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Hint: The given scenario can be represented by a figure. Draw the diagram of the given problem statement for a better understanding of the situation. Use the formula $\sin \theta = \dfrac{{{\text{Opposite}}}}{{{\text{Hypotenuse}}}}$ and $\tan \theta = \dfrac{{{\text{Perpendicular}}}}{{{\text{Base}}}}$ to find the value of the distance between the tree and the point $P$.

Let us assume the distance between the tree and the point $P$ be \[x\] meters. It is given in the question that the angle of elevation of the top of the tree from the point $P$ is \[30^\circ \]. We can therefore draw the diagram representing the scenario.

Here the line TA represents the tree height of 18 meters and the point $P$ is the point in the plane of the tree's base.

We know that in a right angled triangle the $\tan \theta = \dfrac{{{\text{Perpendicular}}}}{{{\text{Base}}}}$

In the triangle\[TPA\],

\[\tan {30^ \circ } = \dfrac{{TA}}{{PA}}\]

Substituting the value 18 for $TA$ and \[x\] for $PA$ in the equation, we get

\[\tan {30^ \circ } = \dfrac{{18}}{x}\]

Solving the above equation for \[x\]

$

\dfrac{1}{{\sqrt 3 }} = \dfrac{{18}}{x} \\

x = 18\sqrt 3 \\

$

Thus the horizontal distance of the base of the tree from $P$ is \[18\sqrt 3 \]m.

Therefore the option D is the correct answer.

Note: In a right angled triangle, the $\tan \theta $ is the equal to $\dfrac{{{\text{Perpendicular}}}}{{{\text{Base}}}}$, where perpendicular is the side opposite to the angle $\theta $, and $\sin \theta $ is the equal to $\dfrac{{{\text{Perpendicular}}}}{{{\text{Hypotenuse}}}}$, where perpendicular is the side opposite to the angle $\theta $.

__Complete step by step solution__Let us assume the distance between the tree and the point $P$ be \[x\] meters. It is given in the question that the angle of elevation of the top of the tree from the point $P$ is \[30^\circ \]. We can therefore draw the diagram representing the scenario.

Here the line TA represents the tree height of 18 meters and the point $P$ is the point in the plane of the tree's base.

We know that in a right angled triangle the $\tan \theta = \dfrac{{{\text{Perpendicular}}}}{{{\text{Base}}}}$

In the triangle\[TPA\],

\[\tan {30^ \circ } = \dfrac{{TA}}{{PA}}\]

Substituting the value 18 for $TA$ and \[x\] for $PA$ in the equation, we get

\[\tan {30^ \circ } = \dfrac{{18}}{x}\]

Solving the above equation for \[x\]

$

\dfrac{1}{{\sqrt 3 }} = \dfrac{{18}}{x} \\

x = 18\sqrt 3 \\

$

Thus the horizontal distance of the base of the tree from $P$ is \[18\sqrt 3 \]m.

Therefore the option D is the correct answer.

Note: In a right angled triangle, the $\tan \theta $ is the equal to $\dfrac{{{\text{Perpendicular}}}}{{{\text{Base}}}}$, where perpendicular is the side opposite to the angle $\theta $, and $\sin \theta $ is the equal to $\dfrac{{{\text{Perpendicular}}}}{{{\text{Hypotenuse}}}}$, where perpendicular is the side opposite to the angle $\theta $.

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