
Rutherford's scattering experiment is related to the size of the:
(A) Nucleus
(B) Atom
(C) Electron
(D) Neutron
Answer
219k+ views
Hint: Rutherford was originally interested in finding how the electrons are arranged inside an atom. Therefore, he performed an experiment for this, commonly known as alpha particle scattering. In his experiment, he made fast moving alpha particles to fall on a very thin gold foil.
Complete step by step solution:
Model for the structure of an atom had been first proposed by J.J. Thomson, commonly known as watermelon or plum pudding model. Later, Ernest Rutherford's model was finally accepted as the correct nuclear model.
Requirements of Rutherford's scattering experiment:
(i) He selected gold foil because it is very ductile, the thickness of the foil used was about 1000 atoms.
(ii) α-particles are doubly-charged helium ions. They have a mass of 4µ, so they can move very fast with a considerable amount of energy.
Rutherford expected that all the alpha particles would be deflected by the particles present in the gold atoms, since the alpha particles were much heavier than the protons. But the experiment gave completely different results.
Observations of Rutherford's scattering experiment:
(i) Most of the fast-moving alpha particles went straight through the gold foil without any deflection.
(ii) Some of the alpha particles were deflected by small angles.
(iii) Surprisingly, one out of every 12,000 alpha particles were completely reflected back.
From these observations, he concluded that:
(i) Most of the space inside the atom is vacant as most of the alpha particles went straight through the gold foil without any deflection.
(ii) A few particles showed little deflection from their trajectory, indicating that the positive charge of the atom occupies very small space.
(iii) And a very small number of alpha particles were deflected by very large angles or completely deflected back, indicating that all the positive charge and mass of the gold atom occupied a very small volume within the atom.
From the observation, Rutherford calculated that the radius of the nucleus, which was about \[{{10}^{5}}\] times less than the radius of the atom.
So, the correct option is (a).
Note: Rutherford's model could not explain the stability of an atom. As he said that electrons revolving around the nucleus continuously should lose energy and will be pulled towards the nucleus, resulting in colliding with it.
Complete step by step solution:
Model for the structure of an atom had been first proposed by J.J. Thomson, commonly known as watermelon or plum pudding model. Later, Ernest Rutherford's model was finally accepted as the correct nuclear model.
Requirements of Rutherford's scattering experiment:
(i) He selected gold foil because it is very ductile, the thickness of the foil used was about 1000 atoms.
(ii) α-particles are doubly-charged helium ions. They have a mass of 4µ, so they can move very fast with a considerable amount of energy.
Rutherford expected that all the alpha particles would be deflected by the particles present in the gold atoms, since the alpha particles were much heavier than the protons. But the experiment gave completely different results.
Observations of Rutherford's scattering experiment:
(i) Most of the fast-moving alpha particles went straight through the gold foil without any deflection.
(ii) Some of the alpha particles were deflected by small angles.
(iii) Surprisingly, one out of every 12,000 alpha particles were completely reflected back.
From these observations, he concluded that:
(i) Most of the space inside the atom is vacant as most of the alpha particles went straight through the gold foil without any deflection.
(ii) A few particles showed little deflection from their trajectory, indicating that the positive charge of the atom occupies very small space.
(iii) And a very small number of alpha particles were deflected by very large angles or completely deflected back, indicating that all the positive charge and mass of the gold atom occupied a very small volume within the atom.
From the observation, Rutherford calculated that the radius of the nucleus, which was about \[{{10}^{5}}\] times less than the radius of the atom.
So, the correct option is (a).
Note: Rutherford's model could not explain the stability of an atom. As he said that electrons revolving around the nucleus continuously should lose energy and will be pulled towards the nucleus, resulting in colliding with it.
Recently Updated Pages
The hybridization and shape of NH2 ion are a sp2 and class 11 chemistry JEE_Main

What is the pH of 001 M solution of HCl a 1 b 10 c class 11 chemistry JEE_Main

Aromatization of nhexane gives A Benzene B Toluene class 11 chemistry JEE_Main

Show how you will synthesise i 1Phenylethanol from class 11 chemistry JEE_Main

The enolic form of acetone contains a 10sigma bonds class 11 chemistry JEE_Main

Which of the following Compounds does not exhibit tautomerism class 11 chemistry JEE_Main

Trending doubts
JEE Main 2026: Application Form Open, Exam Dates, Syllabus, Eligibility & Question Papers

Derivation of Equation of Trajectory Explained for Students

Hybridisation in Chemistry – Concept, Types & Applications

Understanding the Angle of Deviation in a Prism

Understanding Collisions: Types and Examples for Students

Understanding Atomic Structure for Beginners

Other Pages
NCERT Solutions For Class 11 Chemistry Chapter 7 Redox Reaction

JEE Advanced Marks vs Ranks 2025: Understanding Category-wise Qualifying Marks and Previous Year Cut-offs

Thermodynamics Class 11 Chemistry Chapter 5 CBSE Notes - 2025-26

NCERT Solutions ForClass 11 Chemistry Chapter Chapter 5 Thermodynamics

Equilibrium Class 11 Chemistry Chapter 6 CBSE Notes - 2025-26

How to Convert a Galvanometer into an Ammeter or Voltmeter

