
The magnification for a mirror is -3. How are u and v related?
Answer
218.1k+ views
Hint: Before we understand the concept of magnification in a mirror, it is important to understand the magnification is only possible in curved mirrors. In plane mirrors, the magnification is always 1 which means that the image is not enlarged or diminished in a plane mirror and always has the same size of the object. Hence, we have to consider curved mirrors only.
Complete step by step answer:
Magnification of the image is defined as the ratio of height of the image produced by the curved mirror to the ratio of height of the object.
Let us consider an object AB of height ${h_0}$ and distance -u from the pole P placed between centre of curvature C and focus F in front of a concave mirror as shown:

There are two rays emerging from the object.
i) First ray, parallel to the principal axis PA, after reflection, passes through focus.
ii) Second ray, passing through focus, after reflection, passes parallel to the principal axis.
These two rays meet beyond the centre of curvature C, to form the image GH of height ${h_i}$ at distance of -v from the pole.
Consider the triangles ABP and GHP.
$\Rightarrow \angle PAB = \angle PGH = {90^ \circ }$
By the law of reflection that incident angle equal to reflected angle, we have –
$\Rightarrow \angle APB = \angle GPH$
Hence, we can prove that the triangles ABP and GHP are similar.
By rule of similarity, we can say that –
$\Rightarrow \dfrac{{GH}}{{AB}} = \dfrac{{\left( { - v} \right)}}{{\left( { - u} \right)}}$
$ \Rightarrow \dfrac{{GH}}{{AB}} = \dfrac{v}{u}$
Given that $AB = {h_0}$ and $GH = - {h_i}$ (the negative sign is because the height of image is measured downwards direction)
Magnification is equal to the ratio of height of image of height of object.
$\Rightarrow m = \dfrac{{ - {h_i}}}{{{h_0}}}$
Substituting,
$\Rightarrow m = - \dfrac{v}{u}$
Therefore, magnification is defined as the ratio of v to u with a minus sign.
Note: The formula for the magnification in a lens is the same as that of a mirror, but only in the magnitude. The magnification formula for lenses has a positive sign while the magnification formula for a mirror has a negative sign.
Magnification for lens –
$m = \dfrac{v}{u}$
The students must understand the clear distinction between the two so that there is no confusion between the two formulae.
Complete step by step answer:
Magnification of the image is defined as the ratio of height of the image produced by the curved mirror to the ratio of height of the object.
Let us consider an object AB of height ${h_0}$ and distance -u from the pole P placed between centre of curvature C and focus F in front of a concave mirror as shown:

There are two rays emerging from the object.
i) First ray, parallel to the principal axis PA, after reflection, passes through focus.
ii) Second ray, passing through focus, after reflection, passes parallel to the principal axis.
These two rays meet beyond the centre of curvature C, to form the image GH of height ${h_i}$ at distance of -v from the pole.
Consider the triangles ABP and GHP.
$\Rightarrow \angle PAB = \angle PGH = {90^ \circ }$
By the law of reflection that incident angle equal to reflected angle, we have –
$\Rightarrow \angle APB = \angle GPH$
Hence, we can prove that the triangles ABP and GHP are similar.
By rule of similarity, we can say that –
$\Rightarrow \dfrac{{GH}}{{AB}} = \dfrac{{\left( { - v} \right)}}{{\left( { - u} \right)}}$
$ \Rightarrow \dfrac{{GH}}{{AB}} = \dfrac{v}{u}$
Given that $AB = {h_0}$ and $GH = - {h_i}$ (the negative sign is because the height of image is measured downwards direction)
Magnification is equal to the ratio of height of image of height of object.
$\Rightarrow m = \dfrac{{ - {h_i}}}{{{h_0}}}$
Substituting,
$\Rightarrow m = - \dfrac{v}{u}$
Therefore, magnification is defined as the ratio of v to u with a minus sign.
Note: The formula for the magnification in a lens is the same as that of a mirror, but only in the magnitude. The magnification formula for lenses has a positive sign while the magnification formula for a mirror has a negative sign.
Magnification for lens –
$m = \dfrac{v}{u}$
The students must understand the clear distinction between the two so that there is no confusion between the two formulae.
Recently Updated Pages
Young’s Double Slit Experiment Derivation Explained

Wheatstone Bridge Explained: Working, Formula & Uses

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

JEE General Topics in Chemistry Important Concepts and Tips

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

Understanding Atomic Structure for Beginners

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

How to Convert a Galvanometer into an Ammeter or Voltmeter

Understanding Centrifugal Force in Physics

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Degree of Dissociation: Meaning, Formula, Calculation & Uses

Understanding Electromagnetic Waves and Their Importance

