The equation of the line joining the origin to the point \[\left( { - 4,{\rm{ }}5} \right)\]is [MP PET \[1984\]]
A) \[5x + 4y = 0\;\;\]
B) \[3x + 4y = 2\]
C) \[5x - 4y = 0\;\]
D) \[4x - 5y = 0\]
Answer
253.2k+ views
Hint: Straight line is a set of infinites points in which all points are linear. Slope of the required line is calculated by using the coordinate of two points. Now, after that two points formula is used to find required equation of straight line.
Formula Used:\[m = \dfrac{{\left( {{y_2} - {y_1}} \right)}}{{\left( {{x_2} - {x_1}} \right)}}\]
Where
m is slope of required line
Equation of line
\[y - {y_1} = \dfrac{{\left( {{y_2} - {y_1}} \right)}}{{\left( {{x_2} - {x_1}} \right)}}\left( {x - {x_1}} \right)\]
Complete step by step solution:Given: Lines passes through origin and \[\left( { - 4,{\rm{ }}5} \right)\]
Equation of a required straight line:
\[m = \dfrac{{\left( {{y_2} - {y_1}} \right)}}{{\left( {{x_2} - {x_1}} \right)}}\]
\[y - {y_1} = \dfrac{{\left( {{y_2} - {y_1}} \right)}}{{\left( {{x_2} - {x_1}} \right)}}\left( {x - {x_1}} \right)\]
Where \[\left( {{x_1},\;{y_1}} \right)\], \[\left( {{x_2},\;{y_2}} \right)\] are two points through which line passes.
\[y = \dfrac{{\left( 5 \right)}}{{\left( { - 4} \right)}}\left( x \right)\] Because line passes through origin
\[ - 4y = 5x\]
\[5x + 4y = 0\]
Option ‘A’ is correct
Note:Here use only two points equation because two points are given through which line is passes. Slope is found by using two points which is lying on lines.
Formula Used:\[m = \dfrac{{\left( {{y_2} - {y_1}} \right)}}{{\left( {{x_2} - {x_1}} \right)}}\]
Where
m is slope of required line
Equation of line
\[y - {y_1} = \dfrac{{\left( {{y_2} - {y_1}} \right)}}{{\left( {{x_2} - {x_1}} \right)}}\left( {x - {x_1}} \right)\]
Complete step by step solution:Given: Lines passes through origin and \[\left( { - 4,{\rm{ }}5} \right)\]
Equation of a required straight line:
\[m = \dfrac{{\left( {{y_2} - {y_1}} \right)}}{{\left( {{x_2} - {x_1}} \right)}}\]
\[y - {y_1} = \dfrac{{\left( {{y_2} - {y_1}} \right)}}{{\left( {{x_2} - {x_1}} \right)}}\left( {x - {x_1}} \right)\]
Where \[\left( {{x_1},\;{y_1}} \right)\], \[\left( {{x_2},\;{y_2}} \right)\] are two points through which line passes.
\[y = \dfrac{{\left( 5 \right)}}{{\left( { - 4} \right)}}\left( x \right)\] Because line passes through origin
\[ - 4y = 5x\]
\[5x + 4y = 0\]
Option ‘A’ is correct
Note:Here use only two points equation because two points are given through which line is passes. Slope is found by using two points which is lying on lines.
Recently Updated Pages
States of Matter Chapter For JEE Main Chemistry

Mutually Exclusive vs Independent Events: Key Differences Explained

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

[Awaiting the three content sources: Ask AI Response, Competitor 1 Content, and Competitor 2 Content. Please provide those to continue with the analysis and optimization.]

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Isoelectronic Definition in Chemistry: Meaning, Examples & Trends

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

JEE Main 2026 Application Login: Direct Link, Registration, Form Fill, and Steps

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

Other Pages
JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

CBSE Class 12 Maths 2026 Question Paper: Free PDF & Solutions

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

JEE Advanced Marks vs Rank 2025 - Predict Your IIT Rank Based on Score

