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# What will be the normality of a solution obtained by mixing 200ml of pure water to 100ml of 0.2N HCl solution?(A) 0.4N(B) 0.5N(C) 1.05N(D) 0.0667N

Last updated date: 17th Apr 2024
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Hint: To answer this question, we must focus on the concept of normality and how to calculate it. Normality can be described as the number of gram or mole equivalents of solute present in one liter of a solution.

Complete step by step solution:
To calculate the volume of a definite solution required to prepare solution of other Normality, we use the following equation:
${N_1}{V_1} = {N_2}{V_2}$
This equation is valid for any number of solutions of different concentrations that we need to mix together.
Where,
${N_1}$= initial normality
${V_1}$= initial volume
${N_2}$= Normality of the new solution.
${V_2}$= Volume of new solution.
From the question we get,
${N_1}$=0.2N of HCl
${V_1}$=100ml
${V_2}$=200ml of water + 100ml of Hydrochloric acid = 300ml
Substituting these values in the formula we get,
${N_2} = \dfrac{{{N_1}{V_1}}}{{{V_2}}} = \dfrac{{0.2 \times 100}}{{300}} = 0.667N$

Hence, the correct answer is Option (D) 0.667N.