Answer
64.8k+ views
Hint:In several capacitors can be connected together to be used in a variety of applications. Multiple connections of capacitors behave as one equivalent capacitor. Capacitors are often arranged in two, simple and customary sorts of connections, referred to as series and parallel. The sum of total capacitance calculation is, ${C_P} = {C_{1 + }}{C_2} + {C_3} + ...........$
Complete step by step answer:
When the equivalent capacitance for the given parallel combination, it can be found by using formula for,
${C_{eq}} = {C_1} + {C_2} + {C_3} + .........$
And, the equivalent capacitance for series combination are often found by using formula
$\dfrac{1}{{{C_{eq}}}} = \dfrac{1}{{{C_1}}} + \dfrac{1}{{{C_2}}} + \dfrac{1}{{{C_3}}} + .........$
When option A is,
Two capacitor are in serial with the mixture combination of \[5\] capacitor in parallel
So, $\dfrac{1}{{{C_{eq}}}} = \dfrac{1}{2} + \dfrac{1}{2} + \dfrac{1}{{(2 + 2 + 2 + 2 + 2)}}$
On simplification we get,
$ \Rightarrow {C_{eq}} = \dfrac{{10}}{{11}}\mu F$
Therefore, option (A) is the correct answer.
Additional Information:
The one and only standard components in electronic circuits are called capacitors.
Also, we can observe that the complicated combination of any capacitors occurs in the practical circuits. So we can say that it is useful to possess a group of rules for some general arrangements of capacitors and it is locating the equivalent capacitance. It seems that we will always find the equivalent capacitance by repeated application of two simple rules. These rules are associated with capacitors connected serial and in parallel.
Note: Capacitors serial and Parallel a capacitor is especially used for storing electric energy like electrostatic energy. Once there's a requirement to reinforce more energy to store capacity, then an appropriate capacitor with increased capacitance is often necessary.
Complete step by step answer:
When the equivalent capacitance for the given parallel combination, it can be found by using formula for,
${C_{eq}} = {C_1} + {C_2} + {C_3} + .........$
And, the equivalent capacitance for series combination are often found by using formula
$\dfrac{1}{{{C_{eq}}}} = \dfrac{1}{{{C_1}}} + \dfrac{1}{{{C_2}}} + \dfrac{1}{{{C_3}}} + .........$
When option A is,
Two capacitor are in serial with the mixture combination of \[5\] capacitor in parallel
So, $\dfrac{1}{{{C_{eq}}}} = \dfrac{1}{2} + \dfrac{1}{2} + \dfrac{1}{{(2 + 2 + 2 + 2 + 2)}}$
On simplification we get,
$ \Rightarrow {C_{eq}} = \dfrac{{10}}{{11}}\mu F$
Therefore, option (A) is the correct answer.
Additional Information:
The one and only standard components in electronic circuits are called capacitors.
Also, we can observe that the complicated combination of any capacitors occurs in the practical circuits. So we can say that it is useful to possess a group of rules for some general arrangements of capacitors and it is locating the equivalent capacitance. It seems that we will always find the equivalent capacitance by repeated application of two simple rules. These rules are associated with capacitors connected serial and in parallel.
Note: Capacitors serial and Parallel a capacitor is especially used for storing electric energy like electrostatic energy. Once there's a requirement to reinforce more energy to store capacity, then an appropriate capacitor with increased capacitance is often necessary.
Recently Updated Pages
Write a composition in approximately 450 500 words class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Arrange the sentences P Q R between S1 and S5 such class 10 english JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What is the common property of the oxides CONO and class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
What happens when dilute hydrochloric acid is added class 10 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
If four points A63B 35C4 2 and Dx3x are given in such class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
The area of square inscribed in a circle of diameter class 10 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Other Pages
A boat takes 2 hours to go 8 km and come back to a class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Electric field due to uniformly charged sphere class 12 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
In the ground state an element has 13 electrons in class 11 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
According to classical free electron theory A There class 11 physics JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Differentiate between homogeneous and heterogeneous class 12 chemistry JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Excluding stoppages the speed of a bus is 54 kmph and class 11 maths JEE_Main
![arrow-right](/cdn/images/seo-templates/arrow-right.png)