
Rutherford's scattering experiment is related to the size of the:
(A) Nucleus
(B) Atom
(C) Electron
(D) Neutron
Answer
136.2k+ views
Hint: Rutherford was originally interested in finding how the electrons are arranged inside an atom. Therefore, he performed an experiment for this, commonly known as alpha particle scattering. In his experiment, he made fast moving alpha particles to fall on a very thin gold foil.
Complete step by step solution:
Model for the structure of an atom had been first proposed by J.J. Thomson, commonly known as watermelon or plum pudding model. Later, Ernest Rutherford's model was finally accepted as the correct nuclear model.
Requirements of Rutherford's scattering experiment:
(i) He selected gold foil because it is very ductile, the thickness of the foil used was about 1000 atoms.
(ii) α-particles are doubly-charged helium ions. They have a mass of 4µ, so they can move very fast with a considerable amount of energy.
Rutherford expected that all the alpha particles would be deflected by the particles present in the gold atoms, since the alpha particles were much heavier than the protons. But the experiment gave completely different results.
Observations of Rutherford's scattering experiment:
(i) Most of the fast-moving alpha particles went straight through the gold foil without any deflection.
(ii) Some of the alpha particles were deflected by small angles.
(iii) Surprisingly, one out of every 12,000 alpha particles were completely reflected back.
From these observations, he concluded that:
(i) Most of the space inside the atom is vacant as most of the alpha particles went straight through the gold foil without any deflection.
(ii) A few particles showed little deflection from their trajectory, indicating that the positive charge of the atom occupies very small space.
(iii) And a very small number of alpha particles were deflected by very large angles or completely deflected back, indicating that all the positive charge and mass of the gold atom occupied a very small volume within the atom.
From the observation, Rutherford calculated that the radius of the nucleus, which was about \[{{10}^{5}}\] times less than the radius of the atom.
So, the correct option is (a).
Note: Rutherford's model could not explain the stability of an atom. As he said that electrons revolving around the nucleus continuously should lose energy and will be pulled towards the nucleus, resulting in colliding with it.
Complete step by step solution:
Model for the structure of an atom had been first proposed by J.J. Thomson, commonly known as watermelon or plum pudding model. Later, Ernest Rutherford's model was finally accepted as the correct nuclear model.
Requirements of Rutherford's scattering experiment:
(i) He selected gold foil because it is very ductile, the thickness of the foil used was about 1000 atoms.
(ii) α-particles are doubly-charged helium ions. They have a mass of 4µ, so they can move very fast with a considerable amount of energy.
Rutherford expected that all the alpha particles would be deflected by the particles present in the gold atoms, since the alpha particles were much heavier than the protons. But the experiment gave completely different results.
Observations of Rutherford's scattering experiment:
(i) Most of the fast-moving alpha particles went straight through the gold foil without any deflection.
(ii) Some of the alpha particles were deflected by small angles.
(iii) Surprisingly, one out of every 12,000 alpha particles were completely reflected back.
From these observations, he concluded that:
(i) Most of the space inside the atom is vacant as most of the alpha particles went straight through the gold foil without any deflection.
(ii) A few particles showed little deflection from their trajectory, indicating that the positive charge of the atom occupies very small space.
(iii) And a very small number of alpha particles were deflected by very large angles or completely deflected back, indicating that all the positive charge and mass of the gold atom occupied a very small volume within the atom.
From the observation, Rutherford calculated that the radius of the nucleus, which was about \[{{10}^{5}}\] times less than the radius of the atom.
So, the correct option is (a).
Note: Rutherford's model could not explain the stability of an atom. As he said that electrons revolving around the nucleus continuously should lose energy and will be pulled towards the nucleus, resulting in colliding with it.
Recently Updated Pages
JEE Main 2021 July 25 Shift 2 Question Paper with Answer Key

JEE Main 2021 July 25 Shift 1 Question Paper with Answer Key

JEE Main 2021 July 20 Shift 2 Question Paper with Answer Key

JEE Main 2021 July 22 Shift 2 Question Paper with Answer Key

How to find Oxidation Number - Important Concepts for JEE

Half-Life of Order Reactions - Important Concepts and Tips for JEE

Trending doubts
JEE Main 2025 Session 2: Application Form (Out), Exam Dates (Released), Eligibility, & More

Electromagnetic radiation with maximum wavelength is class 11 chemistry JEE_Main

JEE Main 2025: Derivation of Equation of Trajectory in Physics

The correct order of electron affinity is A F Cl Br class 11 chemistry JEE_Main

Learn About Angle Of Deviation In Prism: JEE Main Physics 2025

Degree of Dissociation and Its Formula With Solved Example for JEE

Other Pages
NCERT Solutions for Class 11 Chemistry Chapter 9 Hydrocarbons

NCERT Solutions for Class 11 Chemistry Chapter 7 Redox Reaction

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

NCERT Solutions for Class 11 Chemistry Chapter 5 Thermodynamics

Hydrocarbons Class 11 Notes: CBSE Chemistry Chapter 9

NCERT Solutions for Class 11 Chemistry In Hindi Chapter 1 Some Basic Concepts of Chemistry
