Answer
64.8k+ views
Hint: Use the given formula of the volume and find the volume of the increase in the water by substituting the given values. Similarly find the volume of the decrease in the ice amount. The difference in these values gives the answer for the change in the volume of the product when the ice melts.
Useful formula:
The volume is given by
$V = \dfrac{m}{\rho }$
Where $V$ is the volume of the water or ice, $m$ is its mass and $\rho $ is its density.
Complete step by step solution:
It is given that the
The $m\,gm$ of ice melts
The density of ice is $x\,gmc{c^{ - 1}}$
The density of water is $y\,gmc{c^{ - 1}}$
We know that when the ice melts, it forms into the state of the water.
Using the formula of the volume, the volume of the water and the density is obtained as follows.
Volume of the ice reduces, $V = \dfrac{m}{x}$
The volume of the water increases, $V = \dfrac{m}{y}$
So the change in the volume is the difference of the volume of the decrease in the ice volume and the increase in the water volume.
$\Delta V = \dfrac{m}{y} - \dfrac{m}{x}$
By simplification of the above equation, we get
$\Delta V = m\left( {\dfrac{1}{y} - \dfrac{1}{x}} \right)\,cc$
Hence the change in the volume is obtained as $m\left( {\dfrac{1}{y} - \dfrac{1}{x}} \right)\,cc$ .
Note: The water commonly lies between three states as vapour in the gaseous state, water in the liquid state and ice in the solid state. The $cc$ specified in the above solution determines the cubic centimeter which is the unit of the volume.
Useful formula:
The volume is given by
$V = \dfrac{m}{\rho }$
Where $V$ is the volume of the water or ice, $m$ is its mass and $\rho $ is its density.
Complete step by step solution:
It is given that the
The $m\,gm$ of ice melts
The density of ice is $x\,gmc{c^{ - 1}}$
The density of water is $y\,gmc{c^{ - 1}}$
We know that when the ice melts, it forms into the state of the water.
Using the formula of the volume, the volume of the water and the density is obtained as follows.
Volume of the ice reduces, $V = \dfrac{m}{x}$
The volume of the water increases, $V = \dfrac{m}{y}$
So the change in the volume is the difference of the volume of the decrease in the ice volume and the increase in the water volume.
$\Delta V = \dfrac{m}{y} - \dfrac{m}{x}$
By simplification of the above equation, we get
$\Delta V = m\left( {\dfrac{1}{y} - \dfrac{1}{x}} \right)\,cc$
Hence the change in the volume is obtained as $m\left( {\dfrac{1}{y} - \dfrac{1}{x}} \right)\,cc$ .
Note: The water commonly lies between three states as vapour in the gaseous state, water in the liquid state and ice in the solid state. The $cc$ specified in the above solution determines the cubic centimeter which is the unit of the volume.
Recently Updated Pages
Write a composition in approximately 450 500 words class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Arrange the sentences P Q R between S1 and S5 such class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What is the common property of the oxides CONO and class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
If four points A63B 35C4 2 and Dx3x are given in such class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The area of square inscribed in a circle of diameter class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Other Pages
Excluding stoppages the speed of a bus is 54 kmph and class 11 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
In the ground state an element has 13 electrons in class 11 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Electric field due to uniformly charged sphere class 12 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
A boat takes 2 hours to go 8 km and come back to a class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
According to classical free electron theory A There class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)