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# The capacity of a normal human eye to see the smallest objects is:(A) 5000nm (B) 10000nm (C) 18000nm (D) 25000nm

Last updated date: 17th Apr 2024
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Hint: As we know that, the capacity of a normal human eye to see the smallest objects is $100\mu m$ (micrometers.) The image sent to the eye by way of the lens increases, we see an object more easily, even though its physical size has not changed. Under normal lighting conditions (light source $\approx 1000$ lumens at height 600-700nm,viewing angle $\approx 35$ degrees) the angular size recognized by naked eye will be round 1 arc minute $= \dfrac{1}{{60}}$ degrees=.0003 radians.

According to the question, we know that the capacity of a normal human eye to see the smallest objects is $100\mu m$. Then we will convert the value of maximum capacity of a normal eye from micrometers to nanometers as follows:
$100 \times {10^{ - 6}}m = 10000nm$
Therefore, the capacity of a normal human eye to see the smallest objects is 10,000 nm that is option B.

Hence the correct solution is option B