The coefficient of thermal conductivity of copper, mercury and glass respectively are ${K_{C,}}{K_m}$ and ${K_g}$ such that ${K_C} > {K_m} > {K_g}$. If the same quantity of heat is flowing per second per unit area through each and corresponding temperature gradient are ${X_c},{X_m}$ and ${X_g}$. Then:
(A) ${X_c} = {X_m} = {X_g}$
(B) ${X_c} > {X_m} > {X_g}$
(C) ${X_c} < {X_m} < {X_g}$
(D) ${X_m} < {X_c} < {X_g}$
Answer
272.4k+ views
Hint We know that the law of conduction of heat is also known as the Fourier’s law. We know that the heat transfer is classified into various mechanisms, which are thermal conduction, thermal conduction, thermal radiation, and the transfer of energy by the phase changes. This is the concept which is used to solve this answer. We should consider the fact that engineers also consider the transfer of mass of differing chemical species, either cold, or hot, to reach the required amount of heat transfer.
Complete step by step answer
We should know that from the basis law of conduction which is Fourier’s law that:
$Q = - KA\left( {\dfrac{{dT}}{{dx}}} \right)$
Where the $\dfrac{{dT}}{{dx}}$is the temperature gradient
So, K is inversely proportional to the temperature gradient.
Hence, we can say that:
${K_{metal}} > {K_{liquid}} > {K_{gas}}$
Now we can write that:
${X_{metal}} < {X_{liquid}} < {X_{gas}}$or we can say,
${X_{copper}} < {X_{mercury}} < {X_{glass}}$
Hence the ceramics material has greater conductivity as compared to that of gas. So it can said that the same quantity of heat is flowing per second per unit area through each and corresponding temperature gradient are ${X_c},{X_m}$ and ${X_g}$, then ${X_c} < {X_m} < {X_g}$.
Hence the correct answer is option C.
Note The law of heat conduction is known as the explanation which states that the rate of transfer of heat through a material is proportional to the negative gradient in the temperature and to the area, at the right angles to that of the gradient, through which the heat will flow.
The basic idea of the law states that the heat flux vector will be proportional to the negative vector gradient of the temperature. The process of conduction is greater in the solids because of the network of the relatively close fixed spatial relationships between the atoms to help the transfer of the energy between the vibration.
Complete step by step answer
We should know that from the basis law of conduction which is Fourier’s law that:
$Q = - KA\left( {\dfrac{{dT}}{{dx}}} \right)$
Where the $\dfrac{{dT}}{{dx}}$is the temperature gradient
So, K is inversely proportional to the temperature gradient.
Hence, we can say that:
${K_{metal}} > {K_{liquid}} > {K_{gas}}$
Now we can write that:
${X_{metal}} < {X_{liquid}} < {X_{gas}}$or we can say,
${X_{copper}} < {X_{mercury}} < {X_{glass}}$
Hence the ceramics material has greater conductivity as compared to that of gas. So it can said that the same quantity of heat is flowing per second per unit area through each and corresponding temperature gradient are ${X_c},{X_m}$ and ${X_g}$, then ${X_c} < {X_m} < {X_g}$.
Hence the correct answer is option C.
Note The law of heat conduction is known as the explanation which states that the rate of transfer of heat through a material is proportional to the negative gradient in the temperature and to the area, at the right angles to that of the gradient, through which the heat will flow.
The basic idea of the law states that the heat flux vector will be proportional to the negative vector gradient of the temperature. The process of conduction is greater in the solids because of the network of the relatively close fixed spatial relationships between the atoms to help the transfer of the energy between the vibration.
Recently Updated Pages
WBJEE 2026 Result Live: Important Dates, Last Date Apply Online 2026

Circuit Switching vs Packet Switching: Key Differences Explained

Dimensions of Pressure in Physics: Formula, Derivation & SI Unit

JEE General Topics in Chemistry Important Concepts and Tips

JEE Extractive Metallurgy Important Concepts and Tips for Exam Preparation

JEE Atomic Structure and Chemical Bonding important Concepts and Tips

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

Understanding the Electric Field of a Uniformly Charged Ring

Understanding Atomic Structure for Beginners

Derivation of Equation of Trajectory Explained for Students

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced 2026 Notification Out with Exam Date, Registration (Extended), Syllabus and More

JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

CBSE Notes Class 11 Physics Chapter 1 - Units And Measurements - 2026-27

NCERT Solutions For Class 11 Physics Chapter 1 Units And Measurements - 2025-26

Important Questions For Class 11 Physics Chapter 1 Units and Measurement - 2025-26

JEE Advanced Weightage Chapter Wise 2026 for Physics, Chemistry, and Mathematics

