Question

The IUPAC name of the well-known terpene camphor having the structure is:

(A) 6-oxo-1,2,2-trimethyl bicyclo[2,2,1]heptane
(B) 1,7,7-trimethyl bicyclo[2,2,1]heptane-2-one
(C) 1,5,5-trimethyl bicyclo[2,1,1]hexane-2-one
(D) 1,7,7-trimethyl bicyclo[2,1,2]heptane-2-one

Answer 1

Hint: This is a complex structure. Identify the compound whether it is cyclo, or bicyclic compound. Count the number of carbon atoms, and start naming the compound.

Complete step by step answer:
- First, let us name this compound step by step according to the rules of IUPAC.
- We will identify the parent hydrocarbon whether it is cyclo or bicyclo as mentioned; it is a bicyclic compound consisting of 7 carbon atoms.
- Now, carefully look at the figure; specific positions are assigned to the carbon atoms.
            
- The first position is assigned to the bridged atom, and now we will assign the second position to the carbon along the longest chain having functional group, or substituents.
The further positions will be assigned to the carbon atoms along the shortest chain.
- We can see in the figure that the methyl groups are present on first, and the seventh position acting as substituents; the total count of methyl groups attached is 3.
As we can see there is presence of a carbonyl group at the second position i.e. a ketone group.
Accordingly, the IUPAC name of well-known terpene camphor is 1,7,7-trimethyl bicyclo[2,2,1]heptane-2-one.
Hence, the correct option is (B).

Additional information: Terpene camphor is a kind of waxy substance, with the strong aroma. It is a volatile, and a flammable, and also known as terpenoid.

Note: Be careful while naming the compound. Look at the structure carefully, as if one factor is missed the naming assigned to the compound will be wrong. In the naming one is assigned to the carbonyl group attached at 2 positions.