How do you tell if an image is upright or inverted?
Answer
258k+ views
Hint: The images formed by spherical surfaces can be of two types, that is real and inverted or virtual and erect. The images formed by the converging of light rays from an object form real and inverted images. Similarly, the image which is formed by the diverging light rays from the object will be virtual and erect.
Complete answer:
* If the image is real in the case of mirrors, it will always be inverted. Also in case of mirrors if the image distance is negative hence the image is inverted. These images will form on the same side of the mirror.
* If the image is real in the case of lenses, it will always be inverted. Also in case of lenses if the image distance is positive hence the image is inverted. These images will form on the opposite side of the lens.


* If the image is virtual in the case of mirrors, it will always be upright. Also in case of mirrors if the image distance is positive hence the image is upright. These images will form on the opposite side of the mirror.
* If the image is virtual in the case of lenses, it will always be upright. Also in case of lenses if the image distance is negative hence the image is upright. These images will form on the same side of the lens.


Note: The image formed by the convex mirror and concave lens will always be virtual and erect wherever the object is placed between \[\infty\] and P. The concave mirror and convex lens will form real and inverted images with varying sizes according to the object distance (u) and they can also form virtual images
Complete answer:
* If the image is real in the case of mirrors, it will always be inverted. Also in case of mirrors if the image distance is negative hence the image is inverted. These images will form on the same side of the mirror.
* If the image is real in the case of lenses, it will always be inverted. Also in case of lenses if the image distance is positive hence the image is inverted. These images will form on the opposite side of the lens.


* If the image is virtual in the case of mirrors, it will always be upright. Also in case of mirrors if the image distance is positive hence the image is upright. These images will form on the opposite side of the mirror.
* If the image is virtual in the case of lenses, it will always be upright. Also in case of lenses if the image distance is negative hence the image is upright. These images will form on the same side of the lens.


Note: The image formed by the convex mirror and concave lens will always be virtual and erect wherever the object is placed between \[\infty\] and P. The concave mirror and convex lens will form real and inverted images with varying sizes according to the object distance (u) and they can also form virtual images
Recently Updated Pages
JEE Main Mock Test 2025-26: Electromagnetic Induction & Alternating Currents

JEE Main Mock Test 2025-26: Optics Chapter Practice Online

JEE Main 2025-26 Mock Test: Properties of Solids and Liquids

JEE Main Mock Test 2025-26: Dual Nature of Matter & Radiation

JEE Main 2025-26 Electromagnetic Waves Mock Test with Solutions

JEE Main 2025-26 Mock Test: Electronic Devices Chapter Practice

Trending doubts
JEE Main 2026: Exam Dates, Session 2 Updates, City Slip, Admit Card & Latest News

JEE Main Participating Colleges 2026 - A Complete List of Top Colleges

JEE Main Marking Scheme 2026- Paper-Wise Marks Distribution and Negative Marking Details

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Electric Field of a Uniformly Charged Ring

Derivation of Equation of Trajectory Explained for Students

Other Pages
CBSE Class 12 Physics Question Paper 2026: Download SET-wise PDF with Answer Key & Analysis

JEE Advanced 2026 - Exam Date (Released), Syllabus, Registration, Eligibility, Preparation, and More

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

JEE Advanced Weightage 2025 Chapter-Wise for Physics, Maths and Chemistry

Understanding Atomic Structure for Beginners

Understanding Electromagnetic Waves and Their Importance

