The C-C bond length of the following molecules is in the order:
\[
{\text{(A)}}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{6}}}{\text{ > }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{4}}}{\text{ > }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}{\text{ > }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}} \\
{\text{(B)}}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{4}}}{\text{ < }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{6}}} \\
{\text{(C) }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{6}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{\text{ < }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{4}}} \\
{\text{(D) }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{4}}}{\text{ < }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{\text{ < }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}} \\
\]
Answer
294.6k+ views
Hint: The carbon-carbon bond lengths are dependent upon the type of bonds namely single bond, double bond, or triple bond. The single bond has more bond length compared to double bond which in turn is more than triple bond.
Complete step by step answer:
Bond lengths decrease with increase in s-character. In other words, multiple bonds have a shorter bond length as compared to a single bond.
In the case of single bond only sigma bonds are present whereas in double bond a sigma and a pi bond are present. Sigma bonds are weaker bonds but have high bond length compared to a pi bond. In triple bonds there are two pi bonds which makes it a shorter bond.
A typical carbon-carbon single bond has a length of 154 pm, while a typical double bond and triple bonds are 134 pm and 120 pm, respectively.

We can see that
Ethane has a single bond between carbon and carbon.
In benzene, the carbon-carbon bond lengths are in resonance due to its aromatic nature, so they have bond length between single bond and double bond as it exhibits partial double bond character.
In ethene, there is a double bond between carbon and carbon.
In ethyne, there is a triple bond between carbon and carbon.
Thus, Single bond > Partial double bond > Double bond > Triple bond.
Therefore, we get the correct following order:
\[{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{4}}}{\text{ < }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{6}}}\]
So, the correct option is B.
Note: Partial double bond character is exhibited by molecules having resonance structures where both single bonds and double bonds are exhibited by the molecule. These molecules have bond lengths more than single bonds but less than double bonds.
Complete step by step answer:
Bond lengths decrease with increase in s-character. In other words, multiple bonds have a shorter bond length as compared to a single bond.
In the case of single bond only sigma bonds are present whereas in double bond a sigma and a pi bond are present. Sigma bonds are weaker bonds but have high bond length compared to a pi bond. In triple bonds there are two pi bonds which makes it a shorter bond.
A typical carbon-carbon single bond has a length of 154 pm, while a typical double bond and triple bonds are 134 pm and 120 pm, respectively.

We can see that
Ethane has a single bond between carbon and carbon.
In benzene, the carbon-carbon bond lengths are in resonance due to its aromatic nature, so they have bond length between single bond and double bond as it exhibits partial double bond character.
In ethene, there is a double bond between carbon and carbon.
In ethyne, there is a triple bond between carbon and carbon.
Thus, Single bond > Partial double bond > Double bond > Triple bond.
Therefore, we get the correct following order:
\[{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{2}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{4}}}{\text{ < }}{{\text{C}}_{\text{6}}}{{\text{H}}_{\text{6}}}{\text{ < }}{{\text{C}}_{\text{2}}}{{\text{H}}_{\text{6}}}\]
So, the correct option is B.
Note: Partial double bond character is exhibited by molecules having resonance structures where both single bonds and double bonds are exhibited by the molecule. These molecules have bond lengths more than single bonds but less than double bonds.
Recently Updated Pages
Number of sigma and pi bonds in C2 molecule isare A class 11 chemistry JEE_Main

10g of hydrogen and 64g of oxygen were filled in a class 11 chemistry JEE_Main

If CH3COOH Ka105 reacts with NaOH at 298 K then find class 11 chemistry JEE_Main

The average and RMS value of voltage for square waves class 12 physics JEE_Main

The force between two short electric dipoles placed class 12 physics JEE_Main

The dimensional formula of k Coulombs Constant is Take class 11 physics JEE_Main

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

Understanding the Electric Field of a Uniformly Charged Ring

Understanding Atomic Structure for Beginners

Electron Gain Enthalpy and Electron Affinity Explained

Derivation of Equation of Trajectory Explained for Students

How to Convert a Galvanometer into an Ammeter or Voltmeter

Other Pages
JEE Advanced Percentile vs Marks 2026: JEE Main Cutoff, AIR & IIT Admission Guide

NCERT Solutions For Class 11 Chemistry In Hindi Chapter 1 Some Basic Concepts Of Chemistry - 2026-27 Free PDF Download (Sign-in Required)

JEE Advanced Weightage Chapter Wise 2026 for Physics, Chemistry, and Mathematics

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

NCERT Solutions For Class 11 Chemistry Chapter 8 Organic Chemistry - Some Basic Principles And Techniques - 2026-27 Free PDF Download (Sign-in Required)

