
Silver is monovalent and has an atomic mass of 108 g. Copper is divalent and has an atomic mass of 63.6 g. the same current is passed, for the same length of time through a silver coulometer and a copper coulometer. If 27.0 g of silver is deposited, then the corresponding amount of copper deposited is:
(A) 31.08 g
(B)15.908 g
(C) 7.95 g
(D) None of these
Answer
171.9k+ views
Hint: This question is based on faraday's second law of electrolysis. It can be solved by equating the ratio of the mass of both the substances deposited to the ratio of the equivalent mass of both the substances.
Complete step by step solution:
Faraday's second law states that: If we pass the same quantity of electricity through the solution containing different electrolytes that are connected in series, then the mass or weight of the substance produced at the electrodes is directly proportional to their equivalent weight.
Equivalent weight or mass is the quantity of the substance that will combine with or displace another substance.
So, according to the question, the formula will be:
$\dfrac{\text{Eq}\text{. wt}\text{. of Ag}}{\text{Eq}\text{. wt}\text{. of Cu}}\text{=}\dfrac{\text{Mass of Ag deposited}}{\text{Mass of Cu deposited}}$
Equivalent weight can be calculated by dividing the mass of the substance to its valency.
The equivalent weight of Ag = 108 g (because it is a monovalent atom)
The equivalent weight of Cu = $\dfrac{63.6}{2}=31.8\text{ g}$ (because copper is divalent atom)
The mass of silver deposited is 27.0 g.
Putting all these in the formula, we get:
$\dfrac{\text{Eq}\text{. wt}\text{. of Ag}}{\text{Eq}\text{. wt}\text{. of Cu}}\text{=}\dfrac{\text{Mass of Ag deposited}}{\text{Mass of Cu deposited}}$
$\dfrac{108}{31.8}\text{=}\dfrac{27}{x}$
$x=7.95\,\text{g}$
So, the correct answer is an option (C)- 7.95 g.
Note: The equivalent weight can also be calculated by multiplying the Faraday’s value to the ratio weight of the substance to the quantity of electricity. The value of Faraday is 96500.
$Eq.\text{ }wt.=\dfrac{W}{Q}\text{ x 96500}$.
Complete step by step solution:
Faraday's second law states that: If we pass the same quantity of electricity through the solution containing different electrolytes that are connected in series, then the mass or weight of the substance produced at the electrodes is directly proportional to their equivalent weight.
Equivalent weight or mass is the quantity of the substance that will combine with or displace another substance.
So, according to the question, the formula will be:
$\dfrac{\text{Eq}\text{. wt}\text{. of Ag}}{\text{Eq}\text{. wt}\text{. of Cu}}\text{=}\dfrac{\text{Mass of Ag deposited}}{\text{Mass of Cu deposited}}$
Equivalent weight can be calculated by dividing the mass of the substance to its valency.
The equivalent weight of Ag = 108 g (because it is a monovalent atom)
The equivalent weight of Cu = $\dfrac{63.6}{2}=31.8\text{ g}$ (because copper is divalent atom)
The mass of silver deposited is 27.0 g.
Putting all these in the formula, we get:
$\dfrac{\text{Eq}\text{. wt}\text{. of Ag}}{\text{Eq}\text{. wt}\text{. of Cu}}\text{=}\dfrac{\text{Mass of Ag deposited}}{\text{Mass of Cu deposited}}$
$\dfrac{108}{31.8}\text{=}\dfrac{27}{x}$
$x=7.95\,\text{g}$
So, the correct answer is an option (C)- 7.95 g.
Note: The equivalent weight can also be calculated by multiplying the Faraday’s value to the ratio weight of the substance to the quantity of electricity. The value of Faraday is 96500.
$Eq.\text{ }wt.=\dfrac{W}{Q}\text{ x 96500}$.
Recently Updated Pages
Sets, Relations, and Functions Mock Test 2025-26

Molarity vs Molality: Definitions, Formulas & Key Differences

Preparation of Hydrogen Gas: Methods & Uses Explained

Polymers in Chemistry: Definition, Types, Examples & Uses

P Block Elements: Definition, Groups, Trends & Properties for JEE/NEET

Order of Reaction in Chemistry: Definition, Formula & Examples

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

Displacement-Time Graph and Velocity-Time Graph for JEE

JEE Main 2025: Derivation of Equation of Trajectory in Physics

Atomic Structure - Electrons, Protons, Neutrons and Atomic Models

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Classification of Drugs

Other Pages
NCERT Solutions for Class 12 Chemistry Chapter 1 Solutions Exercise - 2025-26

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Solutions Class 12 Chemistry Chapter 1 CBSE Notes - 2025-26

NCERT Solutions for Class 12 Chemistry Chapter 6 Haloalkanes and Haloarenes - 2025-26

NCERT Solution for Class 12 Chemistry Chapter 2 Electrochemistry - 2025-26

Electrochemistry Class 12 Chemistry Chapter 2 CBSE Notes - 2025-26
