
The density of neon will be highest at
(A) $STP$
(B) $0^\circ C,2atm$
(C) $273^\circ C,1atm$
(D) $273^\circ C,2atm$
Answer
243.6k+ views
Hint – You can start the solution by describing what factors decide the density of a material. Then use the equations $PV = nRT$ and $n = \dfrac{w}{M}$. Then finally use the equation for density $d = \dfrac{w}{V}$ to find the relation between \[P,d\] and \[T\].
Complete step by step solution:
Density of a material is decided by two internal factors, the level of compression of the material and the kinetic energy of the material. There also exists internal factors like temperature, pressure, etc. that affect the internal factors and cause the density to change.
We know that the density of materials especially gases and liquids change with temperature. For example – The density of water is maximum at $4^\circ C$.
We also know that for an ideal gas, the following is used.
$PV = nRT$(Equation 1)
Here
$P = $Pressure,
$V = $Volume,
$n = $Number of moles,
$R = $Universal gas constant
$T = $Temperature.
We also know
$n = \dfrac{w}{M}$(Equation 2)
Here
$w = $Weight,
$M = $Molar mass.
Using the value of number of moles derived in equation 2 in equation 2, we get
$PV = \left( {\dfrac{w}{M}RT} \right)$
$ \Rightarrow PM = \left( {\dfrac{w}{V}} \right)RT$
As $density(d) = \dfrac{{weight}}{{volume}}$
So,
$PM = dRT$
$ \Rightarrow d = \dfrac{{PM}}{{RT}}$
As $M$and$R$are constants
\[d \propto P\]
\[d \propto \dfrac{1}{T}\]
Thus low temperature conditions and high pressure conditions will result in greater density of Neon (\[Ne\]).
Choosing from the available options it is clear that the density of Neon will be highest at \[0^\circ C\] and \[2atm\].
Hence, option B is the correct choice.
Note – You can also figure out the solution theoretically. You know that more pressure will result in the molecules of the substance being pushed closely together in compact form leading to an increase in density. Also increasing the temperature will provide more kinetic energy to the molecules further decreasing the density of the substance.
Complete step by step solution:
Density of a material is decided by two internal factors, the level of compression of the material and the kinetic energy of the material. There also exists internal factors like temperature, pressure, etc. that affect the internal factors and cause the density to change.
We know that the density of materials especially gases and liquids change with temperature. For example – The density of water is maximum at $4^\circ C$.
We also know that for an ideal gas, the following is used.
$PV = nRT$(Equation 1)
Here
$P = $Pressure,
$V = $Volume,
$n = $Number of moles,
$R = $Universal gas constant
$T = $Temperature.
We also know
$n = \dfrac{w}{M}$(Equation 2)
Here
$w = $Weight,
$M = $Molar mass.
Using the value of number of moles derived in equation 2 in equation 2, we get
$PV = \left( {\dfrac{w}{M}RT} \right)$
$ \Rightarrow PM = \left( {\dfrac{w}{V}} \right)RT$
As $density(d) = \dfrac{{weight}}{{volume}}$
So,
$PM = dRT$
$ \Rightarrow d = \dfrac{{PM}}{{RT}}$
As $M$and$R$are constants
\[d \propto P\]
\[d \propto \dfrac{1}{T}\]
Thus low temperature conditions and high pressure conditions will result in greater density of Neon (\[Ne\]).
Choosing from the available options it is clear that the density of Neon will be highest at \[0^\circ C\] and \[2atm\].
Hence, option B is the correct choice.
Note – You can also figure out the solution theoretically. You know that more pressure will result in the molecules of the substance being pushed closely together in compact form leading to an increase in density. Also increasing the temperature will provide more kinetic energy to the molecules further decreasing the density of the substance.
Recently Updated Pages
JEE Main 2026 Session 2 City Intimation Slip & Exam Date: Expected Date, Download Link

JEE Main 2026 Session 2 Application Form: Reopened Registration, Dates & Fees

JEE Main 2026 Session 2 Registration (Reopened): Last Date, Fees, Link & Process

WBJEE 2026 Registration Started: Important Dates Eligibility Syllabus Exam Pattern

Types of Solutions in Chemistry: Explained Simply

JEE Main Mock Test 2025-26: Principles Related To Practical

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Ideal and Non-Ideal Solutions Explained for Class 12 Chemistry

Understanding the Angle of Deviation in a Prism

Understanding Differential Equations: A Complete Guide

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Electric Field of a Uniformly Charged Ring

Other Pages
CBSE Class 12 Chemistry Question Paper 2026 PDF Download (All Sets) with Answer Key

NCERT Solutions For Class 12 Chemistry Chapter 10 Biomolecules - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 4 The D And F Block Elements - 2025-26

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions For Class 12 Chemistry Chapter 2 Electrochemistry - 2025-26

NCERT Solutions For Class 12 Chemistry Chapter 3 Chemical Kinetics - 2025-26

