
The C-C bond length of the following molecules is in the order:
\[
{\text{(A)}}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{6}}}{\text{ > }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{4}}}{\text{ > }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}{\text{ > }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}} \\
{\text{(B)}}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{4}}}{\text{ < }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{6}}} \\
{\text{(C) }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{6}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{\text{ < }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{4}}} \\
{\text{(D) }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{4}}}{\text{ < }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{\text{ < }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}} \\
\]
Answer
155.1k+ views
Hint: The carbon-carbon bond lengths are dependent upon the type of bonds namely single bond, double bond, or triple bond. The single bond has more bond length compared to double bond which in turn is more than triple bond.
Complete step by step answer:
Bond lengths decrease with increase in s-character. In other words, multiple bonds have a shorter bond length as compared to a single bond.
In the case of single bond only sigma bonds are present whereas in double bond a sigma and a pi bond are present. Sigma bonds are weaker bonds but have high bond length compared to a pi bond. In triple bonds there are two pi bonds which makes it a shorter bond.
A typical carbon-carbon single bond has a length of 154 pm, while a typical double bond and triple bonds are 134 pm and 120 pm, respectively.

We can see that
Ethane has a single bond between carbon and carbon.
In benzene, the carbon-carbon bond lengths are in resonance due to its aromatic nature, so they have bond length between single bond and double bond as it exhibits partial double bond character.
In ethene, there is a double bond between carbon and carbon.
In ethyne, there is a triple bond between carbon and carbon.
Thus, Single bond > Partial double bond > Double bond > Triple bond.
Therefore, we get the correct following order:
\[{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{4}}}{\text{ < }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{6}}}\]
So, the correct option is B.
Note: Partial double bond character is exhibited by molecules having resonance structures where both single bonds and double bonds are exhibited by the molecule. These molecules have bond lengths more than single bonds but less than double bonds.
Complete step by step answer:
Bond lengths decrease with increase in s-character. In other words, multiple bonds have a shorter bond length as compared to a single bond.
In the case of single bond only sigma bonds are present whereas in double bond a sigma and a pi bond are present. Sigma bonds are weaker bonds but have high bond length compared to a pi bond. In triple bonds there are two pi bonds which makes it a shorter bond.
A typical carbon-carbon single bond has a length of 154 pm, while a typical double bond and triple bonds are 134 pm and 120 pm, respectively.

We can see that
Ethane has a single bond between carbon and carbon.
In benzene, the carbon-carbon bond lengths are in resonance due to its aromatic nature, so they have bond length between single bond and double bond as it exhibits partial double bond character.
In ethene, there is a double bond between carbon and carbon.
In ethyne, there is a triple bond between carbon and carbon.
Thus, Single bond > Partial double bond > Double bond > Triple bond.
Therefore, we get the correct following order:
\[{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{4}}}{\text{ < }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{6}}}\]
So, the correct option is B.
Note: Partial double bond character is exhibited by molecules having resonance structures where both single bonds and double bonds are exhibited by the molecule. These molecules have bond lengths more than single bonds but less than double bonds.
Recently Updated Pages
JEE Atomic Structure and Chemical Bonding important Concepts and Tips

JEE Amino Acids and Peptides Important Concepts and Tips for Exam Preparation

JEE Electricity and Magnetism Important Concepts and Tips for Exam Preparation

Chemical Properties of Hydrogen - Important Concepts for JEE Exam Preparation

JEE Energetics Important Concepts and Tips for Exam Preparation

JEE Isolation, Preparation and Properties of Non-metals Important Concepts and Tips for Exam Preparation

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

NH4NO3 and NH4NO2 on heating decomposes in to A NO2 class 11 chemistry JEE_Main

Degree of Dissociation and Its Formula With Solved Example for JEE

Displacement-Time Graph and Velocity-Time Graph for JEE

Other Pages
JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced 2025: Dates, Registration, Syllabus, Eligibility Criteria and More

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

NCERT Solutions for Class 11 Chemistry In Hindi Chapter 1 Some Basic Concepts of Chemistry

JEE Advanced 2025 Notes

Electrical Field of Charged Spherical Shell - JEE
