carrier wave is varied in accordance with the instantaneous value of the modulating signal. This is advantageous because all man made and atmospheric disturbances cause variation in the amplitude to the carrier wave which is eliminated in case of frequency modulation.
(iii) Phase modulation: In this case the phase of the carrier wave is varied in accordance with the instantaneous value of the modulating signal.
Recently Updated Pages
Dimensions of Charge: Dimensional Formula, Derivation, SI Units & Examples

How to Calculate Moment of Inertia: Step-by-Step Guide & Formulas

Circuit Switching vs Packet Switching: Key Differences Explained

Dimensions of Pressure in Physics: Formula, Derivation & SI Unit

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2026: Session 2 Registration Open, City Intimation Slip, Exam Dates, Syllabus & Eligibility

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Understanding the Angle of Deviation in a Prism

Hybridisation in Chemistry – Concept, Types & Applications

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Laws of Motion Class 11 Physics Chapter 4 CBSE Notes - 2025-26

Waves Class 11 Physics Chapter 14 CBSE Notes - 2025-26

Mechanical Properties of Fluids Class 11 Physics Chapter 9 CBSE Notes - 2025-26

Thermodynamics Class 11 Physics Chapter 11 CBSE Notes - 2025-26

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

