Answer
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Hint: This problem can be solved using the concept of law of equipartition of energy and the kinetic theory of gases. According to the Law of Equipartition of energy the total energy for the system is equally divided among the degrees of freedom, this is applicable for any dynamic system in thermal equilibrium. To understand the concept of kinetic theory of gases we need to understand what is the degree of freedom. It is the number of independent parameters that define its configuration or state. For a mono-atomic gas like Helium the degree of freedom is one where for a triatomic molecule it is three.
Complete step by step solution:
The formula which we are going to use is
$t = \dfrac{\lambda }{v}$
Since the value of Lambda is not given we have to find it. That is the mean free path of a plane
$ \Rightarrow \lambda = \dfrac{1}{{\sqrt 2 \pi {d^2}n}}$
Where d is the diameter and n is the number density.
The given values are
$N = 10m$ $v = 150km{h^{ - 1}}$ $V = 20 \times 20 \times 1.5k{m^3}$
$ \Rightarrow n = \dfrac{N}{V}$
$ \Rightarrow \dfrac{{10}}{{20 \times 20 \times 1.5}}$
$ \Rightarrow n = 0.0167k{m^{ - 3}}$
Now we have to find time elapse before collision of two planes
$t = \dfrac{\lambda }{v}$
$ \Rightarrow t = \dfrac{1}{{\sqrt 2 \pi {d^2}nv}}$
$ \Rightarrow t = \dfrac{1}{{1.414 \times 3.14 \times {{\left( {20} \right)}^2} \times {{10}^{ - 6}} \times 0.0167 \times 150}}$
$ \Rightarrow t = \dfrac{{{{10}^6}}}{{4449.5}}$
$ \Rightarrow t = 225h$
So the correct answer is option d.
Additional Information:
Mean free path is the average distance a molecule can travel freely without colliding against each other. Kinetic theory of an ideal gas is based on the fact that gas molecules are in continuous motion they collide with themselves and within the walls of the container and these collisions are elastic. This concludes that total kinetic energy is conserved.
Note:
Properties of an ideal gas is mainly based on Charles law and Boyle's law.
Real gas satisfies the ideal gas equation only at low pressure and high temperature.
Complete step by step solution:
The formula which we are going to use is
$t = \dfrac{\lambda }{v}$
Since the value of Lambda is not given we have to find it. That is the mean free path of a plane
$ \Rightarrow \lambda = \dfrac{1}{{\sqrt 2 \pi {d^2}n}}$
Where d is the diameter and n is the number density.
The given values are
$N = 10m$ $v = 150km{h^{ - 1}}$ $V = 20 \times 20 \times 1.5k{m^3}$
$ \Rightarrow n = \dfrac{N}{V}$
$ \Rightarrow \dfrac{{10}}{{20 \times 20 \times 1.5}}$
$ \Rightarrow n = 0.0167k{m^{ - 3}}$
Now we have to find time elapse before collision of two planes
$t = \dfrac{\lambda }{v}$
$ \Rightarrow t = \dfrac{1}{{\sqrt 2 \pi {d^2}nv}}$
$ \Rightarrow t = \dfrac{1}{{1.414 \times 3.14 \times {{\left( {20} \right)}^2} \times {{10}^{ - 6}} \times 0.0167 \times 150}}$
$ \Rightarrow t = \dfrac{{{{10}^6}}}{{4449.5}}$
$ \Rightarrow t = 225h$
So the correct answer is option d.
Additional Information:
Mean free path is the average distance a molecule can travel freely without colliding against each other. Kinetic theory of an ideal gas is based on the fact that gas molecules are in continuous motion they collide with themselves and within the walls of the container and these collisions are elastic. This concludes that total kinetic energy is conserved.
Note:
Properties of an ideal gas is mainly based on Charles law and Boyle's law.
Real gas satisfies the ideal gas equation only at low pressure and high temperature.
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