Select the correct order (for hydrolysis at room temperature).
This question has multiple correct options
(A) ${\text{SiC}}{{\text{l}}_4}{\text{ }} < {\text{ CC}}{{\text{l}}_4}$
(B) ${\text{CC}}{{\text{l}}_4}{\text{ }} < {\text{ SiC}}{{\text{l}}_4}$
(C) ${\text{NC}}{{\text{l}}_3}{\text{ }} > {\text{ N}}{{\text{F}}_3}$
(D) ${\text{NC}}{{\text{l}}_3}{\text{ }} < {\text{ N}}{{\text{F}}_3}$
Answer
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Hint: Depending on the strength of bond formed between an element and its halide, their reactivity towards hydrolysis is determined. Weaker the bond more is the reactivity towards hydrolysis.
Complete step by step answer:
Si and C are the elements of group 14 and are called the Carbon family. They form tetra-halides of the form ${\text{M}}{{\text{X}}_4}$ in which the central atom is in ${\text{s}}{{\text{p}}^3}$ hybridization. The bond between Si-Cl is weaker than C-Cl bond and hence at room temperature, ${\text{SiC}}{{\text{l}}_4}$ is easily hydrolysed than ${\text{CC}}{{\text{l}}_4}$. So, option B is correct.
However, in halogens, N-Cl bond is much weaker than N-F bond and hence, at room temperature nitrogen trichloride is easily hydrolysed than nitrogen trifluoride. So, option C is also correct.
Additional information:
Nitrogen belongs to group 15 and forms a wide range of halides of ${\text{E}}{{\text{X}}_3}$type, ${\text{E}}{{\text{X}}_5}$type and ${\text{E}}{{\text{X}}_2}$ type and of all the trihalides of nitrogen, only ${\text{N}}{{\text{F}}_3}$ is found to be stable.
Halogens have seven valence electrons because halogens have one electron missing, they form negative ions and hence have a very high value of electronegativity. The electronegativity decreases down the group due to the decrease in effective nuclear charge. Thus, fluorine is the most electronegative element.
Note: In the first two options we have to see the strength of bond between chlorine and two elements of the carbon family whereas in next two options we have to see the differences in the strength of bond between nitrogen and two different halogens. Hence, there will be two correct options.
Complete step by step answer:
Si and C are the elements of group 14 and are called the Carbon family. They form tetra-halides of the form ${\text{M}}{{\text{X}}_4}$ in which the central atom is in ${\text{s}}{{\text{p}}^3}$ hybridization. The bond between Si-Cl is weaker than C-Cl bond and hence at room temperature, ${\text{SiC}}{{\text{l}}_4}$ is easily hydrolysed than ${\text{CC}}{{\text{l}}_4}$. So, option B is correct.
However, in halogens, N-Cl bond is much weaker than N-F bond and hence, at room temperature nitrogen trichloride is easily hydrolysed than nitrogen trifluoride. So, option C is also correct.
Additional information:
Nitrogen belongs to group 15 and forms a wide range of halides of ${\text{E}}{{\text{X}}_3}$type, ${\text{E}}{{\text{X}}_5}$type and ${\text{E}}{{\text{X}}_2}$ type and of all the trihalides of nitrogen, only ${\text{N}}{{\text{F}}_3}$ is found to be stable.
Halogens have seven valence electrons because halogens have one electron missing, they form negative ions and hence have a very high value of electronegativity. The electronegativity decreases down the group due to the decrease in effective nuclear charge. Thus, fluorine is the most electronegative element.
Note: In the first two options we have to see the strength of bond between chlorine and two elements of the carbon family whereas in next two options we have to see the differences in the strength of bond between nitrogen and two different halogens. Hence, there will be two correct options.
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