
The maximum compression produced in a spring of force constant k, when a block of weight W moving with velocity v on a frictionless horizontal surface compresses it, shall be:
\({\rm{A) v}}\dfrac{{\sqrt {\rm{w}} }}{{\sqrt {\rm{k}} }}\\{\rm{B) v}}\dfrac{{\sqrt {\rm{k}} }}{{\sqrt {\rm{w}} }}\\{\rm{C) v}}\dfrac{{\sqrt {\rm{w}} }}{{\sqrt {{\rm{k}}{\rm{.g}}} }}\\{\rm{D) v}}\dfrac{{\sqrt {{\rm{k}}{\rm{.g}}} }}{{\sqrt {\rm{w}} }}\)
Answer
216.6k+ views
Hint: When the spring is compressed the kinetic energy increases and the elastic potential energy decreases. The total amount of these two forms of mechanical energy remains constant. Mechanical energy is being converted from potential form to kinetic form, thus saving the total amount.
Complete step by step solution:
\({\rm{so}}\dfrac{{\rm{1}}}{{\rm{2}}}{\rm{m}}{{\rm{v}}^{\rm{2}}}{\rm{ = }}\dfrac{{\rm{1}}}{{\rm{2}}}{\rm{k}}{{\rm{x}}^{\rm{2}}}\\x = \sqrt {\dfrac{{m{v^2}}}{k}} \)
From conservation of energy
KE lost by the block = PE gained by the spring
\(\Rightarrow \dfrac{{\rm{1}}}{{\rm{2}}}{\rm{m}}{{\rm{v}}^{\rm{2}}}{\rm{ = }}\dfrac{{\rm{1}}}{{\rm{2}}}{\rm{k}}{{\rm{x}}^{\rm{2}}}\\ \Rightarrow x = \sqrt {\dfrac{{{\rm{m}}{{\rm{v}}^{\rm{2}}}}}{{\rm{k}}}} \\ \Rightarrow \sqrt {\dfrac{{{\rm{W}}{{\rm{v}}^{\rm{2}}}}}{{{\rm{gk}}}}} \\\therefore {\rm{\text{maximum compression} = v}}\sqrt {\dfrac{{\rm{W}}}{{{\rm{kg}}}}} \)
So option C is correct.
Additional Information: Compression springs are open-coil helical springs wound or built to resist compression along the wind axis. Helical compression is the most common metal spring configuration. These coil springs can operate independently, although often assembled on a guide rod or fitted inside a hole.
When we place a load on a compression coil spring, make it shorter, push it back against the load and try to get it back to its original length. Compression springs offer linear compressive force (push) resistance and are in fact one of the most effective energy storage devices.
Compression springs are found in a wide range of applications, from automotive engines and large stamping presses to lawn mowers to major appliances and medical devices, cell phones, electronics, and sensitive instrumentation devices. The most basic installation anywhere requires a push button. Conical type springs are typically used in applications required for low concrete height and increased resistance.
Note: When a spring is compressed, the spring is worked by external agent forces. Suppose this task is accomplished by a moving object that initially moves to its equilibrium position [position A] in a spring so that the moving object loses momentum (eventually comes to rest) it acts in the spring to contract [position B].
As the spring shrinks and the mass slows down, its kinetic energy changes to elastic potential energy. As this changes, the total amount of mechanical energy is conserved.
Complete step by step solution:
\({\rm{so}}\dfrac{{\rm{1}}}{{\rm{2}}}{\rm{m}}{{\rm{v}}^{\rm{2}}}{\rm{ = }}\dfrac{{\rm{1}}}{{\rm{2}}}{\rm{k}}{{\rm{x}}^{\rm{2}}}\\x = \sqrt {\dfrac{{m{v^2}}}{k}} \)
From conservation of energy
KE lost by the block = PE gained by the spring
\(\Rightarrow \dfrac{{\rm{1}}}{{\rm{2}}}{\rm{m}}{{\rm{v}}^{\rm{2}}}{\rm{ = }}\dfrac{{\rm{1}}}{{\rm{2}}}{\rm{k}}{{\rm{x}}^{\rm{2}}}\\ \Rightarrow x = \sqrt {\dfrac{{{\rm{m}}{{\rm{v}}^{\rm{2}}}}}{{\rm{k}}}} \\ \Rightarrow \sqrt {\dfrac{{{\rm{W}}{{\rm{v}}^{\rm{2}}}}}{{{\rm{gk}}}}} \\\therefore {\rm{\text{maximum compression} = v}}\sqrt {\dfrac{{\rm{W}}}{{{\rm{kg}}}}} \)
So option C is correct.
Additional Information: Compression springs are open-coil helical springs wound or built to resist compression along the wind axis. Helical compression is the most common metal spring configuration. These coil springs can operate independently, although often assembled on a guide rod or fitted inside a hole.
When we place a load on a compression coil spring, make it shorter, push it back against the load and try to get it back to its original length. Compression springs offer linear compressive force (push) resistance and are in fact one of the most effective energy storage devices.
Compression springs are found in a wide range of applications, from automotive engines and large stamping presses to lawn mowers to major appliances and medical devices, cell phones, electronics, and sensitive instrumentation devices. The most basic installation anywhere requires a push button. Conical type springs are typically used in applications required for low concrete height and increased resistance.
Note: When a spring is compressed, the spring is worked by external agent forces. Suppose this task is accomplished by a moving object that initially moves to its equilibrium position [position A] in a spring so that the moving object loses momentum (eventually comes to rest) it acts in the spring to contract [position B].
As the spring shrinks and the mass slows down, its kinetic energy changes to elastic potential energy. As this changes, the total amount of mechanical energy is conserved.
Recently Updated Pages
JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

Electricity and Magnetism Explained: Key Concepts & Applications

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 11 Physics Chapter 8 Mechanical Properties Of Solids

Motion in a Straight Line Class 11 Physics Chapter 2 CBSE Notes - 2025-26

NCERT Solutions for Class 11 Physics Chapter 7 Gravitation 2025-26

Understanding Atomic Structure for Beginners

