Answer
64.8k+ views
Hint: According to the Bohr's model in the atoms the electrons are moving around the nucleus in different shells. These shells are K, L, M, N etc. Electronic distribution of an atom/ion is an arrangement in a space of the electrons around the center of the mass(nucleus) of the atom or ion among the orbits or shells.
Complete step by step answer:
The principle quantum numbers of the shells are, for K is 1, for L is 2, for M is 3, for N is 4 etc.
According to the principal quantum number the total electrons can be filled in a shell is \[2{n^2}\].
Therefore, the total electrons in K shell is 2, in L shell is 8, in M shell is 18 and so on.
Therefore, the electron distribution of \[{M^{ + 2}}\] is
Now the number of electrons of an element is equal to the number of protons.
Therefore, the total number of protons present in \[{M^{ + 2}}\] is 24.
Now the atomic weight of \[{M^{ + 2}}\] is equal to 58.
\[atomic{\text{ }}weight = {\text{ }}proton{\text{ }}number{\text{ }} + {\text{ }}neutron{\text{ }}number{\text{ }}\]
Therefore, the number of neutrons is
\[
atomic{\text{ }}weight = {\text{ }}proton{\text{ }}number{\text{ }} + {\text{ }}neutron{\text{ }}number{\text{ }} \\
or,58 = 24 + neutron{\text{ }}number{\text{ }} \\
or,neutron{\text{ }}number{\text{ }} = 58 - 24 \\
or,neutron{\text{ }}number{\text{ }} = 34 \\
\]
Therefore, the correct option is C.
Note: Remember that atomic weight is equal to the summation of proton and neutron. Also remember that in an atom the total number of electrons in the shells is equal to the number of protons in the nucleus. The principal quantum number for different shells are,1 for K, 2 for L,3 for M, 4 for N etc.
Complete step by step answer:
The principle quantum numbers of the shells are, for K is 1, for L is 2, for M is 3, for N is 4 etc.
According to the principal quantum number the total electrons can be filled in a shell is \[2{n^2}\].
Therefore, the total electrons in K shell is 2, in L shell is 8, in M shell is 18 and so on.
Therefore, the electron distribution of \[{M^{ + 2}}\] is
K | L | M |
2 | 8 | 14 |
Now the number of electrons of an element is equal to the number of protons.
Therefore, the total number of protons present in \[{M^{ + 2}}\] is 24.
Now the atomic weight of \[{M^{ + 2}}\] is equal to 58.
\[atomic{\text{ }}weight = {\text{ }}proton{\text{ }}number{\text{ }} + {\text{ }}neutron{\text{ }}number{\text{ }}\]
Therefore, the number of neutrons is
\[
atomic{\text{ }}weight = {\text{ }}proton{\text{ }}number{\text{ }} + {\text{ }}neutron{\text{ }}number{\text{ }} \\
or,58 = 24 + neutron{\text{ }}number{\text{ }} \\
or,neutron{\text{ }}number{\text{ }} = 58 - 24 \\
or,neutron{\text{ }}number{\text{ }} = 34 \\
\]
Therefore, the correct option is C.
Note: Remember that atomic weight is equal to the summation of proton and neutron. Also remember that in an atom the total number of electrons in the shells is equal to the number of protons in the nucleus. The principal quantum number for different shells are,1 for K, 2 for L,3 for M, 4 for N etc.
Recently Updated Pages
Write a composition in approximately 450 500 words class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Arrange the sentences P Q R between S1 and S5 such class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What is the common property of the oxides CONO and class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
If four points A63B 35C4 2 and Dx3x are given in such class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The area of square inscribed in a circle of diameter class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Other Pages
A boat takes 2 hours to go 8 km and come back to a class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
In the ground state an element has 13 electrons in class 11 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Electric field due to uniformly charged sphere class 12 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
According to classical free electron theory A There class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Excluding stoppages the speed of a bus is 54 kmph and class 11 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)