
The centre of mass of three bodies each of mass 1 kg located at the points (0, 0), (3, 0) and (0, 4) in the XY plane is
A. \[\left( {\dfrac{4}{3},1} \right)\]
B. \[\left( {\dfrac{1}{3},\dfrac{2}{3}} \right)\]
C. \[\left( {\dfrac{1}{2},\dfrac{1}{2}} \right)\]
D. \[\left( {1,\dfrac{4}{3}} \right)\]
Answer
219.3k+ views
Hint:Before we start addressing the problem, we need to know what data has been provided. They have given the coordinates in the XY plane and three bodies having 1kg mass each. In order to solve this, we need the formula for the centre of mass.
Formula Used:
The formula to find the centre of mass is given by,
\[{X_{CM}} = \dfrac{{{m_1}{x_1} + {m_2}{x_2} + {m_3}{x_3}}}{{{m_1} + {m_2} + {m_3}}}\]
Where, \[{m_1},{m_2},{m_3}\] are the masses of three particles and \[{x_1},{x_2},{x_3}\] are the positions of masses.
Complete step by step solution:
Now, consider the centre of mass of three bodies in which each having a mass of 1 kg located at the points (0, 0), (3, 0) and (0, 4) in the XY plane then the centre of mass \[{X_{CM}}\] is given by,
\[{X_{CM}} = \dfrac{{{m_1}{x_1} + {m_2}{x_2} + {m_3}{x_3}}}{{{m_1} + {m_2} + {m_3}}} \\ \]
According to the question, we have \[{m_1} = {m_2} = {m_3} = 1\,kg\], \[\left( {{x_1},{y_1}} \right) = \left( {0,0} \right)\] , \[\left( {{x_2},{y_2}} \right) = \left( {3,0} \right)\] and \[\left( {{x_3},{y_3}} \right) = \left( {0,4} \right)\]
\[{X_{CM}} = \dfrac{{1\left( 0 \right) + 1\left( 3 \right) + 1\left( 0 \right)}}{{1 + 1 + 1}} \\ \]
\[\Rightarrow{X_{CM}} = \dfrac{3}{3} \\ \]
\[ \Rightarrow {X_{CM}} = 1 \\ \]
Similarly,
\[\Rightarrow{Y_{CM}} = \dfrac{{{m_1}{y_1} + {m_2}{y_2} + {m_3}{y_3}}}{{{m_1} + {m_2} + {m_3}}} \\ \]
\[\Rightarrow{Y_{CM}} = \dfrac{{1\left( 0 \right) + 1\left( 0 \right) + 1\left( 4 \right)}}{{1 + 1 + 1}} \\ \]
\[ \therefore {Y_{CM}} = \dfrac{4}{3}\]
Therefore, the coordinates of the centre of mass are \[\left( {1,\dfrac{4}{3}} \right)\].
Hence, option D is the correct answer.
Note: The point in the system which will move in the same way that a single particle would move when it is subjected to an external force is called the centre of mass of the system. Or the centre of mass is the point at which the whole mass of the body is concentrated. The centre of mass of a body can be located in the middle of the object or at some distance from the centre. For example, a bottle will have its centre of mass on its axis.
Formula Used:
The formula to find the centre of mass is given by,
\[{X_{CM}} = \dfrac{{{m_1}{x_1} + {m_2}{x_2} + {m_3}{x_3}}}{{{m_1} + {m_2} + {m_3}}}\]
Where, \[{m_1},{m_2},{m_3}\] are the masses of three particles and \[{x_1},{x_2},{x_3}\] are the positions of masses.
Complete step by step solution:
Now, consider the centre of mass of three bodies in which each having a mass of 1 kg located at the points (0, 0), (3, 0) and (0, 4) in the XY plane then the centre of mass \[{X_{CM}}\] is given by,
\[{X_{CM}} = \dfrac{{{m_1}{x_1} + {m_2}{x_2} + {m_3}{x_3}}}{{{m_1} + {m_2} + {m_3}}} \\ \]
According to the question, we have \[{m_1} = {m_2} = {m_3} = 1\,kg\], \[\left( {{x_1},{y_1}} \right) = \left( {0,0} \right)\] , \[\left( {{x_2},{y_2}} \right) = \left( {3,0} \right)\] and \[\left( {{x_3},{y_3}} \right) = \left( {0,4} \right)\]
\[{X_{CM}} = \dfrac{{1\left( 0 \right) + 1\left( 3 \right) + 1\left( 0 \right)}}{{1 + 1 + 1}} \\ \]
\[\Rightarrow{X_{CM}} = \dfrac{3}{3} \\ \]
\[ \Rightarrow {X_{CM}} = 1 \\ \]
Similarly,
\[\Rightarrow{Y_{CM}} = \dfrac{{{m_1}{y_1} + {m_2}{y_2} + {m_3}{y_3}}}{{{m_1} + {m_2} + {m_3}}} \\ \]
\[\Rightarrow{Y_{CM}} = \dfrac{{1\left( 0 \right) + 1\left( 0 \right) + 1\left( 4 \right)}}{{1 + 1 + 1}} \\ \]
\[ \therefore {Y_{CM}} = \dfrac{4}{3}\]
Therefore, the coordinates of the centre of mass are \[\left( {1,\dfrac{4}{3}} \right)\].
Hence, option D is the correct answer.
Note: The point in the system which will move in the same way that a single particle would move when it is subjected to an external force is called the centre of mass of the system. Or the centre of mass is the point at which the whole mass of the body is concentrated. The centre of mass of a body can be located in the middle of the object or at some distance from the centre. For example, a bottle will have its centre of mass on its axis.
Recently Updated Pages
Chemical Equation - Important Concepts and Tips for JEE

JEE Main 2022 (July 29th Shift 1) Chemistry Question Paper with Answer Key

Conduction Explained: Definition, Examples & Science for Students

Analytical Method of Vector Addition Explained Simply

Atomic Size - Important Concepts and Tips for JEE

JEE Main 2022 (June 29th Shift 1) Maths Question Paper with Answer Key

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Understanding Uniform Acceleration in Physics

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Units And Measurements Class 11 Physics Chapter 1 CBSE Notes - 2025-26

NCERT Solutions For Class 11 Physics Chapter 8 Mechanical Properties Of Solids

Motion in a Straight Line Class 11 Physics Chapter 2 CBSE Notes - 2025-26

NCERT Solutions for Class 11 Physics Chapter 7 Gravitation 2025-26

Mechanical Properties of Fluids Class 11 Physics Chapter 9 CBSE Notes - 2025-26

