
The acceleration of the light pulley is

$\left( A \right)$ $\dfrac{F}{m}$
$\left( B \right)$ $\dfrac{F}{{2m}}$
$\left( C \right)$ $\dfrac{F}{{4m}}$
$\left( D \right)$ $\dfrac{F}{{8m}}$
Answer
162.3k+ views
Hint: Acceleration is the name we tend to provide to any method wherever the speed changes. Since velocity may be speed and a direction so there are only two ways in which it can accelerate: the first one will be by the modification of speed or by the modification of direction—or by modifying each.
Formula used
Tension will be,
$ \Rightarrow T = ma$
Where, $T$ is the tension, $m$ is the mass, and $a$ is the acceleration.
The force applied on the block,
$ \Rightarrow F = 2T$
Here, $F$ is the force exerted on the block.
Solution
So this question is the problem of pulley and string and for solving such a type of question we should know the concept of applying it. Let’s see how we will solve this problem. One keynote for solving such a type of problem is we should know how to make the free body diagram because this will always help while solving this type of problem.
Let us consider the acceleration of the pulley be $a$
So from the relation of constraint, the acceleration of the block will be $2a$.
Now we will consider the forces acting on the block,
$ \Rightarrow T = m\left( {2a} \right)$
And also the forces acting on the pulley will be considered, which is
$ \Rightarrow F = 2T$
So by comparing from the above two equations, we will get
$ \Rightarrow a = \dfrac{T}{{2m}}$
And,
$ \Rightarrow \dfrac{{F/2}}{{2m}}$
On further solving the above equation, we get
$ \Rightarrow \dfrac{F}{{4m}}$
Therefore the acceleration of the light pulley will be $F/4m$.
Notes Problems involving two objects, connecting strings and pulleys are characterized by objects that are moving (or even accelerating) in numerous directions. They move or accelerate at a similar rate however in numerous directions. As such, it becomes necessary in approaching such issues to pick a different arrangement and axes system for every object. Attention ought to lean to choosing an axes system such that each object is accelerating on an axis within a positive direction. With the axes properly outlined for every individual object, a free-body diagram is created. Then Newton's laws are applied to every diagram to develop a system of two equations for the determination of the two unknowns.
Formula used
Tension will be,
$ \Rightarrow T = ma$
Where, $T$ is the tension, $m$ is the mass, and $a$ is the acceleration.
The force applied on the block,
$ \Rightarrow F = 2T$
Here, $F$ is the force exerted on the block.
Solution
So this question is the problem of pulley and string and for solving such a type of question we should know the concept of applying it. Let’s see how we will solve this problem. One keynote for solving such a type of problem is we should know how to make the free body diagram because this will always help while solving this type of problem.
Let us consider the acceleration of the pulley be $a$
So from the relation of constraint, the acceleration of the block will be $2a$.
Now we will consider the forces acting on the block,
$ \Rightarrow T = m\left( {2a} \right)$
And also the forces acting on the pulley will be considered, which is
$ \Rightarrow F = 2T$
So by comparing from the above two equations, we will get
$ \Rightarrow a = \dfrac{T}{{2m}}$
And,
$ \Rightarrow \dfrac{{F/2}}{{2m}}$
On further solving the above equation, we get
$ \Rightarrow \dfrac{F}{{4m}}$
Therefore the acceleration of the light pulley will be $F/4m$.
Notes Problems involving two objects, connecting strings and pulleys are characterized by objects that are moving (or even accelerating) in numerous directions. They move or accelerate at a similar rate however in numerous directions. As such, it becomes necessary in approaching such issues to pick a different arrangement and axes system for every object. Attention ought to lean to choosing an axes system such that each object is accelerating on an axis within a positive direction. With the axes properly outlined for every individual object, a free-body diagram is created. Then Newton's laws are applied to every diagram to develop a system of two equations for the determination of the two unknowns.
Recently Updated Pages
A steel rail of length 5m and area of cross section class 11 physics JEE_Main

At which height is gravity zero class 11 physics JEE_Main

A nucleus of mass m + Delta m is at rest and decays class 11 physics JEE_MAIN

A wave is travelling along a string At an instant the class 11 physics JEE_Main

The length of a conductor is halved its conductivity class 11 physics JEE_Main

Two billiard balls of the same size and mass are in class 11 physics JEE_Main

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Displacement-Time Graph and Velocity-Time Graph for JEE

Degree of Dissociation and Its Formula With Solved Example for JEE

Electric Field Due to Uniformly Charged Ring for JEE Main 2025 - Formula and Derivation

Charging and Discharging of Capacitor

Other Pages
NCERT Solutions for Class 11 Physics Chapter 1 Units and Measurements

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Units and Measurements Class 11 Notes: CBSE Physics Chapter 1

Motion in a Straight Line Class 11 Notes: CBSE Physics Chapter 2

NCERT Solutions for Class 11 Physics Chapter 2 Motion In A Straight Line

Important Questions for CBSE Class 11 Physics Chapter 1 - Units and Measurement
